我使用AJAX获取了以下对象，并将它们存储在数组中：
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
如何创建一个函数，仅使用JavaScript按price属性按升序或降序对对象进行排序？
当前回答
价格降序：
homes.sort((x,y) => {return y.price - x.price})
价格升序：
homes.sort((x,y) => {return x.price - y.price})
其他回答
对于多数组对象字段的排序。在arrprop数组中输入域名，如[“a”，“b”，“c”]然后传入我们要排序的第二个参数arrsource实际源。
function SortArrayobject(arrprop,arrsource){
arrprop.forEach(function(i){
arrsource.sort(function(a,b){
return ((a[i] < b[i]) ? -1 : ((a[i] > b[i]) ? 1 : 0));
});
});
return arrsource;
}
使用lodash.sortBy（使用commonjs的说明，您也可以将cdn的脚本include标记放在html的顶部）
var sortBy = require('lodash.sortby');
// or
sortBy = require('lodash').sortBy;
降序
var descendingOrder = sortBy( homes, 'price' ).reverse();
升序
var ascendingOrder = sortBy( homes, 'price' );
我还处理了一些评级和多个字段排序：
arr = [
{type:'C', note:834},
{type:'D', note:732},
{type:'D', note:008},
{type:'F', note:474},
{type:'P', note:283},
{type:'P', note:165},
{type:'X', note:173},
{type:'Z', note:239},
];
arr.sort(function(a,b){
var _a = ((a.type==='C')?'0':(a.type==='P')?'1':'2');
_a += (a.type.localeCompare(b.type)===-1)?'0':'1';
_a += (a.note>b.note)?'1':'0';
var _b = ((b.type==='C')?'0':(b.type==='P')?'1':'2');
_b += (b.type.localeCompare(a.type)===-1)?'0':'1';
_b += (b.note>a.note)?'1':'0';
return parseInt(_a) - parseInt(_b);
});
后果
[
{"type":"C","note":834},
{"type":"P","note":165},
{"type":"P","note":283},
{"type":"D","note":8},
{"type":"D","note":732},
{"type":"F","note":474},
{"type":"X","note":173},
{"type":"Z","note":239}
]
有了ECMAScript 6，StoBor的答案可以更加简洁：
homes.sort((a, b) => a.price - b.price)
这里是以上所有答案的顶点。
Fiddle验证：http://jsfiddle.net/bobberino/4qqk3/
var sortOn = function (arr, prop, reverse, numeric) {
// Ensure there's a property
if (!prop || !arr) {
return arr
}
// Set up sort function
var sort_by = function (field, rev, primer) {
// Return the required a,b function
return function (a, b) {
// Reset a, b to the field
a = primer(a[field]), b = primer(b[field]);
// Do actual sorting, reverse as needed
return ((a < b) ? -1 : ((a > b) ? 1 : 0)) * (rev ? -1 : 1);
}
}
// Distinguish between numeric and string to prevent 100's from coming before smaller
// e.g.
// 1
// 20
// 3
// 4000
// 50
if (numeric) {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to a string.
// - Replace any non numeric characters.
// - Parse as float to allow 0.02 values.
return parseFloat(String(a).replace(/[^0-9.-]+/g, ''));
}));
} else {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to string.
return String(a).toUpperCase();
}));
}
}
