如何将PHP数组转换成这样的格式
Array
(
[0] => 001-1234567
[1] => 1234567
[2] => 12345678
[3] => 12345678
[4] => 12345678
[5] => AP1W3242
[6] => AP7X1234
[7] => AS1234
[8] => MH9Z2324
[9] => MX1234
[10] => TN1A3242
[11] => ZZ1234
)
到下面格式的Javascript数组?
var cities = [
"Aberdeen",
"Ada",
"Adamsville",
"Addyston",
"Adelphi",
"Adena",
"Adrian",
"Akron",
"Albany"
];
我将假设您为PHP和JS提供的两个数组并不相关,它们只是两种语言中数组的示例。显然,你无法将这些字母和数字序列转换成这些城市的名称。
PHP提供了一个将PHP数组转换为Javascript代码的函数:json_encode()。(从技术上讲,它是JSON格式;JSON代表JavaScript对象表示法
像这样使用它:
<script type='text/javascript'>
<?php
$php_array = array('abc','def','ghi');
$js_array = json_encode($php_array);
echo "var javascript_array = ". $js_array . ";\n";
?>
</script>
更多信息请参见我在上面链接的手册页。
请注意,json_encode()仅在PHP 5.2及更高版本中可用,因此如果您使用的是旧版本,则需要使用现有版本——PHP手册页还包括由需要它的人编写的函数注释。(但也就是说,如果你使用的是PHP 5.2以上的版本,你应该尽快升级)
我使用了一个伪php数组
<?php
// instead to create your array like this
$php_array = ["The","quick","brown","fox","jumps","over","the","lazy","dog"];
// do it like this (a simple variable but with separator)
$php_fake_array = "The,quick,brown,fox,jumps,over,the,lazy,dog";
?>
<script type="text/javascript">
// use the same separator for the JS split() function
js_array = '<?php echo $php_fake_array; ?>'.split(',');
</script>
如果你的数组是未知的(已经创建)
<?php
$php_array = file('my_file.txt');
$php_fake_array = "";
// transform your array with concatenate like this
foreach ($php_array as $cell){
// since this array is unknown, use clever separator
$php_fake_array .= $cell.",,,,,";
}
?>
<script type="text/javascript">
// use the same separator for the JS split() function
js_array = '<?php echo $php_fake_array; ?>'.split(',,,,,');
</script>