如果没有UINavigationController,我似乎无法得到最顶端的UIViewController。以下是我目前所掌握的:

UIApplication.sharedApplication().keyWindow?.rootViewController?.presentViewController(vc, animated: true, completion: nil)

然而,它似乎没有做任何事情。keyWindow和rootViewController似乎也不是nil值,所以可选的链接应该不是问题。

注意:这样做不是一个好主意。它打破了MVC模式。


当前回答

对于swift 4 / 5 +获取topmost viewController

// MARK: UIApplication extensions

extension UIApplication {

    class func getTopViewController(base: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {

        if let nav = base as? UINavigationController {
            return getTopViewController(base: nav.visibleViewController)

        } else if let tab = base as? UITabBarController, let selected = tab.selectedViewController {
            return getTopViewController(base: selected)

        } else if let presented = base?.presentedViewController {
            return getTopViewController(base: presented)
        }
        return base
    }
}

如何使用

if let topVC = UIApplication.getTopViewController() {
   topVC.view.addSubview(forgotPwdView)
}

其他回答

使用这段代码找到top most UIViewController

func getTopViewController() -> UIViewController? {
    var topController: UIViewController? = UIApplication.shared.keyWindow?.rootViewController
    while topController?.presentedViewController != nil {
        topController = topController?.presentedViewController
    }
    return topController
}

基于Dianz的答案,Objective-C版本

- (UIViewController *) topViewController {
   UIViewController *baseVC = UIApplication.sharedApplication.keyWindow.rootViewController;
   if ([baseVC isKindOfClass:[UINavigationController class]]) {
       return ((UINavigationController *)baseVC).visibleViewController;
   }

   if ([baseVC isKindOfClass:[UITabBarController class]]) {
       UIViewController *selectedTVC = ((UITabBarController*)baseVC).selectedViewController;
       if (selectedTVC) {
           return selectedTVC;
       }
   }

   if (baseVC.presentedViewController) {
       return baseVC.presentedViewController;
   }
   return baseVC;
}

在一个非常罕见的情况下,使用自定义segue,最顶层的视图控制器不在导航堆栈或选项卡栏控制器中或被呈现,但它的视图被插入到关键窗口子视图的顶部。

在这种情况下,有必要检查UIApplication.shared.keyWindow.subviews.last == self。视图来确定当前视图控制器是否是最顶端的。

我喜欢@dianz的回答,下面是swift 3的版本。它基本上是一样的,但他少了一个大括号,一些语法/变量/方法名已经改变了。所以它就在这里!

extension UIApplication {
    class func topViewController(base: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {
        if let nav = base as? UINavigationController {
            return topViewController(base: nav.visibleViewController)
        }
        if let tab = base as? UITabBarController {
            if let selected = tab.selectedViewController {
                return topViewController(base: selected)
            }
        }
        if let presented = base?.presentedViewController {
            return topViewController(base: presented)
        }
        return base
    }
}

用法仍然是一样的:

if let topController = UIApplication.topViewController() {
    print("The view controller you're looking at is: \(topController)")
}

在SWIFT 5.2中

你可以使用下面的代码:

import UIKit

extension UIWindow {
    static func getTopViewController() -> UIViewController? {
        if #available(iOS 13, *){
            let keyWindow = UIApplication.shared.windows.filter {$0.isKeyWindow}.first
            
            if var topController = keyWindow?.rootViewController {
                while let presentedViewController = topController.presentedViewController {
                    topController = presentedViewController
                }
                return topController
            }
        } else {
            if var topController = UIApplication.shared.keyWindow?.rootViewController {
                while let presentedViewController = topController.presentedViewController {
                    topController = presentedViewController
                }
                return topController
            }
        }
        return nil
    }
}