如果我在PHP中定义一个数组,如(我没有定义它的大小):
$cart = array();
我只是简单地添加元素到它使用下面?
$cart[] = 13;
$cart[] = "foo";
$cart[] = obj;
PHP中的数组不是有一个add方法吗,比如cart.add(13)?
如果我在PHP中定义一个数组,如(我没有定义它的大小):
$cart = array();
我只是简单地添加元素到它使用下面?
$cart[] = 13;
$cart[] = "foo";
$cart[] = obj;
PHP中的数组不是有一个add方法吗,比如cart.add(13)?
当前回答
你可以使用array_push。 它将元素添加到数组的末尾,就像在堆栈中一样。
你也可以这样做:
$cart = array(13, "foo", $obj);
其他回答
array_push和您描述的方法都可以工作。
$cart = array();
$cart[] = 13;
$cart[] = 14;
// etc
//Above is correct. but below one is for further understanding
$cart = array();
for($i=0;$i<=5;$i++){
$cart[] = $i;
}
echo "<pre>";
print_r($cart);
echo "</pre>";
等于:
<?php
$cart = array();
array_push($cart, 13);
array_push($cart, 14);
// Or
$cart = array();
array_push($cart, 13, 14);
?>
记住,这个方法会覆盖第一个数组,所以只在确定的情况下使用!
$arr1 = $arr1 + $arr2;
(见源代码)
$cart = array();
$cart[] = 11;
$cart[] = 15;
// etc
//Above is correct. but below one is for further understanding
$cart = array();
for($i = 0; $i <= 5; $i++){
$cart[] = $i;
//if you write $cart = [$i]; you will only take last $i value as first element in array.
}
echo "<pre>";
print_r($cart);
echo "</pre>";
$products_arr["passenger_details"]=array();
array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));
echo "<pre>";
echo json_encode($products_arr,JSON_PRETTY_PRINT);
echo "</pre>";
//OR
$countries = array();
$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");
$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");
$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");
foreach ($countries as $country){
echo "<pre>";
echo print_r($country);
echo "</pre>";
}
你可以使用array_push。 它将元素添加到数组的末尾,就像在堆栈中一样。
你也可以这样做:
$cart = array(13, "foo", $obj);