我试图使用PyCrypto构建两个函数,它们接受两个参数:消息和密钥,然后加密/解密消息。
我在网上找到了几个链接来帮助我,但每一个都有缺陷:
codekoala的这个使用os。这是PyCrypto不鼓励的。
此外,我给函数的键不能保证具有预期的确切长度。我要怎么做才能做到呢?
还有,有几种模式,推荐哪种模式?我不知道用什么:/
最后,静脉注射到底是什么?我是否可以提供不同的IV来加密和解密,或者这将返回不同的结果?
我试图使用PyCrypto构建两个函数,它们接受两个参数:消息和密钥,然后加密/解密消息。
我在网上找到了几个链接来帮助我,但每一个都有缺陷:
codekoala的这个使用os。这是PyCrypto不鼓励的。
此外,我给函数的键不能保证具有预期的确切长度。我要怎么做才能做到呢?
还有,有几种模式,推荐哪种模式?我不知道用什么:/
最后,静脉注射到底是什么?我是否可以提供不同的IV来加密和解密,或者这将返回不同的结果?
当前回答
你可以通过使用像SHA-1或SHA-256这样的加密哈希函数(不是Python的内置哈希)从任意密码中获得密码短语。Python在其标准库中包含了对这两者的支持:
import hashlib
hashlib.sha1("this is my awesome password").digest() # => a 20 byte string
hashlib.sha256("another awesome password").digest() # => a 32 byte string
您可以使用[:16]或[:24]截断加密哈希值,它将保留其安全性,直到您指定的长度。
其他回答
你可以通过使用像SHA-1或SHA-256这样的加密哈希函数(不是Python的内置哈希)从任意密码中获得密码短语。Python在其标准库中包含了对这两者的支持:
import hashlib
hashlib.sha1("this is my awesome password").digest() # => a 20 byte string
hashlib.sha256("another awesome password").digest() # => a 32 byte string
您可以使用[:16]或[:24]截断加密哈希值,它将保留其安全性,直到您指定的长度。
下面是我的实现,它通过一些修复为我工作。它将密钥和秘密短语的对齐增强为32字节,IV为16字节:
import base64
import hashlib
from Crypto import Random
from Crypto.Cipher import AES
class AESCipher(object):
def __init__(self, key):
self.bs = AES.block_size
self.key = hashlib.sha256(key.encode()).digest()
def encrypt(self, raw):
raw = self._pad(raw)
iv = Random.new().read(AES.block_size)
cipher = AES.new(self.key, AES.MODE_CBC, iv)
return base64.b64encode(iv + cipher.encrypt(raw.encode()))
def decrypt(self, enc):
enc = base64.b64decode(enc)
iv = enc[:AES.block_size]
cipher = AES.new(self.key, AES.MODE_CBC, iv)
return self._unpad(cipher.decrypt(enc[AES.block_size:])).decode('utf-8')
def _pad(self, s):
return s + (self.bs - len(s) % self.bs) * chr(self.bs - len(s) % self.bs)
@staticmethod
def _unpad(s):
return s[:-ord(s[len(s)-1:])]
我用过Crypto和PyCryptodomex库,它非常快…
import base64
import hashlib
from Cryptodome.Cipher import AES as domeAES
from Cryptodome.Random import get_random_bytes
from Crypto import Random
from Crypto.Cipher import AES as cryptoAES
BLOCK_SIZE = AES.block_size
key = "my_secret_key".encode()
__key__ = hashlib.sha256(key).digest()
print(__key__)
def encrypt(raw):
BS = cryptoAES.block_size
pad = lambda s: s + (BS - len(s) % BS) * chr(BS - len(s) % BS)
raw = base64.b64encode(pad(raw).encode('utf8'))
iv = get_random_bytes(cryptoAES.block_size)
cipher = cryptoAES.new(key= __key__, mode= cryptoAES.MODE_CFB,iv= iv)
a= base64.b64encode(iv + cipher.encrypt(raw))
IV = Random.new().read(BLOCK_SIZE)
aes = domeAES.new(__key__, domeAES.MODE_CFB, IV)
b = base64.b64encode(IV + aes.encrypt(a))
return b
def decrypt(enc):
passphrase = __key__
encrypted = base64.b64decode(enc)
IV = encrypted[:BLOCK_SIZE]
aes = domeAES.new(passphrase, domeAES.MODE_CFB, IV)
enc = aes.decrypt(encrypted[BLOCK_SIZE:])
unpad = lambda s: s[:-ord(s[-1:])]
enc = base64.b64decode(enc)
iv = enc[:cryptoAES.block_size]
cipher = cryptoAES.new(__key__, cryptoAES.MODE_CFB, iv)
b= unpad(base64.b64decode(cipher.decrypt(enc[cryptoAES.block_size:])).decode('utf8'))
return b
encrypted_data =encrypt("Hi Steven!!!!!")
print(encrypted_data)
print("=======")
decrypted_data = decrypt(encrypted_data)
print(decrypted_data)
这是另一种观点(主要源自上述解决方案),但是
uses null for padding does not use lambda (never been a fan) tested with python 2.7 and 3.6.5 #!/usr/bin/python2.7 # you'll have to adjust for your setup, e.g., #!/usr/bin/python3 import base64, re from Crypto.Cipher import AES from Crypto import Random from django.conf import settings class AESCipher: """ Usage: aes = AESCipher( settings.SECRET_KEY[:16], 32) encryp_msg = aes.encrypt( 'ppppppppppppppppppppppppppppppppppppppppppppppppppppppp' ) msg = aes.decrypt( encryp_msg ) print("'{}'".format(msg)) """ def __init__(self, key, blk_sz): self.key = key self.blk_sz = blk_sz def encrypt( self, raw ): if raw is None or len(raw) == 0: raise NameError("No value given to encrypt") raw = raw + '\0' * (self.blk_sz - len(raw) % self.blk_sz) raw = raw.encode('utf-8') iv = Random.new().read( AES.block_size ) cipher = AES.new( self.key.encode('utf-8'), AES.MODE_CBC, iv ) return base64.b64encode( iv + cipher.encrypt( raw ) ).decode('utf-8') def decrypt( self, enc ): if enc is None or len(enc) == 0: raise NameError("No value given to decrypt") enc = base64.b64decode(enc) iv = enc[:16] cipher = AES.new(self.key.encode('utf-8'), AES.MODE_CBC, iv ) return re.sub(b'\x00*$', b'', cipher.decrypt( enc[16:])).decode('utf-8')
您可以使用类似PKCS#7填充的方案。您可以使用它来代替前面的函数来填充(进行加密时)和解封(进行解密时)。我将在下面提供完整的源代码。
import base64
import hashlib
from Crypto import Random
from Crypto.Cipher import AES
import pkcs7
class Encryption:
def __init__(self):
pass
def Encrypt(self, PlainText, SecurePassword):
pw_encode = SecurePassword.encode('utf-8')
text_encode = PlainText.encode('utf-8')
key = hashlib.sha256(pw_encode).digest()
iv = Random.new().read(AES.block_size)
cipher = AES.new(key, AES.MODE_CBC, iv)
pad_text = pkcs7.encode(text_encode)
msg = iv + cipher.encrypt(pad_text)
EncodeMsg = base64.b64encode(msg)
return EncodeMsg
def Decrypt(self, Encrypted, SecurePassword):
decodbase64 = base64.b64decode(Encrypted.decode("utf-8"))
pw_encode = SecurePassword.decode('utf-8')
iv = decodbase64[:AES.block_size]
key = hashlib.sha256(pw_encode).digest()
cipher = AES.new(key, AES.MODE_CBC, iv)
msg = cipher.decrypt(decodbase64[AES.block_size:])
pad_text = pkcs7.decode(msg)
decryptedString = pad_text.decode('utf-8')
return decryptedString
import StringIO
import binascii
def decode(text, k=16):
nl = len(text)
val = int(binascii.hexlify(text[-1]), 16)
if val > k:
raise ValueError('Input is not padded or padding is corrupt')
l = nl - val
return text[:l]
def encode(text, k=16):
l = len(text)
output = StringIO.StringIO()
val = k - (l % k)
for _ in xrange(val):
output.write('%02x' % val)
return text + binascii.unhexlify(output.getvalue())