我的布局中有一个EditText和一个Button。

在编辑字段中写入并单击按钮后,我想在触摸键盘外部时隐藏虚拟键盘。我假设这是一段简单的代码,但我在哪里可以找到它的示例?


当前回答

多亏了这个SO答案,我得出了以下结论,在我的情况下,当滚动浏览ViewPager的片段时,它很好地工作。。。

private void hideKeyboard() {   
    // Check if no view has focus:
    View view = this.getCurrentFocus();
    if (view != null) {
        InputMethodManager inputManager = (InputMethodManager) this.getSystemService(Context.INPUT_METHOD_SERVICE);
        inputManager.hideSoftInputFromWindow(view.getWindowToken(), InputMethodManager.HIDE_NOT_ALWAYS);
    }
}

private void showKeyboard() {   
    // Check if no view has focus:
    View view = this.getCurrentFocus();
    if (view != null) {
        InputMethodManager inputManager = (InputMethodManager) this.getSystemService(Context.INPUT_METHOD_SERVICE);
        inputManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT);
    }
}

其他回答

在AndroidManifest.xml中的<activity..>set android:windowSoftInputMode=“stateAlwaysHidden”

如果您的应用程序以API Level 21或更高为目标,则可以使用默认方法:

editTextObj.setShowSoftInputOnFocus(false);

确保在EditText XML标记中设置了以下代码。

<EditText  
    ....
    android:enabled="true"
    android:focusable="true" />

对于那些寻找喷气背包的人来说,写下答案。

val keyboardController = LocalSoftwareKeyboardController.current

//for showing the keyboard
keyboardController?.show()
//for hiding the keyboard
keyboardController?.hide()

这对我有用:

 @Override
 public boolean dispatchTouchEvent(MotionEvent event) {
View v = getCurrentFocus();
boolean ret = super.dispatchTouchEvent(event);

if (v instanceof EditText) {
    View w = getCurrentFocus();
    int scrcoords[] = new int[2];
    w.getLocationOnScreen(scrcoords);
    float x = event.getRawX() + w.getLeft() - scrcoords[0];
    float y = event.getRawY() + w.getTop() - scrcoords[1];

    Log.d("Activity",
            "Touch event " + event.getRawX() + "," + event.getRawY()
                    + " " + x + "," + y + " rect " + w.getLeft() + ","
                    + w.getTop() + "," + w.getRight() + ","
                    + w.getBottom() + " coords " + scrcoords[0] + ","
                    + scrcoords[1]);
    if (event.getAction() == MotionEvent.ACTION_UP
            && (x < w.getLeft() || x >= w.getRight() || y < w.getTop() || y > w
                    .getBottom())) {

        InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
        imm.hideSoftInputFromWindow(getWindow().getCurrentFocus()
                .getWindowToken(), 0);
    }
}
return ret;
}

我已经尝试了所有的解决方案,但没有一个解决方案适合我,所以我找到了我的解决方案:您应该有如下布尔变量:

public static isKeyboardShowing = false;
InputMethodManager inputMethodManager = (InputMethodManager) getActivity()
            .getSystemService(Context.INPUT_METHOD_SERVICE);

在触摸屏事件中,您可以拨打:

@Override
public boolean onTouchEvent(MotionEvent event) {
    if(keyboardShowing==true){
        inputMethodManager.toggleSoftInput(InputMethodManager.RESULT_UNCHANGED_HIDDEN, 0);
        keyboardShowing = false;
    }
    return super.onTouchEvent(event);
}

在EditText中的任何位置:

yourEditText.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            yourClass.keyboardShowing = true;

        }
    });