试试这个问题:

    SELECT SUBSTRING(CONVERT(VARCHAR,JOINGDATE,103),7,4)AS
    YEAR,SUBSTRING(CONVERT(VARCHAR,JOINGDATE,100),1,2)AS
MONTH,SUBSTRING(CONVERT(VARCHAR,JOINGDATE,100),4,3)AS DATE FROM EMPLOYEE1

结果:

2014    Ja    1
2015    Ja    1
2014    Ja    1
2015    Ja    1
2012    Ja    1
2010    Ja    1
2015    Ja    1

Sql Server 2012有一个函数，它将根据部件(DATEFROMPARTS)创建日期。对于我们其他人来说，这是我创建的一个db函数，它将确定部件的日期(谢谢@Charles)…

IF EXISTS (SELECT * FROM dbo.sysobjects WHERE id = object_id(N'[dbo].[func_DateFromParts]'))
    DROP FUNCTION [dbo].[func_DateFromParts]
GO

CREATE FUNCTION [dbo].[func_DateFromParts]
(
    @Year INT,
    @Month INT,
    @DayOfMonth INT,
    @Hour INT = 0,  -- based on 24 hour clock (add 12 for PM :)
    @Min INT = 0,
    @Sec INT = 0
)
RETURNS DATETIME
AS
BEGIN

    RETURN DATEADD(second, @Sec, 
            DATEADD(minute, @Min, 
            DATEADD(hour, @Hour,
            DATEADD(day, @DayOfMonth - 1, 
            DATEADD(month, @Month - 1, 
            DATEADD(Year, @Year-1900, 0))))))

END

GO

你可以这样称呼它……

SELECT dbo.func_DateFromParts(2013, 10, 4, 15, 50, DEFAULT)

返回……

2013-10-04 15:50:00.000

试试这个问题:

    SELECT SUBSTRING(CONVERT(VARCHAR,JOINGDATE,103),7,4)AS
    YEAR,SUBSTRING(CONVERT(VARCHAR,JOINGDATE,100),1,2)AS
MONTH,SUBSTRING(CONVERT(VARCHAR,JOINGDATE,100),4,3)AS DATE FROM EMPLOYEE1

结果:

2014    Ja    1
2015    Ja    1
2014    Ja    1
2015    Ja    1
2012    Ja    1
2010    Ja    1
2015    Ja    1

使用显式起点'19000101'更安全、更整洁。

create function dbo.fnDateTime2FromParts(@Year int, @Month int, @Day int, @Hour int, @Minute int, @Second int, @Nanosecond int)
returns datetime2
as
begin
    -- Note! SQL Server 2012 includes datetime2fromparts() function
    declare @output datetime2 = '19000101'
    set @output = dateadd(year      , @Year - 1900  , @output)
    set @output = dateadd(month     , @Month - 1    , @output)
    set @output = dateadd(day       , @Day - 1      , @output)
    set @output = dateadd(hour      , @Hour         , @output)
    set @output = dateadd(minute    , @Minute       , @output)
    set @output = dateadd(second    , @Second       , @output)
    set @output = dateadd(ns        , @Nanosecond   , @output)
    return @output
end

如果你不想把字符串排除在外，这也可以(把它放到一个函数中):

DECLARE @Day int, @Month int, @Year int
SELECT @Day = 1, @Month = 2, @Year = 2008

SELECT DateAdd(dd, @Day-1, DateAdd(mm, @Month -1, DateAdd(yy, @Year - 2000, '20000101')))

我知道OP正在询问SQL 2005的答案，但这个问题已经很老了，所以如果你正在运行SQL 2012或以上版本，你可以使用以下命令:

SELECT DATEADD(DAY, 1, EOMONTH(@somedate, -1))

参考: https://learn.microsoft.com/en-us/sql/t-sql/functions/eomonth-transact-sql?view=sql-server-2017&viewFallbackFrom=sql-server-previousversions