select t3.name, sum(t3.prod_A) as Prod_A, sum(t3.prod_B) as Prod_B, sum(t3.prod_C) as    Prod_C, sum(t3.prod_D) as Prod_D, sum(t3.prod_E) as Prod_E  
from
(select t2.name as name, 
case when t2.prodid = 1 then t2.counts
else 0 end  prod_A, 

case when t2.prodid = 2 then t2.counts
else 0 end prod_B,

case when t2.prodid = 3 then t2.counts
else 0 end prod_C,

case when t2.prodid = 4 then t2.counts
else 0 end prod_D, 

case when t2.prodid = "5" then t2.counts
else 0 end prod_E

from 
(SELECT partners.name as name, sales.products_id as prodid, count(products.name) as counts
FROM test.sales left outer join test.partners on sales.partners_id = partners.id
left outer join test.products on sales.products_id = products.id 
where sales.partners_id = partners.id and sales.products_id = products.id group by partners.name, prodid) t2) t3

group by t3.name ;

SELECT company_name, SUM(CASE WHEN ACTION = 'Email' THEN 1 ELSE 0 END) AS "Email",
SUM(CASE WHEN ACTION = 'Print' AND pagecount = 1 THEN 1 ELSE 0 END) AS "print 1 PAGE",
SUM(CASE WHEN ACTION = 'Print' AND pagecount = 2 THEN 1 ELSE 0 END) AS "print 2 PAGE",
SUM(CASE WHEN ACTION = 'Print' AND pagecount = 3 THEN 1 ELSE 0 END) AS "print 2 PAGE"
FROM test1 GROUP BY company_name;

一种选择是结合使用CASE..WHEN语句在MySQL数据库的聚合中是冗余的，并动态考虑所需的查询生成，同时为结果集获得适当的列标题，如下代码块所示:

SET @sql = NULL;

SELECT GROUP_CONCAT(
             CONCAT('SUM( `action` = ''', action, '''',pc0,' ) AS ',action,pc1)
       )
  INTO @sql
  FROM 
  ( 
   SELECT DISTINCT `action`, 
          IF(`pagecount` IS NULL,'',CONCAT('page',`pagecount`)) AS pc1,
          IF(`pagecount` IS NULL,'',CONCAT(' AND `pagecount` = ', pagecount, '')) AS pc0
     FROM `tab` 
    ORDER BY CONCAT(action,pc0) 
  ) t;

SET @sql = CONCAT('SELECT company_name,',@sql,' FROM `tab` GROUP BY company_name'); 
SELECT @sql; 

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

Demo

对于MySQL，您可以直接将条件放在SUM()函数中，它将被计算为布尔0或1，因此您可以根据您的条件计算，而无需使用IF/CASE语句

SELECT
    company_name,  
    SUM(action = 'EMAIL')AS Email,
    SUM(action = 'PRINT' AND pagecount = 1)AS Print1Pages,
    SUM(action = 'PRINT' AND pagecount = 2)AS Print2Pages,
    SUM(action = 'PRINT' AND pagecount = 3)AS Print3Pages
FROM t
GROUP BY company_name

DEMO

select t3.name, sum(t3.prod_A) as Prod_A, sum(t3.prod_B) as Prod_B, sum(t3.prod_C) as    Prod_C, sum(t3.prod_D) as Prod_D, sum(t3.prod_E) as Prod_E  
from
(select t2.name as name, 
case when t2.prodid = 1 then t2.counts
else 0 end  prod_A, 

case when t2.prodid = 2 then t2.counts
else 0 end prod_B,

case when t2.prodid = 3 then t2.counts
else 0 end prod_C,

case when t2.prodid = 4 then t2.counts
else 0 end prod_D, 

case when t2.prodid = "5" then t2.counts
else 0 end prod_E

from 
(SELECT partners.name as name, sales.products_id as prodid, count(products.name) as counts
FROM test.sales left outer join test.partners on sales.partners_id = partners.id
left outer join test.products on sales.products_id = products.id 
where sales.partners_id = partners.id and sales.products_id = products.id group by partners.name, prodid) t2) t3

group by t3.name ;

有一个叫做MySQL数据透视表生成器的工具，它可以帮助你创建一个基于web的数据透视表，然后你可以导出到excel(如果你喜欢的话)。如果数据在单个表或多个表中，它都可以工作。

您需要做的就是指定列(它支持动态列)、行、表主体中的值和表关系(如果有的话)的数据源。

该工具的主页为https://mysqlreports.com/mysql-reporting-tools/mysql-pivot-table/