下面是如何做到这一点，如果你使用SimpleCursorAdapter(其中columnName是你用来填充你的spinner的db列的名称):

private int getIndex(Spinner spinner, String columnName, String searchString) {

    //Log.d(LOG_TAG, "getIndex(" + searchString + ")");

    if (searchString == null || spinner.getCount() == 0) {

        return -1; // Not found
    }
    else {

        Cursor cursor = (Cursor)spinner.getItemAtPosition(0);

        int initialCursorPos = cursor.getPosition(); //  Remember for later

        int index = -1; // Not found
        for (int i = 0; i < spinner.getCount(); i++) {

            cursor.moveToPosition(i);
            String itemText = cursor.getString(cursor.getColumnIndex(columnName));

            if (itemText.equals(searchString)) {
                index = i; // Found!
                break;
            }
        }

        cursor.moveToPosition(initialCursorPos); // Leave cursor as we found it.

        return index;
    }
}

同样(对Akhil的回答进行了细化)，如果你从数组中填充你的Spinner，这是相应的方法:

private int getIndex(Spinner spinner, String searchString) {

    if (searchString == null || spinner.getCount() == 0) {

        return -1; // Not found

    }
    else {

        for (int i = 0; i < spinner.getCount(); i++) {
            if (spinner.getItemAtPosition(i).toString().equals(searchString)) {
                return i; // Found!
            }
        }

        return -1; // Not found
    }
};

你可以使用这种方式，只是让你的代码更简单、更清晰。

ArrayAdapter<String> adapter = (ArrayAdapter<String>) spinnerCountry.getAdapter();
int position = adapter.getPosition(obj.getCountry());
spinnerCountry.setSelection(position);

希望能有所帮助。

实际上有一种方法可以使用AdapterArray上的索引搜索来获得这个，所有这些都可以通过反射来完成。我甚至更进一步，因为我有10个Spinners，并希望从我的数据库中动态设置它们，数据库只保存值而不是文本，因为Spinner实际上每周都在变化，所以值是我的id号。

 // Get the JSON object from db that was saved, 10 spinner values already selected by user
 JSONObject json = new JSONObject(string);
 JSONArray jsonArray = json.getJSONArray("answer");

 // get the current class that Spinner is called in 
 Class<? extends MyActivity> cls = this.getClass();

 // loop through all 10 spinners and set the values with reflection             
 for (int j=1; j< 11; j++) {
      JSONObject obj = jsonArray.getJSONObject(j-1);
      String movieid = obj.getString("id");

      // spinners variable names are s1,s2,s3...
      Field field = cls.getDeclaredField("s"+ j);

      // find the actual position of value in the list     
      int datapos = indexedExactSearch(Arrays.asList(Arrays.asList(this.data).toArray()), "value", movieid) ;
      // find the position in the array adapter
      int pos = this.adapter.getPosition(this.data[datapos]);

      // the position in the array adapter
      ((Spinner)field.get(this)).setSelection(pos);

}

这里是索引搜索，你可以使用几乎任何列表，只要字段是在对象的顶层。

    /**
 * Searches for exact match of the specified class field (key) value within the specified list.
 * This uses a sequential search through each object in the list until a match is found or end
 * of the list reached.  It may be necessary to convert a list of specific objects into generics,
 * ie: LinkedList&ltDevice&gt needs to be passed as a List&ltObject&gt or Object[&nbsp] by using 
 * Arrays.asList(device.toArray(&nbsp)).
 * 
 * @param list - list of objects to search through
 * @param key - the class field containing the value
 * @param value - the value to search for
 * @return index of the list object with an exact match (-1 if not found)
 */
public static <T> int indexedExactSearch(List<Object> list, String key, String value) {
    int low = 0;
    int high = list.size()-1;
    int index = low;
    String val = "";

    while (index <= high) {
        try {
            //Field[] c = list.get(index).getClass().getDeclaredFields();
            val = cast(list.get(index).getClass().getDeclaredField(key).get(list.get(index)) , "NONE");
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (NoSuchFieldException e) {
            e.printStackTrace();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (IllegalAccessException e) {
            e.printStackTrace();
        }

        if (val.equalsIgnoreCase(value))
            return index; // key found

        index = index + 1;
    }

    return -(low + 1);  // key not found return -1
}

可以为所有原语创建的强制转换方法是string和int。

        /**
 *  Base String cast, return the value or default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type String
 */
public static String cast(Object object, String defaultValue) {
    return (object!=null) ? object.toString() : defaultValue;
}


    /**
 *  Base integer cast, return the value or default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type integer
 */
public static int cast(Object object, int defaultValue) { 
    return castImpl(object, defaultValue).intValue();
}

    /**
 *  Base cast, return either the value or the default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type Object
 */
public static Object castImpl(Object object, Object defaultValue) {
    return object!=null ? object : defaultValue;
}

这是我的解决方案

List<Country> list = CountryBO.GetCountries(0);
CountriesAdapter dataAdapter = new CountriesAdapter(this,list);
dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spnCountries.setAdapter(dataAdapter);
spnCountries.setSelection(dataAdapter.getItemIndexById(userProfile.GetCountryId()));

和下面的getItemIndexById

public int getItemIndexById(String id) {
    for (Country item : this.items) {
        if(item.GetId().toString().equals(id.toString())){
            return this.items.indexOf(item);
        }
    }
    return 0;
}

希望这对你有所帮助!

你必须传递你的自定义适配器的位置，如REPEAT[position]。它能正常工作。

基于值设置微调器的一个简单方法是

mySpinner.setSelection(getIndex(mySpinner, myValue));

 //private method of your class
 private int getIndex(Spinner spinner, String myString){
     for (int i=0;i<spinner.getCount();i++){
         if (spinner.getItemAtPosition(i).toString().equalsIgnoreCase(myString)){
             return i;
         }
     }

     return 0;
 } 

复杂代码的方法已经有了，这只是简单得多。