我使用AJAX获取了以下对象,并将它们存储在数组中:

var homes = [
    {
        "h_id": "3",
        "city": "Dallas",
        "state": "TX",
        "zip": "75201",
        "price": "162500"
    }, {
        "h_id": "4",
        "city": "Bevery Hills",
        "state": "CA",
        "zip": "90210",
        "price": "319250"
    }, {
        "h_id": "5",
        "city": "New York",
        "state": "NY",
        "zip": "00010",
        "price": "962500"
    }
];

如何创建一个函数,仅使用JavaScript按price属性按升序或降序对对象进行排序?


当前回答

价格降序:

homes.sort((x,y) => {return y.price - x.price})

价格升序:

homes.sort((x,y) => {return x.price - y.price})

其他回答

可以使用string1.localeCompare(string2)进行字符串比较

this.myArray.sort((a,b) => { 
    return a.stringProp.localeCompare(b.stringProp);
});

注意localCompare不区分大小写

function sortByProperty(home){
    return home.price
}

sortByProperty按价格获取属性。将来,您可能希望按“zip”或字符串值“city”对数据进行排序。您需要在上面的函数中更改home.price

// if you want descending order change this to false
// if you are on react.js you could set this with useState
const ascending=true
// Initially "b" is the index-1 item and "a" is the index-0 item
homes.sort((a,b)=>{
     //initially 0th index
     const first=sortByProperty(a)
     // initially 1st index 
     const second=sortByProperty(b)
     
     // if you multiply by -1 it will be descending 
     const sortOrder=ascending ? 1 : -1
     if (typeof first==="number"){
            return (first-second) * sortOrder
    } else {
           // this will compare the string values
           return (first.localeCompare(second)) * sortOrder
    }
})
 function compareValues(key, order = 'asc') {
  return function innerSort(a, b) {
    if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
      // property doesn't exist on either object
      return 0;
    }

    const varA = (typeof a[key] === 'string')
      ? a[key].toUpperCase() : a[key];
    const varB = (typeof b[key] === 'string')
      ? b[key].toUpperCase() : b[key];

    let comparison = 0;
    if (varA > varB) {
      comparison = 1;
    } else if (varA < varB) {
      comparison = -1;
    }
    return (
      (order === 'desc') ? (comparison * -1) : comparison
    );
  };
}

http://yazilimsozluk.com/sort-array-in-javascript-by-asc-or-desc

虽然我知道OP想要对一组数字进行排序,但这个问题已经被标记为字符串相关类似问题的答案。事实上,上面的答案没有考虑对大小写很重要的文本数组进行排序。大多数答案采用字符串值并将其转换为大写/小写,然后以某种方式进行排序。我遵守的要求很简单:

按字母顺序A-Z排序同一单词的大写值应在小写值之前应将相同字母(A/A、B/B)的值分组在一起

我期望的是[A,A,B,B,C,C],但上面的答案返回A,B,C,A,B,C。实际上,我在这个问题上花了比我想要的时间更长的时间(这就是为什么我发布这个消息,希望它能帮助至少一个人)。虽然两个用户在注释中提到了localeCompare函数,但直到我在四处搜索时偶然发现了该函数之后,我才发现这一点。在阅读了String.product.localeCompare()文档后,我想到了这个:

var values = [ "Delta", "charlie", "delta", "Charlie", "Bravo", "alpha", "Alpha", "bravo" ];
var sorted = values.sort((a, b) => a.localeCompare(b, undefined, { caseFirst: "upper" }));
// Result: [ "Alpha", "alpha", "Bravo", "bravo", "Charlie", "charlie", "Delta", "delta" ]

这告诉函数在小写值之前对大写值进行排序。localeCompare函数中的第二个参数是定义语言环境,但如果您将其保留为未定义,它会自动为您计算语言环境。

这同样适用于对对象数组进行排序:

var values = [
    { id: 6, title: "Delta" },
    { id: 2, title: "charlie" },
    { id: 3, title: "delta" },
    { id: 1, title: "Charlie" },
    { id: 8, title: "Bravo" },
    { id: 5, title: "alpha" },
    { id: 4, title: "Alpha" },
    { id: 7, title: "bravo" }
];
var sorted = values
    .sort((a, b) => a.title.localeCompare(b.title, undefined, { caseFirst: "upper" }));

要对数组进行排序,必须定义一个比较器函数。此函数始终根据您所需的排序模式或顺序(即升序或降序)而不同。

让我们创建一些函数,对数组进行升序或降序排序,并包含对象、字符串或数值。

function sorterAscending(a,b) {
    return a-b;
}

function sorterDescending(a,b) {
    return b-a;
}

function sorterPriceAsc(a,b) {
    return parseInt(a['price']) - parseInt(b['price']);
}

function sorterPriceDes(a,b) {
    return parseInt(b['price']) - parseInt(b['price']);
}

排序数字(按字母顺序和升序):

var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();

排序数字(按字母顺序和降序):

var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
fruits.reverse();

排序编号(数字和升序):

var points = [40,100,1,5,25,10];
points.sort(sorterAscending());

排序编号(数字和降序):

var points = [40,100,1,5,25,10];
points.sort(sorterDescending());

如上所述,将sorterPriceAsc和sorterPriceDes方法用于具有所需键的数组。

homes.sort(sorterPriceAsc()) or homes.sort(sorterPriceDes())