我如何让一个函数等待,直到所有的jQuery Ajax请求在另一个函数内完成?

简而言之,在执行下一个Ajax请求之前,我需要等待所有Ajax请求都完成。但如何?


当前回答

在@BBonifield回答的基础上,我写了一个实用函数,这样信号量逻辑就不会分布在所有ajax调用中。

untilAjax是一个实用函数,它在所有ajaxCalls完成后调用回调函数。

ajaxObjs是一个ajax设置对象的数组[http://api.jquery.com/jQuery.ajax/]。

Fn是回调函数

function untilAjax(ajaxObjs, fn) {
  if (!ajaxObjs || !fn) {
    return;
  }
  var ajaxCount = ajaxObjs.length,
    succ = null;

  for (var i = 0; i < ajaxObjs.length; i++) { //append logic to invoke callback function once all the ajax calls are completed, in success handler.
    succ = ajaxObjs[i]['success'];
    ajaxObjs[i]['success'] = function(data) { //modified success handler
      if (succ) {
        succ(data);
      }
      ajaxCount--;
      if (ajaxCount == 0) {
        fn(); //modify statement suitably if you want 'this' keyword to refer to another object
      }
    };
    $.ajax(ajaxObjs[i]); //make ajax call
    succ = null;
  };

示例:doSomething函数使用untilAjax。

function doSomething() {
  // variable declarations
  untilAjax([{
    url: 'url2',
    dataType: 'json',
    success: function(data) {
      //do something with success data
    }
  }, {
    url: 'url1',
    dataType: 'json',
    success: function(data) {
      //do something with success data
    }
  }, {
    url: 'url2',
    dataType: 'json',
    success: function(response) {
      //do something with success data
    }
  }], function() {
    // logic after all the calls are completed.
  });
}

其他回答

这对我很有用 非常简单

return $.ajax({
  type: 'POST',
  url: urlBaseUrl
  data: {someData:someData},
  dataType: "json",
  success: function(resultData) { 
  }
});

当所有ajax加载完成时,我使用大小检查

function get_ajax(link, data, callback) { $.ajax({ url: link, type: "GET", data: data, dataType: "json", success: function (data, status, jqXHR) { callback(jqXHR.status, data) }, error: function (jqXHR, status, err) { callback(jqXHR.status, jqXHR); }, complete: function (jqXHR, status) { } }) } function run_list_ajax(callback){ var size=0; var max= 10; for (let index = 0; index < max; index++) { var link = 'http://api.jquery.com/ajaxStop/'; var data={i:index} get_ajax(link,data,function(status, data){ console.log(index) if(size>max-2){ callback('done') } size++ }) } } run_list_ajax(function(info){ console.log(info) }) <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js"></script>

如果你需要简单的东西;Once and done回调

        //multiple ajax calls above
        var callback = function () {
            if ($.active !== 0) {
                setTimeout(callback, '500');
                return;
            }
            //whatever you need to do here
            //...
        };
        callback();

如果从头开始,我强烈建议使用$.when()。

尽管这个问题有超过一百万个答案,但我仍然没有找到任何对我的情况有用的答案。假设您必须处理现有的代码库,已经进行了一些ajax调用,并且不想引入承诺的复杂性和/或重做整个事情。

我们可以很容易地利用jQuery的.data, .on和.trigger函数,这些函数一直是jQuery的一部分。

Codepen

我的解决方案的优点是:

显然回调依赖于什么 函数triggerNowOrOnLoaded并不关心数据是否已经加载或我们仍在等待它 将其插入现有代码非常容易

$(function() { // wait for posts to be loaded triggerNowOrOnLoaded("posts", function() { var $body = $("body"); var posts = $body.data("posts"); $body.append("<div>Posts: " + posts.length + "</div>"); }); // some ajax requests $.getJSON("https://jsonplaceholder.typicode.com/posts", function(data) { $("body").data("posts", data).trigger("posts"); }); // doesn't matter if the `triggerNowOrOnLoaded` is called after or before the actual requests $.getJSON("https://jsonplaceholder.typicode.com/users", function(data) { $("body").data("users", data).trigger("users"); }); // wait for both types triggerNowOrOnLoaded(["posts", "users"], function() { var $body = $("body"); var posts = $body.data("posts"); var users = $body.data("users"); $body.append("<div>Posts: " + posts.length + " and Users: " + users.length + "</div>"); }); // works even if everything has already loaded! setTimeout(function() { // triggers immediately since users have been already loaded triggerNowOrOnLoaded("users", function() { var $body = $("body"); var users = $body.data("users"); $body.append("<div>Delayed Users: " + users.length + "</div>"); }); }, 2000); // 2 seconds }); // helper function function triggerNowOrOnLoaded(types, callback) { types = $.isArray(types) ? types : [types]; var $body = $("body"); var waitForTypes = []; $.each(types, function(i, type) { if (typeof $body.data(type) === 'undefined') { waitForTypes.push(type); } }); var isDataReady = waitForTypes.length === 0; if (isDataReady) { callback(); return; } // wait for the last type and run this function again for the rest of the types var waitFor = waitForTypes.pop(); $body.on(waitFor, function() { // remove event handler - we only want the stuff triggered once $body.off(waitFor); triggerNowOrOnLoaded(waitForTypes, callback); }); } <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <body>Hi!</body>

一个小小的变通方法是这样的:

// Define how many Ajax calls must be done
var ajaxCalls = 3;
var counter = 0;
var ajaxCallComplete = function() {
    counter++;
    if( counter >= ajaxCalls ) {
            // When all ajax calls has been done
        // Do something like hide waiting images, or any else function call
        $('*').css('cursor', 'auto');
    }
};

var loadPersons = function() {
        // Show waiting image, or something else
    $('*').css('cursor', 'wait');

    var url = global.ctx + '/loadPersons';
    $.getJSON(url, function(data) {
            // Fun things
    })
    .complete(function() { **ajaxCallComplete();** });
};

var loadCountries = function() {
    // Do things
    var url = global.ctx + '/loadCountries';
    $.getJSON(url, function(data) {
            // Travels
    })
    .complete(function() { **ajaxCallComplete();** });
};

var loadCities = function() {
    // Do things
    var url = global.ctx + '/loadCities';
    $.getJSON(url, function(data) {
            // Travels
    })
    .complete(function() { **ajaxCallComplete();** });
};

$(document).ready(function(){
    loadPersons();
    loadCountries();
    loadCities();
});

希望能有用…