我如何在javascript中解析URL到主机名和路径?

我想拿一根绳子

var a = "http://example.com/aa/bb/"

然后把它加工成一个物体

a.hostname == "example.com"

and

a.pathname == "/aa/bb"

当前回答

AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/

<!DOCTYPE html>
<html>
<head>
    <title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">

<h3>Parse URL using AngularJS</h3>

url: <input type="text" ng-model="url" value="" style="width:780px;">

<ul>
    <li>href = {{parser.href}}</li>
    <li>protocol = {{parser.protocol}}</li>
    <li>host = {{parser.host}}</li>
    <li>hostname = {{parser.hostname}}</li>
    <li>port = {{parser.port}}</li>
    <li>pathname = {{parser.pathname}}</li>
    <li>hash = {{parser.hash}}</li>
    <li>search = {{parser.search}}</li>
</ul>

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>

<script>
function AppCtrl($scope) {

    $scope.$watch('url', function() {
        $scope.parser.href = $scope.url;
    });

    $scope.init = function() {
        $scope.parser = document.createElement('a');
        $scope.url = window.location;
    }

}
</script>

</body>
</html>

2013-04-15 07:02:29

其他回答

AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/

<!DOCTYPE html>
<html>
<head>
    <title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">

<h3>Parse URL using AngularJS</h3>

url: <input type="text" ng-model="url" value="" style="width:780px;">

<ul>
    <li>href = {{parser.href}}</li>
    <li>protocol = {{parser.protocol}}</li>
    <li>host = {{parser.host}}</li>
    <li>hostname = {{parser.hostname}}</li>
    <li>port = {{parser.port}}</li>
    <li>pathname = {{parser.pathname}}</li>
    <li>hash = {{parser.hash}}</li>
    <li>search = {{parser.search}}</li>
</ul>

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>

<script>
function AppCtrl($scope) {

    $scope.$watch('url', function() {
        $scope.parser.href = $scope.url;
    });

    $scope.init = function() {
        $scope.parser = document.createElement('a');
        $scope.url = window.location;
    }

}
</script>

</body>
</html>

2013-04-15 07:02:29

现代方式:

new URL("http://example.com/aa/bb/")

返回一个具有主机名和路径名等属性的对象。

第一个参数是相对或绝对URL;如果它是相对的，那么你需要指定第二个参数(基本URL)。例如，对于相对于当前页面的URL:

new URL("/aa/bb/", location)

除了浏览器，这个API在Node.js中也可以通过require('url'). url从v7开始使用。

2014-06-03 02:18:08

在acdcjunior解决方案上扩展了“searchParam”功能模仿URL对象，增加了“searchParam”来解析查询字符串适用于IE 6、7、8、9、10、11

用法- (JSFiddle Link)

// USAGE:
var myUrl = new ParsedUrl("http://www.example.com/path?var1=123&var2=abc#fragment");
console.log(myUrl);
console.log(myUrl.searchParam('var1'));
console.log(myUrl.searchParam('var2'));

输出- (JSFiddle链接)

{
  hash: "#fragment",
  host: "www.example.com:8080",
  hostname: "www.example.com",
  href: "http://www.example.com:8080/path?var1=123&amp;var2=abc#fragment",
  pathname: "/path",
  port: "80",
  protocol: "http:",
  search: "?var1=123&amp;var2=abc"
}

"123"
"abc"

CODE - (JSFiddle Link)

function ParsedUrl(url) {
    var parser = document.createElement("a");
    parser.href = url;
    
    // IE 8 and 9 dont load the attributes "protocol" and "host" in case the source URL
    // is just a pathname, that is, "/example" and not "http://www.example.com/example".
    parser.href = parser.href;
    
    // IE 7 and 6 wont load "protocol" and "host" even with the above workaround,
    // so we take the protocol/host from window.location and place them manually
    if (parser.host === "") {
        var newProtocolAndHost = window.location.protocol + "//" + window.location.host;
        if (url.charAt(1) === "/") {
            parser.href = newProtocolAndHost + url;
        } else {
            // the regex gets everything up to the last "/"
            // /path/takesEverythingUpToAndIncludingTheLastForwardSlash/thisIsIgnored
            // "/" is inserted before because IE takes it of from pathname
            var currentFolder = ("/"+parser.pathname).match(/.*\//)[0];
            parser.href = newProtocolAndHost + currentFolder + url;
        }
    }
    
    // copies all the properties to this object
    var properties = ['host', 'hostname', 'hash', 'href', 'port', 'protocol', 'search'];
    for (var i = 0, n = properties.length; i < n; i++) {
      this[properties[i]] = parser[properties[i]];
    }
    
    // pathname is special because IE takes the "/" of the starting of pathname
    this.pathname = (parser.pathname.charAt(0) !== "/" ? "/" : "") + parser.pathname;
  
  //search Params
  this.searchParam =  function(variable) {
    var query = (this.search.indexOf('?') === 0) ? this.search.substr(1) : this.search;
    var vars = query.split('&');
    for (var i = 0; i < vars.length; i++) {
        var pair = vars[i].split('=');
        if (decodeURIComponent(pair[0]) == variable) {
            return decodeURIComponent(pair[1]);
        }
    }
    console.log('Query variable %s not found', variable);
    return '';
    };
}

2020-10-02 01:51:05

以下是我从https://gist.github.com/1847816复制的一个版本，但经过重写，以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长，因此将有限数量的值复制到结果将有助于简化结果。

/**
 * See: https://gist.github.com/1847816
 * Parse a URI, returning an object similar to Location
 * Usage: var uri = parseUri("hello?search#hash")
 */
function parseUri(url) {

  var result = {};

  var anchor = document.createElement('a');
  anchor.href = url;

  var keys = 'protocol hostname host pathname port search hash href'.split(' ');
  for (var keyIndex in keys) {
    var currentKey = keys[keyIndex]; 
    result[currentKey] = anchor[currentKey];
  }

  result.toString = function() { return anchor.href; };
  result.requestUri = result.pathname + result.search;  
  return result;

}

2012-03-19 20:16:52

当然，在>2016年，正确的答案是使用URL API 对于页面URL window.location And for <a href="…""> html lanchorelement API

也支持旧浏览器，使用polyfill:

<script crossorigin="anonymous" src="https://polyfill.io/v3/polyfill.min.js?features=URL"></script>

但作为另一种选择，它可以通过RegEx模式简单而准确地处理:

使用正则表达式

任何形式的

绝对/相对路径 IPv4 / IPv6 网络协议/本地文件查询/散列

返回所有URL选项，但不返回searchParams

(+)也将返回文件信息，如PHP pathInfo

2022-02-09 19:07:27

我如何在javascript中解析URL到主机名和路径?

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