我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/
<!DOCTYPE html>
<html>
<head>
<title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">
<h3>Parse URL using AngularJS</h3>
url: <input type="text" ng-model="url" value="" style="width:780px;">
<ul>
<li>href = {{parser.href}}</li>
<li>protocol = {{parser.protocol}}</li>
<li>host = {{parser.host}}</li>
<li>hostname = {{parser.hostname}}</li>
<li>port = {{parser.port}}</li>
<li>pathname = {{parser.pathname}}</li>
<li>hash = {{parser.hash}}</li>
<li>search = {{parser.search}}</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>
<script>
function AppCtrl($scope) {
$scope.$watch('url', function() {
$scope.parser.href = $scope.url;
});
$scope.init = function() {
$scope.parser = document.createElement('a');
$scope.url = window.location;
}
}
</script>
</body>
</html>
其他回答
var getLocation = function(href) {
var l = document.createElement("a");
l.href = href;
return l;
};
var l = getLocation("http://example.com/path");
console.debug(l.hostname)
>> "example.com"
console.debug(l.pathname)
>> "/path"
对于那些正在寻找在IE, Firefox和Chrome中工作的现代解决方案的人:
这些使用超链接元素的解决方案都不会在chrome中起同样的作用。如果你传递一个无效(或空白)的url给chrome，它总是会返回脚本被调用的主机。所以在IE中你会得到空白，而在Chrome中你会得到localhost(或其他什么)。
如果你试图看着推荐人，这是骗人的。你需要确保你返回的主机在原始url中，以处理这个问题:
function getHostNameFromUrl(url) {
// <summary>Parses the domain/host from a given url.</summary>
var a = document.createElement("a");
a.href = url;
// Handle chrome which will default to domain where script is called from if invalid
return url.indexOf(a.hostname) != -1 ? a.hostname : '';
}
这不会解析查询和散列，但除此之外它工作得很好。
const getURIParts = (url) => { const matches = url.match(/^(\w+?:\/\/)?([\w-\.]+(?=\/?))?:?(\d*)?([^:]*)/) return { scheme: matches ? matches[1] : undefined, host: matches ? matches[2] : '', port: matches ? matches[3] : undefined, pathname: matches ? matches[4] : '' } } console.log(getURIParts("")) console.log(getURIParts("http://localhost/bla")) console.log(getURIParts("https://api.spotify.com/")) console.log(getURIParts("https://api.spotify.com")) console.log(getURIParts("wss://wss.slack.com/link/?ticket=1234-5678")) console.log(getURIParts("localhost")) console.log(getURIParts("localhost/bla")) console.log(getURIParts("localhost/")) console.log(getURIParts("api.spotify.com/bla/two")) console.log(getURIParts("api.spotify.com:8000/bla/two")) console.log(getURIParts("https://api.spotify.com:8800/")) console.log(getURIParts("/mp3-preview/f504e6b8e037771318656394f532dede4f9bcaea"))
别再白费力气了。使用https://github.com/medialize/URI.js/
var uri = new URI("http://example.org:80/foo/hello.html");
// get host
uri.host(); // returns string "example.org:80"
// set host
uri.host("example.org:80");
js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:
var some_uri = new URI("http://www.example.com/foo/bar");
alert(some_uri.authority); // www.example.com
alert(some_uri); // http://www.example.com/foo/bar
var blah = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full); // http://www.example.com/foo/blah
