我使用AJAX获取了以下对象，并将它们存储在数组中：
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
如何创建一个函数，仅使用JavaScript按price属性按升序或降序对对象进行排序？
当前回答
我还处理了一些评级和多个字段排序：
arr = [
{type:'C', note:834},
{type:'D', note:732},
{type:'D', note:008},
{type:'F', note:474},
{type:'P', note:283},
{type:'P', note:165},
{type:'X', note:173},
{type:'Z', note:239},
];
arr.sort(function(a,b){
var _a = ((a.type==='C')?'0':(a.type==='P')?'1':'2');
_a += (a.type.localeCompare(b.type)===-1)?'0':'1';
_a += (a.note>b.note)?'1':'0';
var _b = ((b.type==='C')?'0':(b.type==='P')?'1':'2');
_b += (b.type.localeCompare(a.type)===-1)?'0':'1';
_b += (b.note>a.note)?'1':'0';
return parseInt(_a) - parseInt(_b);
});
后果
[
{"type":"C","note":834},
{"type":"P","note":165},
{"type":"P","note":283},
{"type":"D","note":8},
{"type":"D","note":732},
{"type":"F","note":474},
{"type":"X","note":173},
{"type":"Z","note":239}
]
其他回答
我还处理了一些评级和多个字段排序：
arr = [
{type:'C', note:834},
{type:'D', note:732},
{type:'D', note:008},
{type:'F', note:474},
{type:'P', note:283},
{type:'P', note:165},
{type:'X', note:173},
{type:'Z', note:239},
];
arr.sort(function(a,b){
var _a = ((a.type==='C')?'0':(a.type==='P')?'1':'2');
_a += (a.type.localeCompare(b.type)===-1)?'0':'1';
_a += (a.note>b.note)?'1':'0';
var _b = ((b.type==='C')?'0':(b.type==='P')?'1':'2');
_b += (b.type.localeCompare(a.type)===-1)?'0':'1';
_b += (b.note>a.note)?'1':'0';
return parseInt(_a) - parseInt(_b);
});
后果
[
{"type":"C","note":834},
{"type":"P","note":165},
{"type":"P","note":283},
{"type":"D","note":8},
{"type":"D","note":732},
{"type":"F","note":474},
{"type":"X","note":173},
{"type":"Z","note":239}
]
仅对于元素值的普通数组：
function sortArrayOfElements(arrayToSort) {
function compareElements(a, b) {
if (a < b)
return -1;
if (a > b)
return 1;
return 0;
}
return arrayToSort.sort(compareElements);
}
e.g. 1:
var array1 = [1,2,545,676,64,2,24]
output : [1, 2, 2, 24, 64, 545, 676]
var array2 = ["v","a",545,676,64,2,"24"]
output: ["a", "v", 2, "24", 64, 545, 676]
对于对象数组：
function sortArrayOfObjects(arrayToSort, key) {
function compareObjects(a, b) {
if (a[key] < b[key])
return -1;
if (a[key] > b[key])
return 1;
return 0;
}
return arrayToSort.sort(compareObjects);
}
e.g. 1: var array1= [{"name": "User4", "value": 4},{"name": "User3", "value": 3},{"name": "User2", "value": 2}]
output : [{"name": "User2", "value": 2},{"name": "User3", "value": 3},{"name": "User4", "value": 4}]
虽然我知道OP想要对一组数字进行排序，但这个问题已经被标记为字符串相关类似问题的答案。事实上，上面的答案没有考虑对大小写很重要的文本数组进行排序。大多数答案采用字符串值并将其转换为大写/小写，然后以某种方式进行排序。我遵守的要求很简单：
按字母顺序A-Z排序同一单词的大写值应在小写值之前应将相同字母（A/A、B/B）的值分组在一起
我期望的是[A，A，B，B，C，C]，但上面的答案返回A，B，C，A，B，C。实际上，我在这个问题上花了比我想要的时间更长的时间（这就是为什么我发布这个消息，希望它能帮助至少一个人）。虽然两个用户在注释中提到了localeCompare函数，但直到我在四处搜索时偶然发现了该函数之后，我才发现这一点。在阅读了String.product.localeCompare（）文档后，我想到了这个：
var values = [ "Delta", "charlie", "delta", "Charlie", "Bravo", "alpha", "Alpha", "bravo" ];
var sorted = values.sort((a, b) => a.localeCompare(b, undefined, { caseFirst: "upper" }));
// Result: [ "Alpha", "alpha", "Bravo", "bravo", "Charlie", "charlie", "Delta", "delta" ]
这告诉函数在小写值之前对大写值进行排序。localeCompare函数中的第二个参数是定义语言环境，但如果您将其保留为未定义，它会自动为您计算语言环境。
这同样适用于对对象数组进行排序：
var values = [
{ id: 6, title: "Delta" },
{ id: 2, title: "charlie" },
{ id: 3, title: "delta" },
{ id: 1, title: "Charlie" },
{ id: 8, title: "Bravo" },
{ id: 5, title: "alpha" },
{ id: 4, title: "Alpha" },
{ id: 7, title: "bravo" }
];
var sorted = values
.sort((a, b) => a.title.localeCompare(b.title, undefined, { caseFirst: "upper" }));
虽然仅对单个数组进行排序有点过分，但该原型函数允许使用点语法按任何键（包括嵌套键）按升序或降序对Javascript数组进行排序。
(function(){
var keyPaths = [];
var saveKeyPath = function(path) {
keyPaths.push({
sign: (path[0] === '+' || path[0] === '-')? parseInt(path.shift()+1) : 1,
path: path
});
};
var valueOf = function(object, path) {
var ptr = object;
for (var i=0,l=path.length; i<l; i++) ptr = ptr[path[i]];
return ptr;
};
var comparer = function(a, b) {
for (var i = 0, l = keyPaths.length; i < l; i++) {
aVal = valueOf(a, keyPaths[i].path);
bVal = valueOf(b, keyPaths[i].path);
if (aVal > bVal) return keyPaths[i].sign;
if (aVal < bVal) return -keyPaths[i].sign;
}
return 0;
};
Array.prototype.sortBy = function() {
keyPaths = [];
for (var i=0,l=arguments.length; i<l; i++) {
switch (typeof(arguments[i])) {
case "object": saveKeyPath(arguments[i]); break;
case "string": saveKeyPath(arguments[i].match(/[+-]|[^.]+/g)); break;
}
}
return this.sort(comparer);
};
})();
用法：
var data = [
{ name: { first: 'Josh', last: 'Jones' }, age: 30 },
{ name: { first: 'Carlos', last: 'Jacques' }, age: 19 },
{ name: { first: 'Carlos', last: 'Dante' }, age: 23 },
{ name: { first: 'Tim', last: 'Marley' }, age: 9 },
{ name: { first: 'Courtney', last: 'Smith' }, age: 27 },
{ name: { first: 'Bob', last: 'Smith' }, age: 30 }
]
data.sortBy('age'); // "Tim Marley(9)", "Carlos Jacques(19)", "Carlos Dante(23)", "Courtney Smith(27)", "Josh Jones(30)", "Bob Smith(30)"
按具有点语法或数组语法的嵌套财产排序：
data.sortBy('name.first'); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
data.sortBy(['name', 'first']); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
按多个键排序：
data.sortBy('name.first', 'age'); // "Bob Smith(30)", "Carlos Jacques(19)", "Carlos Dante(23)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
data.sortBy('name.first', '-age'); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
您可以分叉回购：https://github.com/eneko/Array.sortBy
homes.sort(function(a, b){
var nameA=a.prices.toLowerCase(), nameB=b.prices.toLowerCase()
if (nameA < nameB) //sort string ascending
return -1
if (nameA > nameB)
return 1
return 0 //default return value (no sorting)
})
