我需要以下输出:-
即将从您的充值账户中扣除27.59欧元的50%。
当我这样做的时候:-
$variablesArray[0] = '€';
$variablesArray[1] = 27.59;
$stringWithVariables = 'About to deduct 50% of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);
但它给了我这个错误vsprintf()[函数。vsprintf]:参数太少…因为它认为50%中的%也可以替换。我怎么逃脱呢?
当前回答
用另一个%转义它:
$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';
其他回答
用另一个%转义它:
$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';
这很简单。
在原来的%前面加上另一个%来转义它。
例如,
$num=23;
printf("%%d of 23 = %d",$num);
输出:
%d of 23 = 23
那么这个呢:
$variablesArray[0] = '%';
$variablesArray[1] = '€';
$variablesArray[2] = 27.59;
$stringWithVariables = 'About to deduct 50%s of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);
只要在变量数组中加上百分号
这对我来说很管用:
sprintf(
'%s (Cash Discount: %%%s, Deferred Discount: %%%s)',
$segment->name,
$segment->discount_cash,
$segment->discount_deferred,
)
// Gold (Cash Discount: %25, Deferred Discount: %20)
对于在你的语言字符串中添加%，你只需要添加两个%%而不是一个
