如果可以选择使用getline(不要忽略其安全性问题)，如果希望使用大括号指针，则可以避免使用字符串函数，因为getline返回的是字符数。如下图所示

#include <stdio.h>
#include <stdlib.h>
int main()
{
    char *fname, *lname;
    size_t size = 32, nchar; // Max size of strings and number of characters read
    fname = malloc(size * sizeof *fname);
    lname = malloc(size * sizeof *lname);
    if (NULL == fname || NULL == lname)
    {
        printf("Error in memory allocation.");
        exit(1);
    }
    printf("Enter first name ");
    nchar = getline(&fname, &size, stdin);
    if (nchar == -1) // getline return -1 on failure to read a line.
    {
        printf("Line couldn't be read..");
        // This if block could be repeated for next getline too
        exit(1);
    }
    printf("Number of characters read :%zu\n", nchar);
    fname[nchar - 1] = '\0';
    printf("Enter last name ");
    nchar = getline(&lname, &size, stdin);
    printf("Number of characters read :%zu\n", nchar);
    lname[nchar - 1] = '\0';
    printf("Name entered %s %s\n", fname, lname);
    return 0;
}

注意:getline的[安全问题]不应该被忽视。

size_t ln = strlen(name) - 1;
if (*name && name[ln] == '\n') 
    name[ln] = '\0';

下面是一个从fgets()保存的字符串中删除潜在'\n'的快速方法。 它使用strlen()，带有2个测试。

char buffer[100];
if (fgets(buffer, sizeof buffer, stdin) != NULL) {

  size_t len = strlen(buffer);
  if (len > 0 && buffer[len-1] == '\n') {
    buffer[--len] = '\0';
  }

现在根据需要使用buffer和len。

该方法的附带好处是为后续代码提供len值。它可以比strchr(Name， '\n')更快。参考YMMV，但两种方法都有效。

在某些情况下，原始fgets()将不包含在"\n"中: A)行太长，不适合buffer，所以只有'\n'前面的char被保存在buffer中。未读字符保留在流中。 B)文件的最后一行没有以“\n”结尾。

如果输入在某个地方嵌入了空字符'\0'，strlen()报告的长度将不包括'\n'位置。

其他一些回答的问题:

strtok(buffer, "\n"); fails to remove the '\n' when buffer is "\n". From this answer - amended after this answer to warn of this limitation. The following fails on rare occasions when the first char read by fgets() is '\0'. This happens when input begins with an embedded '\0'. Then buffer[len -1] becomes buffer[SIZE_MAX] accessing memory certainly outside the legitimate range of buffer. Something a hacker may try or found in foolishly reading UTF16 text files. This was the state of an answer when this answer was written. Later a non-OP edited it to include code like this answer's check for "". size_t len = strlen(buffer); if (buffer[len - 1] == '\n') { // FAILS when len == 0 buffer[len -1] = '\0'; } sprintf(buffer,"%s",buffer); is undefined behavior: Ref. Further, it does not save any leading, separating or trailing whitespace. Now deleted. [Edit due to good later answer] There are no problems with the 1 liner buffer[strcspn(buffer, "\n")] = 0; other than performance as compared to the strlen() approach. Performance in trimming is usually not an issue given code is doing I/O - a black hole of CPU time. Should following code need the string's length or is highly performance conscious, use this strlen() approach. Else the strcspn() is a fine alternative.

下面的函数是我在Github上维护的字符串处理库的一部分。它从字符串中删除不需要的字符，这正是你想要的

int zstring_search_chr(const char *token,char s){
    if (!token || s=='\0')
        return 0;

    for (;*token; token++)
        if (*token == s)
            return 1;

    return 0;
}

char *zstring_remove_chr(char *str,const char *bad) {
    char *src = str , *dst = str;
    while(*src)
        if(zstring_search_chr(bad,*src))
            src++;
        else
            *dst++ = *src++;  /* assign first, then incement */

    *dst='\0';
        return str;
}

一个示例用法是

Example Usage
      char s[]="this is a trial string to test the function.";
      char const *d=" .";
      printf("%s\n",zstring_remove_chr(s,d));

  Example Output
      thisisatrialstringtotestthefunction

你可能想要检查其他可用的功能，甚至为项目贡献:) https://github.com/fnoyanisi/zString

优雅的方式:

Name[strcspn(Name, "\n")] = 0;

略显丑陋的方式:

char *pos;
if ((pos=strchr(Name, '\n')) != NULL)
    *pos = '\0';
else
    /* input too long for buffer, flag error */

有点奇怪的方式:

strtok(Name, "\n");

注意，如果用户输入一个空字符串(即只按Enter)， strtok函数就不能正常工作。它保留\n字符。

当然，还有其他原因。

如果每一行都有'\n'，则直接从fgets输出中删除'\n'

line[strlen(line) - 1] = '\0';

否则:

void remove_newline_ch(char *line)
{
    int new_line = strlen(line) -1;
    if (line[new_line] == '\n')
        line[new_line] = '\0';
}