如何使用Python在电子邮件中发送HTML内容?我可以发送简单的短信。


当前回答

对于python3,改进@taltman的回答:

使用email.message. emailmessage而不是email.message. message来构造email。 使用电子邮件。Set_content func, assign subtype='html'参数。而不是低级的func set_payload和手动添加头。 使用SMTP。send_message func而不是SMTP。Sendmail func发送电子邮件。 与块一起使用,可自动关闭连接。

from email.message import EmailMessage
from smtplib import SMTP

# construct email
email = EmailMessage()
email['Subject'] = 'foo'
email['From'] = 'sender@test.com'
email['To'] = 'recipient@test.com'
email.set_content('<font color="red">red color text</font>', subtype='html')

# Send the message via local SMTP server.
with smtplib.SMTP('localhost') as s:
    s.login('foo_user', 'bar_password')
    s.send_message(email)

其他回答

对于python3,改进@taltman的回答:

使用email.message. emailmessage而不是email.message. message来构造email。 使用电子邮件。Set_content func, assign subtype='html'参数。而不是低级的func set_payload和手动添加头。 使用SMTP。send_message func而不是SMTP。Sendmail func发送电子邮件。 与块一起使用,可自动关闭连接。

from email.message import EmailMessage
from smtplib import SMTP

# construct email
email = EmailMessage()
email['Subject'] = 'foo'
email['From'] = 'sender@test.com'
email['To'] = 'recipient@test.com'
email.set_content('<font color="red">red color text</font>', subtype='html')

# Send the message via local SMTP server.
with smtplib.SMTP('localhost') as s:
    s.login('foo_user', 'bar_password')
    s.send_message(email)

如果你想要更简单的东西:

from redmail import EmailSender
email = EmailSender(host="smtp.myhost.com", port=1)

email.send(
    subject="Example email",
    sender="me@example.com",
    receivers=["you@example.com"],
    html="<h1>Hi, this is HTML body</h1>"
)

Pip从PyPI安装红色邮件:

pip install redmail

红色邮件几乎有所有你需要从发送电子邮件,它有很多功能,包括:

附件 模板化(使用Jinja) 嵌入式图像 他们的表 以抄送或密送方式发送 Gmail预配置

文档:https://red-mail.readthedocs.io/en/latest/index.html

源代码:https://github.com/Miksus/red-mail

以下是我对AWS使用boto3的回答

    subject = "Hello"
    html = "<b>Hello Consumer</b>"

    client = boto3.client('ses', region_name='us-east-1', aws_access_key_id="your_key",
                      aws_secret_access_key="your_secret")

client.send_email(
    Source='ACME <do-not-reply@acme.com>',
    Destination={'ToAddresses': [email]},
    Message={
        'Subject': {'Data': subject},
        'Body': {
            'Html': {'Data': html}
        }
    }

你可以试试我的邮件模块。

from mailer import Mailer
from mailer import Message

message = Message(From="me@example.com",
                  To="you@example.com")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
   How are you?<br>
   Here is the <a href="http://www.python.org">link</a> you wanted.</p>"""

sender = Mailer('smtp.example.com')
sender.send(message)

下面是示例代码。灵感来自Python Cookbook网站上的代码(找不到确切的链接)

def createhtmlmail (html, text, subject, fromEmail):
    """Create a mime-message that will render HTML in popular
    MUAs, text in better ones"""
    import MimeWriter
    import mimetools
    import cStringIO

    out = cStringIO.StringIO() # output buffer for our message 
    htmlin = cStringIO.StringIO(html)
    txtin = cStringIO.StringIO(text)

    writer = MimeWriter.MimeWriter(out)
    #
    # set up some basic headers... we put subject here
    # because smtplib.sendmail expects it to be in the
    # message body
    #
    writer.addheader("From", fromEmail)
    writer.addheader("Subject", subject)
    writer.addheader("MIME-Version", "1.0")
    #
    # start the multipart section of the message
    # multipart/alternative seems to work better
    # on some MUAs than multipart/mixed
    #
    writer.startmultipartbody("alternative")
    writer.flushheaders()
    #
    # the plain text section
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
    mimetools.encode(txtin, pout, 'quoted-printable')
    txtin.close()
    #
    # start the html subpart of the message
    #
    subpart = writer.nextpart()
    subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
    #
    # returns us a file-ish object we can write to
    #
    pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
    mimetools.encode(htmlin, pout, 'quoted-printable')
    htmlin.close()
    #
    # Now that we're done, close our writer and
    # return the message body
    #
    writer.lastpart()
    msg = out.getvalue()
    out.close()
    print msg
    return msg

if __name__=="__main__":
    import smtplib
    html = 'html version'
    text = 'TEST VERSION'
    subject = "BACKUP REPORT"
    message = createhtmlmail(html, text, subject, 'From Host <sender@host.com>')
    server = smtplib.SMTP("smtp_server_address","smtp_port")
    server.login('username', 'password')
    server.sendmail('sender@host.com', 'target@otherhost.com', message)
    server.quit()