Ruby的例子:

name = "Spongebob Squarepants"
puts "Who lives in a Pineapple under the sea? \n#{name}."

成功的Python字符串连接对我来说似乎很冗长。


当前回答

Python的字符串插值类似于C的printf()

如果你尝试:

name = "SpongeBob Squarepants"
print "Who lives in a Pineapple under the sea? %s" % name

标记%s将被name变量替换。您应该看一下打印功能标签:http://docs.python.org/library/functions.html

其他回答

对于旧的Python(在2.4上测试),上面的解决方案指明了方向。你可以这样做:

import string

def try_interp():
    d = 1
    f = 1.1
    s = "s"
    print string.Template("d: $d f: $f s: $s").substitute(**locals())

try_interp()

你会得到

d: 1 f: 1.1 s: s

从Python 2.6开始。X你可能想用:

"my {0} string: {1}".format("cool", "Hello there!")

Python的字符串插值类似于C的printf()

如果你尝试:

name = "SpongeBob Squarepants"
print "Who lives in a Pineapple under the sea? %s" % name

标记%s将被name变量替换。您应该看一下打印功能标签:http://docs.python.org/library/functions.html

按照PEP 498的规定,Python 3.6将包含字符串插值。你可以这样做:

name = 'Spongebob Squarepants'
print(f'Who lives in a Pineapple under the sea? \n{name}')

请注意,我讨厌海绵宝宝,所以写这篇文章有点痛苦。:)

Python 3.6及更新版本使用f-strings进行字面值字符串插值:

name='world'
print(f"Hello {name}!")