Android上的LocationManager API似乎对一个只需要偶尔粗略估计用户位置的应用程序来说有点麻烦。

我正在开发的应用程序本身并不是一个定位应用程序,但它确实需要获取用户的位置,以便显示附近企业的列表。它不需要担心用户是否在移动或类似的事情。

以下是我想做的:

向用户显示附近位置的列表。预加载用户的位置,以便在“活动X”中需要它时,它将可用。我并不特别关心更新的准确性或频率。只要不太远,只要抓住一个位置就足够了。也许如果我想变得更漂亮,我会每隔几分钟左右更新一次位置,但这不是一个很大的优先事项。适用于任何具有GPS或网络位置提供商的设备。

这似乎并不难,但在我看来,我必须组建两个不同的位置提供商(GPS和NETWORK),并管理每个提供商的生命周期。不仅如此,我还必须在多个活动中复制相同的代码以满足#2。过去,我曾尝试使用getBestProvider()将解决方案简化为仅使用一个位置提供程序,但这似乎只提供了最好的“理论”提供程序,而不是实际会为您提供最佳结果的提供程序。

有没有更简单的方法来实现这一点?


当前回答

Kotlin版本的@Fedor Greate回答:

类的用法:

val locationResult = object : MyLocation.LocationResult() {

    override fun gotLocation(location: Location?) {

        val lat = location!!.latitude
        val lon = location.longitude

        Toast.makeText(context, "$lat --SLocRes-- $lon", Toast.LENGTH_SHORT).show()
    }

}

val myLocation = MyLocation()
myLocation.getLocation(inflater.context, locationResult)

MyLocation类:

class MyLocation {
    internal lateinit var timer1: Timer
    internal var lm: LocationManager? = null
    internal lateinit var locationResult: LocationResult
    internal var gps_enabled = false
    internal var network_enabled = false

    internal var locationListenerGps: LocationListener = object : LocationListener {


        override fun onLocationChanged(location: Location) {
            timer1.cancel()
            locationResult.gotLocation(location)
            lm!!.removeUpdates(this)
            lm!!.removeUpdates(locationListenerNetwork)
        }

        override fun onProviderDisabled(provider: String) {}
        override fun onProviderEnabled(provider: String) {}
        override fun onStatusChanged(provider: String, status: Int, extras: Bundle) {}
    }

    internal var locationListenerNetwork: LocationListener = object : LocationListener {
        override fun onLocationChanged(location: Location) {
            timer1.cancel()
            locationResult.gotLocation(location)
            lm!!.removeUpdates(this)
            lm!!.removeUpdates(locationListenerGps)
        }

        override fun onProviderDisabled(provider: String) {}
        override fun onProviderEnabled(provider: String) {}
        override fun onStatusChanged(provider: String, status: Int, extras: Bundle) {}
    }

    fun getLocation(context: Context, result: LocationResult): Boolean {
        //I use LocationResult callback class to pass location value from MyLocation to user code.
        locationResult = result
        if (lm == null)
            lm = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager?

        //exceptions will be thrown if provider is not permitted.
        try {
            gps_enabled = lm!!.isProviderEnabled(LocationManager.GPS_PROVIDER)
        } catch (ex: Exception) {
        }

        try {
            network_enabled = lm!!.isProviderEnabled(LocationManager.NETWORK_PROVIDER)
        } catch (ex: Exception) {
        }

        //don't start listeners if no provider is enabled
        if (!gps_enabled && !network_enabled)
            return false

        if (ActivityCompat.checkSelfPermission(context,
                Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED ||
            ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED) run {

            ActivityCompat.requestPermissions(context as Activity,
                arrayOf(Manifest.permission.ACCESS_FINE_LOCATION, Manifest.permission.ACCESS_COARSE_LOCATION), 111)
        }


        if (gps_enabled)
            lm!!.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0f, locationListenerGps)
        if (network_enabled)
            lm!!.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0f, locationListenerNetwork)
        timer1 = Timer()
        timer1.schedule(GetLastLocation(context), 20000)
        return true
    }

    internal inner class GetLastLocation(var context: Context) : TimerTask() {
        override fun run() {
            lm!!.removeUpdates(locationListenerGps)
            lm!!.removeUpdates(locationListenerNetwork)

            var net_loc: Location? = null
            var gps_loc: Location? = null

            if (ActivityCompat.checkSelfPermission(context,
                    Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED ||
                ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED
            ) run {

                ActivityCompat.requestPermissions(context as Activity,
                    arrayOf(Manifest.permission.ACCESS_FINE_LOCATION, Manifest.permission.ACCESS_COARSE_LOCATION),111)
            }


            if (gps_enabled)
                gps_loc = lm!!.getLastKnownLocation(LocationManager.GPS_PROVIDER)
            if (network_enabled)
                net_loc = lm!!.getLastKnownLocation(LocationManager.NETWORK_PROVIDER)

            //if there are both values use the latest one
            if (gps_loc != null && net_loc != null) {
                if (gps_loc.getTime() > net_loc.getTime())
                    locationResult.gotLocation(gps_loc)
                else
                    locationResult.gotLocation(net_loc)
                return
            }

            if (gps_loc != null) {
                locationResult.gotLocation(gps_loc)
                return
            }
            if (net_loc != null) {
                locationResult.gotLocation(net_loc)
                return
            }
            locationResult.gotLocation(null)
        }
    }

     abstract class LocationResult {
          abstract fun gotLocation(location: Location?)
    }
}

其他回答

编辑:更新了Google Play Services库中的最新位置服务API(2014年7月)

我建议您使用新的位置服务API,该API可从Google Play Services库中获得,它提供了一个更强大的高级框架,可自动执行位置提供商选择和电源管理等任务。根据官方文档:“……位置API使您可以轻松地构建位置感知应用程序,而无需关注底层位置技术的细节。它们还允许您通过使用设备硬件的所有功能来最小化功耗。”

有关更多信息,请访问:使您的应用程序位置感知

要查看使用最新位置服务API的完整示例,请访问:Android LocationClient类已弃用,但在文档中使用

这里有点晚了,但在这种情况下,我会使用谷歌地图API,并使用谷歌地图的纬度和经度API标记附近的位置。另外,如果你能在地图上显示他/她的位置,用户体验会更好。无需担心用户位置的更新或使用android api搜索。让谷歌地图为您处理内部内容。

@emmby可能已经在他的应用程序中解决了这个问题,但为了将来的参考,我向其他开发人员推荐的是查看谷歌地图API中的位置特定内容。

编辑:在谷歌地图中显示用户位置的链接

最近进行了重构以获得代码的位置,学习了一些好的想法,最终实现了一个相对完善的库和演示。

//request all valid provider(network/gps)
private boolean requestAllProviderUpdates() {
    checkRuntimeEnvironment();
    checkPermission();

    if (isRequesting) {
        EasyLog.d("Request location update is busy");
        return false;
    }


    long minTime = getCheckTimeInterval();
    float minDistance = getCheckMinDistance();

    if (mMapLocationListeners == null) {
        mMapLocationListeners = new HashMap<>();
    }

    mValidProviders = getValidProviders();
    if (mValidProviders == null || mValidProviders.isEmpty()) {
        throw new IllegalArgumentException("Not available provider.");
    }

    for (String provider : mValidProviders) {
        LocationListener locationListener = new LocationListener() {
            @Override
            public void onLocationChanged(Location location) {
                if (location == null) {
                    EasyLog.e("LocationListener callback location is null.");
                    return;
                }
                printf(location);
                mLastProviderTimestamp = location.getTime();

                if (location.getProvider().equals(LocationManager.GPS_PROVIDER)) {
                    finishResult(location);
                } else {
                    doLocationResult(location);
                }

                removeProvider(location.getProvider());
                if (isEmptyValidProviders()) {
                    requestTimeoutMsgInit();
                    removeUpdates();
                }
            }

            @Override
            public void onStatusChanged(String provider, int status, Bundle extras) {
            }

            @Override
            public void onProviderEnabled(String provider) {
            }

            @Override
            public void onProviderDisabled(String provider) {
            }
        };
        getLocationManager().requestLocationUpdates(provider, minTime, minDistance, locationListener);
        mMapLocationListeners.put(provider, locationListener);
        EasyLog.d("Location request %s provider update.", provider);
    }
    isRequesting = true;
    return true;
}

//remove request update
public void removeUpdates() {
    checkRuntimeEnvironment();

    LocationManager locationManager = getLocationManager();
    if (mMapLocationListeners != null) {
        Set<String> keys = mMapLocationListeners.keySet();
        for (String key : keys) {
            LocationListener locationListener = mMapLocationListeners.get(key);
            if (locationListener != null) {
                locationManager.removeUpdates(locationListener);
                EasyLog.d("Remove location update, provider is " + key);
            }
        }
        mMapLocationListeners.clear();
        isRequesting = false;
    }
}

//Compared with the last successful position, to determine whether you need to filter
private boolean isNeedFilter(Location location) {
    checkLocation(location);

    if (mLastLocation != null) {
        float distance = location.distanceTo(mLastLocation);
        if (distance < getCheckMinDistance()) {
            return true;
        }
        if (location.getAccuracy() >= mLastLocation.getAccuracy()
                && distance < location.getAccuracy()) {
            return true;
        }
        if (location.getTime() <= mLastProviderTimestamp) {
            return true;
        }
    }
    return false;
}

private void doLocationResult(Location location) {
    checkLocation(location);

    if (isNeedFilter(location)) {
        EasyLog.d("location need to filtered out, timestamp is " + location.getTime());
        finishResult(mLastLocation);
    } else {
        finishResult(location);
    }
}

//Return to the finished position
private void finishResult(Location location) {
    checkLocation(location);

    double latitude = location.getLatitude();
    double longitude = location.getLongitude();
    float accuracy = location.getAccuracy();
    long time = location.getTime();
    String provider = location.getProvider();

    if (mLocationResultListeners != null && !mLocationResultListeners.isEmpty()) {
        String format = "Location result:<%f, %f> Accuracy:%f Time:%d Provider:%s";
        EasyLog.i(String.format(format, latitude, longitude, accuracy, time, provider));

        mLastLocation = location;
        synchronized (this) {
            Iterator<LocationResultListener> iterator =  mLocationResultListeners.iterator();
            while (iterator.hasNext()) {
                LocationResultListener listener = iterator.next();
                if (listener != null) {
                    listener.onResult(location);
                }
                iterator.remove();
            }
        }
    }
}

完整代码:https://github.com/bingerz/FastLocation/blob/master/fastlocationlib/src/main/java/cn/bingerz/fastlocation/FastLocation.java

*每次请求完成位置时,最好删除更新,否则手机状态栏将始终显示定位图标。

通过使用FusedLocationProviderApi,这是最新的API,也是在Android中获取位置的最佳可能性。将其添加到build.gradle文件中

dependencies {
    compile 'com.google.android.gms:play-services:6.5.87'
}

您可以通过此url获取完整的源代码http://javapapers.com/android/android-location-fused-provider/

你可以一直使用LocationManager.getLastKnownLocation(),但就像它说的那样,它可能已经过时了。

获取一般位置的一个简单方法是注册网络(通常很快)。

LocationManager locationManager = (LocationManager) this.getSystemService(Context.LOCATION_SERVICE);
locationManager.requestLocationUpdates(
     LocationManager.NETWORK_PROVIDER, 1000, 1000, this);

然后做

locationManager.removeUpdates(this);

在侦听器的onLocationChanged()方法中。