如果你需要在任何旧的适配器上有一个indexOf方法(并且你不知道底层实现)，那么你可以使用这个:

private int indexOf(final Adapter adapter, Object value)
{
    for (int index = 0, count = adapter.getCount(); index < count; ++index)
    {
        if (adapter.getItem(index).equals(value))
        {
            return index;
        }
    }
    return -1;
}

实际上有一种方法可以使用AdapterArray上的索引搜索来获得这个，所有这些都可以通过反射来完成。我甚至更进一步，因为我有10个Spinners，并希望从我的数据库中动态设置它们，数据库只保存值而不是文本，因为Spinner实际上每周都在变化，所以值是我的id号。

 // Get the JSON object from db that was saved, 10 spinner values already selected by user
 JSONObject json = new JSONObject(string);
 JSONArray jsonArray = json.getJSONArray("answer");

 // get the current class that Spinner is called in 
 Class<? extends MyActivity> cls = this.getClass();

 // loop through all 10 spinners and set the values with reflection             
 for (int j=1; j< 11; j++) {
      JSONObject obj = jsonArray.getJSONObject(j-1);
      String movieid = obj.getString("id");

      // spinners variable names are s1,s2,s3...
      Field field = cls.getDeclaredField("s"+ j);

      // find the actual position of value in the list     
      int datapos = indexedExactSearch(Arrays.asList(Arrays.asList(this.data).toArray()), "value", movieid) ;
      // find the position in the array adapter
      int pos = this.adapter.getPosition(this.data[datapos]);

      // the position in the array adapter
      ((Spinner)field.get(this)).setSelection(pos);

}

这里是索引搜索，你可以使用几乎任何列表，只要字段是在对象的顶层。

    /**
 * Searches for exact match of the specified class field (key) value within the specified list.
 * This uses a sequential search through each object in the list until a match is found or end
 * of the list reached.  It may be necessary to convert a list of specific objects into generics,
 * ie: LinkedList&ltDevice&gt needs to be passed as a List&ltObject&gt or Object[&nbsp] by using 
 * Arrays.asList(device.toArray(&nbsp)).
 * 
 * @param list - list of objects to search through
 * @param key - the class field containing the value
 * @param value - the value to search for
 * @return index of the list object with an exact match (-1 if not found)
 */
public static <T> int indexedExactSearch(List<Object> list, String key, String value) {
    int low = 0;
    int high = list.size()-1;
    int index = low;
    String val = "";

    while (index <= high) {
        try {
            //Field[] c = list.get(index).getClass().getDeclaredFields();
            val = cast(list.get(index).getClass().getDeclaredField(key).get(list.get(index)) , "NONE");
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (NoSuchFieldException e) {
            e.printStackTrace();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (IllegalAccessException e) {
            e.printStackTrace();
        }

        if (val.equalsIgnoreCase(value))
            return index; // key found

        index = index + 1;
    }

    return -(low + 1);  // key not found return -1
}

可以为所有原语创建的强制转换方法是string和int。

        /**
 *  Base String cast, return the value or default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type String
 */
public static String cast(Object object, String defaultValue) {
    return (object!=null) ? object.toString() : defaultValue;
}


    /**
 *  Base integer cast, return the value or default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type integer
 */
public static int cast(Object object, int defaultValue) { 
    return castImpl(object, defaultValue).intValue();
}

    /**
 *  Base cast, return either the value or the default
 * @param object - generic Object
 * @param defaultValue - default value to give if Object is null
 * @return - returns type Object
 */
public static Object castImpl(Object object, Object defaultValue) {
    return object!=null ? object : defaultValue;
}

这是我的解决方案

List<Country> list = CountryBO.GetCountries(0);
CountriesAdapter dataAdapter = new CountriesAdapter(this,list);
dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spnCountries.setAdapter(dataAdapter);
spnCountries.setSelection(dataAdapter.getItemIndexById(userProfile.GetCountryId()));

和下面的getItemIndexById

public int getItemIndexById(String id) {
    for (Country item : this.items) {
        if(item.GetId().toString().equals(id.toString())){
            return this.items.indexOf(item);
        }
    }
    return 0;
}

希望这对你有所帮助!

因为我需要一些东西，这也适用于本地化，我想出了以下两种方法:

    private int getArrayPositionForValue(final int arrayResId, final String value) {
        final Resources english = Utils.getLocalizedResources(this, new Locale("en"));
        final List<String> arrayValues = Arrays.asList(english.getStringArray(arrayResId));

        for (int position = 0; position < arrayValues.size(); position++) {
            if (arrayValues.get(position).equalsIgnoreCase(value)) {
                return position;
            }
        }
        Log.w(TAG, "getArrayPosition() --> return 0 (fallback); No index found for value = " + value);
        return 0;
    }

如您所见，我还遇到了arrays.xml和我要比较的值之间的大小写敏感性的额外复杂性。 如果你没有这个，上面的方法可以简化为:

返回arrayValues.indexOf(价值);

静态助手方法

public static Resources getLocalizedResources(Context context, Locale desiredLocale) {
        Configuration conf = context.getResources().getConfiguration();
        conf = new Configuration(conf);
        conf.setLocale(desiredLocale);
        Context localizedContext = context.createConfigurationContext(conf);
        return localizedContext.getResources();
    }

非常简单，只需使用getSelectedItem();

eg :

ArrayAdapter<CharSequence> type=ArrayAdapter.createFromResource(this,R.array.admin_typee,android.R.layout.simple_spinner_dropdown_item);
        type.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
        mainType.setAdapter(type);

String group=mainType.getSelectedItem().toString();

上述方法返回一个字符串值

在上面的R.array。Admin_type是值中的字符串资源文件

只需在值>>字符串中创建一个.xml文件

这是我通过字符串获取索引的简单方法。

private int getIndexByString(Spinner spinner, String string) {
    int index = 0;

    for (int i = 0; i < spinner.getCount(); i++) {
        if (spinner.getItemAtPosition(i).toString().equalsIgnoreCase(string)) {
            index = i;
            break;
        }
    }
    return index;
}