基本上,就像标题说的那样。我想知道如何添加1天的NSDate。

如果它是:

21st February 2011

它将变成:

22nd February 2011

或者如果它是:

31st December 2011

它将变成:

1st January 2012.

当前回答

Swift 3.0非常简单的实现将是:

func dateByAddingDays(inDays: Int) -> Date {
    let today = Date()
    return Calendar.current.date(byAdding: .day, value: inDays, to: today)!
}

其他回答

Swift 4,如果你真正需要的是24小时轮班(60*60*24秒)而不是“1个日历天”

未来: let dayAhead = Date(timeIntervalSinceNow: TimeInterval(86400.0))

过去: let dayAgo = Date(timeIntervalSinceNow: TimeInterval(-86400.0))

使用以下代码:

NSDate *now = [NSDate date];
int daysToAdd = 1;
NSDate *newDate1 = [now dateByAddingTimeInterval:60*60*24*daysToAdd];

As

addTimeInterval

现在已弃用。

Swift 5.0:

var dayComponent    = DateComponents()
dayComponent.day    = 1 // For removing one day (yesterday): -1
let theCalendar     = Calendar.current
let nextDate        = theCalendar.date(byAdding: dayComponent, to: Date())
print("nextDate : \(nextDate)")

目标C:

NSDateComponents *dayComponent = [[NSDateComponents alloc] init];
dayComponent.day = 1;

NSCalendar *theCalendar = [NSCalendar currentCalendar];
NSDate *nextDate = [theCalendar dateByAddingComponents:dayComponent toDate:[NSDate date] options:0];

NSLog(@"nextDate: %@ ...", nextDate);

这应该是不言而喻的。

Swift 3.0非常简单的实现将是:

func dateByAddingDays(inDays: Int) -> Date {
    let today = Date()
    return Calendar.current.date(byAdding: .day, value: inDays, to: today)!
}

我也有同样的问题;使用NSDate扩展:

- (id)dateByAddingYears:(NSUInteger)years
                 months:(NSUInteger)months
                   days:(NSUInteger)days
                  hours:(NSUInteger)hours
                minutes:(NSUInteger)minutes
                seconds:(NSUInteger)seconds
{
    NSDateComponents * delta = [[[NSDateComponents alloc] init] autorelease];
    NSCalendar * gregorian = [[[NSCalendar alloc]
                               initWithCalendarIdentifier:NSCalendarIdentifierGregorian] autorelease];

    [delta setYear:years];
    [delta setMonth:months];
    [delta setDay:days];
    [delta setHour:hours];
    [delta setMinute:minutes];
    [delta setSecond:seconds];

    return [gregorian dateByAddingComponents:delta toDate:self options:0];
}