我已经使用Spring RestTemplate有一段时间了,当我试图调试它的请求和响应时,我总是碰壁。我基本上希望看到与打开“verbose”选项时使用curl时相同的东西。例如:

curl -v http://twitter.com/statuses/public_timeline.rss

将显示发送的数据和接收的数据(包括头、cookie等)。

我看了一些相关的帖子,比如: 如何在Spring RestTemplate中记录响应? 但我还没能解决这个问题。

实现这一点的一种方法是实际更改RestTemplate源代码,并在那里添加一些额外的日志记录语句,但我认为这种方法确实是最后的办法。应该有某种方法告诉Spring Web Client/RestTemplate以一种更友好的方式记录所有内容。

我的目标是能够用如下代码做到这一点:

restTemplate.put("http://someurl", objectToPut, urlPathValues);

然后在日志文件或控制台中获得相同类型的调试信息(就像我使用curl获得的一样)。 我相信这对于任何使用Spring RestTemplate并且遇到问题的人来说都是非常有用的。使用curl来调试RestTemplate问题是行不通的(在某些情况下)。


当前回答

正如@MilacH指出的,在实现中有一个错误。如果返回statusCode > 400,则从拦截器抛出IOException,因为没有调用errorHandler。可以忽略异常,然后在处理程序方法中再次捕获异常。

package net.sprd.fulfillment.common;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.http.HttpRequest;
import org.springframework.http.client.ClientHttpRequestExecution;
import org.springframework.http.client.ClientHttpRequestInterceptor;
import org.springframework.http.client.ClientHttpResponse;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import static java.nio.charset.StandardCharsets.UTF_8;

public class LoggingRequestInterceptor implements ClientHttpRequestInterceptor {

    final static Logger log = LoggerFactory.getLogger(LoggingRequestInterceptor.class);

    @SuppressWarnings("HardcodedLineSeparator")
    public static final char LINE_BREAK = '\n';

    @Override
    public ClientHttpResponse intercept(HttpRequest request, byte[] body, ClientHttpRequestExecution execution) throws IOException {
        try {
            traceRequest(request, body);
        } catch (Exception e) {
            log.warn("Exception in LoggingRequestInterceptor while tracing request", e);
        }

        ClientHttpResponse response = execution.execute(request, body);

        try {
            traceResponse(response);
        } catch (IOException e) {
            // ignore the exception here, as it will be handled by the error handler of the restTemplate
            log.warn("Exception in LoggingRequestInterceptor", e);
        }
        return response;
    }

    private void traceRequest(HttpRequest request, byte[] body) {
        log.info("===========================request begin================================================");
        log.info("URI         : {}", request.getURI());
        log.info("Method      : {}", request.getMethod());
        log.info("Headers     : {}", request.getHeaders());
        log.info("Request body: {}", new String(body, UTF_8));
        log.info("==========================request end================================================");
    }

    private void traceResponse(ClientHttpResponse response) throws IOException {
        StringBuilder inputStringBuilder = new StringBuilder();
        try (BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(response.getBody(), UTF_8))) {
            String line = bufferedReader.readLine();
            while (line != null) {
                inputStringBuilder.append(line);
                inputStringBuilder.append(LINE_BREAK);
                line = bufferedReader.readLine();
            }
        }

        log.info("============================response begin==========================================");
        log.info("Status code  : {}", response.getStatusCode());
        log.info("Status text  : {}", response.getStatusText());
        log.info("Headers      : {}", response.getHeaders());
        log.info("Response body: {}", inputStringBuilder);
        log.info("=======================response end=================================================");
    }

}

其他回答

除了在另一个答案中描述的HttpClient日志之外,您还可以引入一个ClientHttpRequestInterceptor,它读取请求体和响应并记录它。如果其他东西也使用HttpClient,或者你想要一个自定义的日志格式,你可能需要这样做。注意:您需要给RestTemplate一个BufferingClientHttpRequestFactory,这样您就可以读取两次响应。

假设RestTemplate配置为使用HttpClient 4。x,你可以在这里阅读HttpClient的日志文档。这些记录器与其他答案中指定的记录器不同。

HttpClient 3的日志配置。X在这里可用。

这可能不是正确的方法,但我认为这是打印请求和响应而不需要在日志中填充太多内容的最简单方法。

通过添加以下2行应用。Properties记录所有请求和响应,第一行记录请求,第二行记录响应。

logging.level.org.springframework.web.client.RestTemplate=DEBUG
logging.level.org.springframework.web.servlet.mvc.method.annotation.HttpEntityMethodProcessor=DEBUG

Related to the response using ClientHttpInterceptor, I found a way of keeping the whole response without Buffering factories. Just store the response body input stream inside byte array using some utils method that will copy that array from body, but important, surround this method with try catch because it will break if response is empty (that is the cause of Resource Access Exception) and in catch just create empty byte array, and than just create anonymous inner class of ClientHttpResponse using that array and other parameters from the original response. Than you can return that new ClientHttpResponse object to the rest template execution chain and you can log response using body byte array that is previously stored. That way you will avoid consuming InputStream in the actual response and you can use Rest Template response as it is. Note, this may be dangerous if your's response is too big

我终于找到了正确的方法。 大部分的解决方案来自 我如何配置Spring和SLF4J以获得日志记录?

看来有两件事需要做:

在log4j中添加以下行。属性:log4j.logger.httpclient.wire=DEBUG 确保spring不会忽略您的日志配置

第二个问题主要发生在使用slf4j的spring环境中(就像我的例子一样)。 因此,当使用slf4j时,请确保发生以下两件事:

There is no commons-logging library in your classpath : this can be done by adding the exclusion descriptors in your pom : <exclusions><exclusion> <groupId>commons-logging</groupId> <artifactId>commons-logging</artifactId> </exclusion> </exclusions> The log4j.properties file is stored somewhere in the classpath where spring can find/see it. If you have problems with this, a last resort solution would be to put the log4j.properties file in the default package (not a good practice but just to see that things work as you expect)