我怎么写这个回到父2层去找文件?
fs.readFile(__dirname + 'foo.bar');
我怎么写这个回到父2层去找文件?
fs.readFile(__dirname + 'foo.bar');
当前回答
使用路径。加入http://nodejs.org/docs/v0.4.10/api/path.html path.join
var path = require("path"),
fs = require("fs");
fs.readFile(path.join(__dirname, '..', '..', 'foo.bar'));
Path.join()将为你处理开头/结尾斜杠,只是做正确的事情,你不必试图记住什么时候结尾斜杠存在,什么时候不存在。
其他回答
使用路径。加入http://nodejs.org/docs/v0.4.10/api/path.html path.join
var path = require("path"),
fs = require("fs");
fs.readFile(path.join(__dirname, '..', '..', 'foo.bar'));
Path.join()将为你处理开头/结尾斜杠,只是做正确的事情,你不必试图记住什么时候结尾斜杠存在,什么时候不存在。
你可以用不同的方法定位父文件夹下的文件,
const path = require('path');
const fs = require('fs');
// reads foo.bar file which is located in immediate parent folder.
fs.readFile(path.join(__dirname, '..', 'foo.bar');
// Method 1: reads foo.bar file which is located in 2 level back of the current folder.
path.join(__dirname, '..','..');
// Method 2: reads foo.bar file which is located in 2 level back of the current folder.
fs.readFile(path.normalize(__dirname + "/../../foo.bar"));
// Method 3: reads foo.bar file which is located in 2 level back of the current folder.
fs.readFile(__dirname + '/../../foo.bar');
// Method 4: reads foo.bar file which is located in 2 level back of the current folder.
fs.readFile(path.resolve(__dirname, '..', '..','foo.bar'));
如果你不确定父结点在哪里,这个会给你路径;
var path = require('path'),
__parentDir = path.dirname(module.parent.filename);
fs.readFile(__parentDir + '/foo.bar');
如果另一个模块调用你的,你仍然想知道正在运行的主文件的位置,你可以使用@Jason的代码修改:
var path = require('path'),
__parentDir = path.dirname(process.mainModule.filename);
fs.readFile(__parentDir + '/foo.bar');
通过这种方式,您将获得实际运行的脚本的位置。
这很好
path.join(__dirname + '/../client/index.html')
const path = require('path')
const fs = require('fs')
fs.readFile(path.join(__dirname + '/../client/index.html'))