使用MySQL,我可以执行以下操作:

SELECT hobbies FROM peoples_hobbies WHERE person_id = 5;

我的输出:

shopping
fishing
coding

但我只想要1行1列:

预期输出:

shopping, fishing, coding

原因是我从多个表中选择了多个值,在所有的连接之后,我得到了比我想要的多得多的行。

我在MySQL Doc上查找了一个函数,它看起来不像CONCAT或CONCAT_WS函数接受结果集。

这里有人知道怎么做吗?


当前回答

这里,我的意图是在不使用group_concat()函数的情况下应用字符串连接:

Set @concatHobbies = '';
SELECT TRIM(LEADING ', ' FROM T.hobbies ) FROM 
(
   select 
   Id, @concatHobbies := concat_ws(', ',@concatHobbies,hobbies) as hobbies
   from peoples_hobbies
)T
Order by Id DESC
LIMIT 1

Here

   select 
   Id, @concatHobbies := concat_ws(', ',@concatHobbies,hobbies) as hobbies
   from peoples_hobbies

将返回

  Id    hobbies
  1     , shopping
  2     , shopping, fishing
  3     , shopping, fishing, coding

现在我们的预期结果是第三。所以我用

  Order by Id DESC 
  LIMIT 1
  

然后我也将第一个“,”从字符串中删除

 TRIM(LEADING ', ' FROM T.hobbies )

其他回答

通过设置GROUP_CONCAT_max_len参数,可以更改GROUP_CONCAT值的最大长度。

请参阅MySQL文档中的详细信息。

试试看:

DECLARE @Hobbies NVARCHAR(200) = ' '

SELECT @Hobbies = @Hobbies + hobbies + ',' FROM peoples_hobbies WHERE person_id = 5;

TL;博士;

set @sql='';
set @result='';
set @separator=' union \r\n';
SELECT 
@sql:=concat('select ''',INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME  ,''' as col_name,',
INFORMATION_SCHEMA.COLUMNS.CHARACTER_MAXIMUM_LENGTH ,' as def_len ,' ,
'MAX(CHAR_LENGTH(',INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME , '))as  max_char_len',
' FROM ',
INFORMATION_SCHEMA.COLUMNS.TABLE_NAME
) as sql_piece, if(@result:=if(@result='',@sql,concat(@result,@separator,@sql)),'','') as dummy
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE 
INFORMATION_SCHEMA.COLUMNS.DATA_TYPE like '%char%'
and INFORMATION_SCHEMA.COLUMNS.TABLE_SCHEMA='xxx' 
and INFORMATION_SCHEMA.COLUMNS.TABLE_NAME='yyy';
select @result;

现在已经很晚了,但对于那些正在搜索“使用透视表将多个MySQL行连接到一个字段中”的人来说会很有帮助:)

查询:

SELECT pm.id, pm.name, GROUP_CONCAT(c.name) as channel_names
FROM payment_methods pm
LEFT JOIN payment_methods_channels_pivot pmcp ON pmcp.payment_method_id = pm.id
LEFT JOIN channels c ON c.id = pmcp.channel_id
GROUP BY pm.id

桌子

payment_methods 
  id  | name
  1   | PayPal

channels
  id  | name
  1   | Google
  2   | Faceook

payment_methods_channels_pivot
   payment_method_id | channel_id
   1                 |  1
   1                 |  2

输出:

使用MySQL(5.6.13)会话变量和赋值运算符,如下所示

SELECT @logmsg := CONCAT_ws(',',@logmsg,items) FROM temp_SplitFields a;

然后你可以得到

test1,test11

在我的例子中,我有一行ID,必须将其转换为char,否则,结果被编码为二进制格式:

SELECT CAST(GROUP_CONCAT(field SEPARATOR ',') AS CHAR) FROM table