以下是我基于json_encode()解决方案的主张:

不区分大小写选项 返回计数而不是true 数组中的任何位置(键和值)

如果没有找到word，它仍然返回0 = false。

function in_array_count($needle, $haystack, $caseSensitive = true) {
    if(!$caseSensitive) {
        return substr_count(strtoupper(json_encode($haystack)), strtoupper($needle));
    }
    return substr_count(json_encode($haystack), $needle);
}

希望能有所帮助。

如果你的数组像这样

$array = array(
              array("name" => "Robert", "Age" => "22", "Place" => "TN"), 
              array("name" => "Henry", "Age" => "21", "Place" => "TVL")
         );

使用这个

function in_multiarray($elem, $array,$field)
{
    $top = sizeof($array) - 1;
    $bottom = 0;
    while($bottom <= $top)
    {
        if($array[$bottom][$field] == $elem)
            return true;
        else 
            if(is_array($array[$bottom][$field]))
                if(in_multiarray($elem, ($array[$bottom][$field])))
                    return true;

        $bottom++;
    }        
    return false;
}

示例:echo in_multiarray("22"， $array，"Age");

我正在寻找一个函数，它可以让我在数组(干草堆)中搜索字符串和数组(如针)，所以我通过@jwueller添加到答案中。

这是我的代码:

/**
 * Recursive in_array function
 * Searches recursively for needle in an array (haystack).
 * Works with both strings and arrays as needle.
 * Both needle's and haystack's keys are ignored, only values are compared.
 * Note: if needle is an array, all values in needle have to be found for it to
 * return true. If one value is not found, false is returned.
 * @param  mixed   $needle   The array or string to be found
 * @param  array   $haystack The array to be searched in
 * @param  boolean $strict   Use strict value & type validation (===) or just value
 * @return boolean           True if in array, false if not.
 */
function in_array_r($needle, $haystack, $strict = false) {
     // array wrapper
    if (is_array($needle)) {
        foreach ($needle as $value) {
            if (in_array_r($value, $haystack, $strict) == false) {
                // an array value was not found, stop search, return false
                return false;
            }
        }
        // if the code reaches this point, all values in array have been found
        return true;
    }

    // string handling
    foreach ($haystack as $item) {
        if (($strict ? $item === $needle : $item == $needle)
            || (is_array($item) && in_array_r($needle, $item, $strict))) {
            return true;
        }
    }
    return false;
}

我找到了一个非常简单的解决方法:

如果你的数组是:

Array
(
[details] => Array
    (
        [name] => Dhruv
        [salary] => 5000
    )

[score] => Array
    (
        [ssc] => 70
        [diploma] => 90
        [degree] => 70
    )

)

然后代码将像这样:

 if(in_array("5000",$array['details'])){
             echo "yes found.";
         }
     else {
             echo "no not found";
          }

In_array()在多维数组上不起作用。你可以写一个递归函数来做这件事:

function in_array_r($needle, $haystack, $strict = false) {
    foreach ($haystack as $item) {
        if (($strict ? $item === $needle : $item == $needle) || (is_array($item) && in_array_r($needle, $item, $strict))) {
            return true;
        }
    }

    return false;
}

用法:

$b = array(array("Mac", "NT"), array("Irix", "Linux"));
echo in_array_r("Irix", $b) ? 'found' : 'not found';

这个也可以。

function in_array_r($item , $array){
    return preg_match('/"'.preg_quote($item, '/').'"/i' , json_encode($array));
}

用法:

if(in_array_r($item , $array)){
    // found!
}