请尝试:

in_array("irix",array_keys($b))
in_array("Linux",array_keys($b["irix"])

我不确定是否需要，但这个也许能满足你的要求

这个也可以。

function in_array_r($item , $array){
    return preg_match('/"'.preg_quote($item, '/').'"/i' , json_encode($array));
}

用法:

if(in_array_r($item , $array)){
    // found!
}

我正在寻找一个函数，它可以让我在数组(干草堆)中搜索字符串和数组(如针)，所以我通过@jwueller添加到答案中。

这是我的代码:

/**
 * Recursive in_array function
 * Searches recursively for needle in an array (haystack).
 * Works with both strings and arrays as needle.
 * Both needle's and haystack's keys are ignored, only values are compared.
 * Note: if needle is an array, all values in needle have to be found for it to
 * return true. If one value is not found, false is returned.
 * @param  mixed   $needle   The array or string to be found
 * @param  array   $haystack The array to be searched in
 * @param  boolean $strict   Use strict value & type validation (===) or just value
 * @return boolean           True if in array, false if not.
 */
function in_array_r($needle, $haystack, $strict = false) {
     // array wrapper
    if (is_array($needle)) {
        foreach ($needle as $value) {
            if (in_array_r($value, $haystack, $strict) == false) {
                // an array value was not found, stop search, return false
                return false;
            }
        }
        // if the code reaches this point, all values in array have been found
        return true;
    }

    // string handling
    foreach ($haystack as $item) {
        if (($strict ? $item === $needle : $item == $needle)
            || (is_array($item) && in_array_r($needle, $item, $strict))) {
            return true;
        }
    }
    return false;
}

$userdb = Array
(
    (0) => Array
        (
            ('uid') => '100',
            ('name') => 'Sandra Shush',
            ('url') => 'urlof100'
        ),

    (1) => Array
        (
            ('uid') => '5465',
            ('name') => 'Stefanie Mcmohn',
            ('url') => 'urlof5465'
        ),

    (2) => Array
        (
            ('uid') => '40489',
            ('name') => 'Michael',
            ('url') => 'urlof40489'
        )
);

$url_in_array = in_array('urlof5465', array_column($userdb, 'url'));

if($url_in_array) {
    echo 'value is in multidim array';
}
else {
    echo 'value is not in multidim array';
}

对于多维儿童:in_array('needle'， array_column($arr， 'key'))

对于一维子元素:in_array('needle'， call_user_func_array('array_merge'， $arr))

我找到了一个非常简单的解决方法:

如果你的数组是:

Array
(
[details] => Array
    (
        [name] => Dhruv
        [salary] => 5000
    )

[score] => Array
    (
        [ssc] => 70
        [diploma] => 90
        [degree] => 70
    )

)

然后代码将像这样:

 if(in_array("5000",$array['details'])){
             echo "yes found.";
         }
     else {
             echo "no not found";
          }