更新:2013年的原始答案现在已经过时，因为一些类已经被替换了。新的方法是使用新的java。时间类。

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("dd MM yyyy");
String inputString1 = "23 01 1997";
String inputString2 = "27 04 1997";

try {
    LocalDateTime date1 = LocalDate.parse(inputString1, dtf);
    LocalDateTime date2 = LocalDate.parse(inputString2, dtf);
    long daysBetween = Duration.between(date1, date2).toDays();
    System.out.println ("Days: " + daysBetween);
} catch (ParseException e) {
    e.printStackTrace();
}

注意，这个解决方案给出的是实际的24小时天数，而不是日历天数。对于后者，请使用

long daysBetween = ChronoUnit.DAYS.between(date1, date2)

原始答案(Java 8已过时)

您正在使用字符串进行一些不必要的转换。有一个SimpleDateFormat类-试试这个:

SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
String inputString1 = "23 01 1997";
String inputString2 = "27 04 1997";

try {
    Date date1 = myFormat.parse(inputString1);
    Date date2 = myFormat.parse(inputString2);
    long diff = date2.getTime() - date1.getTime();
    System.out.println ("Days: " + TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS));
} catch (ParseException e) {
    e.printStackTrace();
}

编辑:由于有一些关于这段代码正确性的讨论:它确实考虑到了闰年。然而，TimeUnit.DAYS.convert函数失去了精度，因为毫秒被转换为天(更多信息请参阅链接文档)。如果这是一个问题，diff也可以手动转换:

float days = (diff / (1000*60*60*24));

注意，这是一个浮点值，不一定是整型。

public static String dateCalculation(String getTime, String dependTime) {
    //Time A is getTime that need to calculate.
    //Time B is static time that Time A depend on B Time and calculate the result.

    Date date = new Date();
    final SimpleDateFormat sdf = new SimpleDateFormat("yyy-MM-dd H:mm:ss");
    Date dateObj = null;
    Date checkDate = null;

    try {
        dateObj = sdf.parse(getTime);
    } catch (ParseException e) {
        e.printStackTrace();
        return "0";
    }
    SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");

    String checkInDate = dateFormat.format(dateObj).toString();
    Date defaultTime = null;
    try {
        defaultTime = dateFormat.parse(dependTime);
        checkDate = dateFormat.parse(checkInDate);
    } catch (ParseException e) {
        e.printStackTrace();
        return "0";
    }

    try {
        if (dateFormat.parse(dateFormat.format(date)).after(defaultTime)) {
            long diff = checkDate.getTime() - defaultTime.getTime();
            Log.e("Difference", "onBindViewHolder: Difference: " + dateObj + " : " + defaultTime + " : " + diff);
            if (diff > 0) {
                long diffSeconds = diff / 1000 % 60;
                long diffMinutes = diff / (60 * 1000) % 60;
                long diffHours = diff / (60 * 60 * 1000);

                return "Late: " + diffHours + " Hour, " + diffMinutes + " Minutes, " + diffSeconds + " Sec";
            } else {
                return "0";
            }
        }
    } catch (ParseException e) {
        e.printStackTrace();
        return "0";
    }
    return "0";
}

最简单的方法:

public static long getDifferenceDays(Date d1, Date d2) {
    long diff = d2.getTime() - d1.getTime();
    return TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS);
}

当夏令时到来时，大多数/所有答案都给我们带来了问题。下面是我们针对所有日期的工作解决方案，不使用JodaTime。它利用日历对象:

public static int daysBetween(Calendar day1, Calendar day2){
    Calendar dayOne = (Calendar) day1.clone(),
            dayTwo = (Calendar) day2.clone();

    if (dayOne.get(Calendar.YEAR) == dayTwo.get(Calendar.YEAR)) {
        return Math.abs(dayOne.get(Calendar.DAY_OF_YEAR) - dayTwo.get(Calendar.DAY_OF_YEAR));
    } else {
        if (dayTwo.get(Calendar.YEAR) > dayOne.get(Calendar.YEAR)) {
            //swap them
            Calendar temp = dayOne;
            dayOne = dayTwo;
            dayTwo = temp;
        }
        int extraDays = 0;

        int dayOneOriginalYearDays = dayOne.get(Calendar.DAY_OF_YEAR);

        while (dayOne.get(Calendar.YEAR) > dayTwo.get(Calendar.YEAR)) {
            dayOne.add(Calendar.YEAR, -1);
            // getActualMaximum() important for leap years
            extraDays += dayOne.getActualMaximum(Calendar.DAY_OF_YEAR);
        }

        return extraDays - dayTwo.get(Calendar.DAY_OF_YEAR) + dayOneOriginalYearDays ;
    }
}

Use:

public int getDifferenceDays(Date d1, Date d2) {
    int daysdiff = 0;
    long diff = d2.getTime() - d1.getTime();
    long diffDays = diff / (24 * 60 * 60 * 1000) + 1;
    daysdiff = (int) diffDays;
    return daysdiff;
}

下面的方法非常适合我:

public int daysBetween(LocalDate later, LocalDate before) {
        SimpleDateFormat myFormat = new SimpleDateFormat("dd MM yyyy");
        int daysBetween = 0;
        try {
            Date dateBefore = myFormat.parse(localDateToString(before));
            Date dateAfter = myFormat.parse(localDateToString(later));
            long difference = dateAfter.getTime() - dateBefore.getTime();
            daysBetween = (int) (difference / (1000 * 60 * 60 * 24));
        } catch (Exception e) {
            e.printStackTrace();
        }
        return daysBetween;
    }

    public String localDateToString(LocalDate date) {
        DateTimeFormatter myFormat = DateTimeFormatter.ofPattern("dd MM yyyy");
        return date.format(myFormat).toString();
    }