我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/
<!DOCTYPE html>
<html>
<head>
<title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">
<h3>Parse URL using AngularJS</h3>
url: <input type="text" ng-model="url" value="" style="width:780px;">
<ul>
<li>href = {{parser.href}}</li>
<li>protocol = {{parser.protocol}}</li>
<li>host = {{parser.host}}</li>
<li>hostname = {{parser.hostname}}</li>
<li>port = {{parser.port}}</li>
<li>pathname = {{parser.pathname}}</li>
<li>hash = {{parser.hash}}</li>
<li>search = {{parser.search}}</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>
<script>
function AppCtrl($scope) {
$scope.$watch('url', function() {
$scope.parser.href = $scope.url;
});
$scope.init = function() {
$scope.parser = document.createElement('a');
$scope.url = window.location;
}
}
</script>
</body>
</html>
其他回答
js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:
var some_uri = new URI("http://www.example.com/foo/bar");
alert(some_uri.authority); // www.example.com
alert(some_uri); // http://www.example.com/foo/bar
var blah = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full); // http://www.example.com/foo/blah
var loc = window.location; // => "http://example.com:3000/pathname/?search=test#hash"
返回当前turl。
如果你想传递你自己的字符串作为url(在IE11中不工作):
var loc = new URL("http://example.com:3000/pathname/?search=test#hash")
然后你可以这样解析它:
loc.protocol; // => "http:"
loc.host; // => "example.com:3000"
loc.hostname; // => "example.com"
loc.port; // => "3000"
loc.pathname; // => "/pathname/"
loc.hash; // => "#hash"
loc.search; // => "?search=test"
只需使用url.js库(用于web和node.js)。
https://github.com/websanova/js-url
url: http://example.com?param=test#param=again
url('?param'); // test
url('#param'); // again
url('protocol'); // http
url('port'); // 80
url('domain'); // example.com
url('tld'); // com
etc...
那么简单的正则表达式呢?
url = "http://www.example.com/path/to/somwhere";
urlParts = /^(?:\w+\:\/\/)?([^\/]+)(.*)$/.exec(url);
hostname = urlParts[1]; // www.example.com
path = urlParts[2]; // /path/to/somwhere
下面是一个使用regexp的简单函数,它模仿了a标记行为。
Pros
可预测的行为(无跨浏览器问题) 不需要DOM 它真的很短。
Cons
regexp有点难读
-
function getLocation(href) {
var match = href.match(/^(https?\:)\/\/(([^:\/?#]*)(?:\:([0-9]+))?)([\/]{0,1}[^?#]*)(\?[^#]*|)(#.*|)$/);
return match && {
href: href,
protocol: match[1],
host: match[2],
hostname: match[3],
port: match[4],
pathname: match[5],
search: match[6],
hash: match[7]
}
}
-
getLocation("http://example.com/");
/*
{
"protocol": "http:",
"host": "example.com",
"hostname": "example.com",
"port": undefined,
"pathname": "/"
"search": "",
"hash": "",
}
*/
getLocation("http://example.com:3000/pathname/?search=test#hash");
/*
{
"protocol": "http:",
"host": "example.com:3000",
"hostname": "example.com",
"port": "3000",
"pathname": "/pathname/",
"search": "?search=test",
"hash": "#hash"
}
*/
编辑:
下面是正则表达式的分解
var reURLInformation = new RegExp([
'^(https?:)//', // protocol
'(([^:/?#]*)(?::([0-9]+))?)', // host (hostname and port)
'(/{0,1}[^?#]*)', // pathname
'(\\?[^#]*|)', // search
'(#.*|)$' // hash
].join(''));
var match = href.match(reURLInformation);