//For Mumbai time difference is 5.5 hrs so
city_time_diff=5.5; //change according to your city

let time_now = Date.now();
time_now = time_now + (3600000 * city_time_diff); //Add our city time (in msec);
let new_date = new Date(time_now);
console.log("My city time is: ", new_date);

我在单元测试中遇到了类似的问题(特别是开玩笑地说，单元测试在本地运行以创建快照，然后CI服务器(可能)在不同的时区运行，导致快照比较失败)。我嘲笑我们的约会和一些辅助方法，如下所示:

describe('...', () => {
  let originalDate;

  beforeEach(() => {
    originalDate = Date;
    Date = jest.fn(
      (d) => {
        let newD;
        if (d) {
          newD = (new originalDate(d));
        } else {
          newD = (new originalDate('2017-05-29T10:00:00z'));
        }
        newD.toLocaleString = () => {
          return (new originalDate(newD.valueOf())).toLocaleString("en-US", {timeZone: "America/New_York"});
        };
        newD.toLocaleDateString = () => {
          return (new originalDate(newD.valueOf())).toLocaleDateString("en-US", {timeZone: "America/New_York"});
        };
        newD.toLocaleTimeString = () => {
          return (new originalDate(newD.valueOf())).toLocaleTimeString("en-US", {timeZone: "America/New_York"});
        };
        return newD;
      }
    );
    Date.now = () => { return (Date()); };
  });

  afterEach(() => {
    Date = originalDate;
  });

});

这里有几个工作答案，但不知为何，他们中的很多人似乎让你到字符串，但不是回到一个日期对象，你开始，所以这里是我的简单的非函数采取如何在JS日期更改时区:

var TZ='Australia/Brisbane'; //Target timezone from server
var date = new Date();       //Init this to a time if you don't want current time
date=new Date(Date.parse(date.toLocaleString("en-US", {timeZone: TZ})));
//Just a clarification on what happens
// 1) First new Date() gives you a Date object at current time in the clients browser local timezone
// 2) .toLocaleString takes that time, and returns a string if time in the target timezone
// 3) Date.parse converts that new string to a Unix epoch number
// 4) new Date() converts the Unix epoch into a Date object in the new TimeZone. 
// Now I can use my usual getHours and other Date functions as required.

希望这对其他人有所帮助(如果你找到了下面的答案!)

这应该解决您的问题，请随时提供修复。该方法还将考虑给定日期的夏时制。

dateWithTimeZone = (timeZone, year, month, day, hour, minute, second) => {
  let date = new Date(Date.UTC(year, month, day, hour, minute, second));

  let utcDate = new Date(date.toLocaleString('en-US', { timeZone: "UTC" }));
  let tzDate = new Date(date.toLocaleString('en-US', { timeZone: timeZone }));
  let offset = utcDate.getTime() - tzDate.getTime();

  date.setTime( date.getTime() + offset );

  return date;
};

如何与时区和本地时间一起使用:

dateWithTimeZone("America/Los_Angeles",2019,8,8,0,0,0)

尝试使用npm中的ctoc。 https://www.npmjs.com/package/ctoc_timezone

它有简单的功能来改变时区(大多数时区大约400)和你想要显示的所有自定义格式。

我在运行GCP云函数时遇到了这个问题。当然，它在本地机器上工作，但是在云中运行使得new Date()的操作系统默认值(本地)无关紧要。在我的例子中，来自云的api调用需要东部标准时间，ISO格式(不带“Z”)，偏移量为“-0500”或“-0400”，取决于DST，例如:

2021 - 12 - 01 - t00:00:00.000 - 0500

同样，这不是浏览器格式问题，所以我被迫采用这种格式，以便api调用能够正确工作。

使用@chickens代码作为开始，这是有效的:

var date = new Date(); 
var now_utc =  Date.UTC(date.getUTCFullYear(), date.getUTCMonth(), date.getUTCDate(),
date.getUTCHours(), date.getUTCMinutes(), date.getUTCSeconds());

var dt = new Date(now_utc);

let utcDate = new Date(dt.toLocaleString('en-US', { timeZone: "UTC" }));
let tzDate = new Date(dt.toLocaleString('en-US', { timeZone: "America/New_York" }));
let offset1 = utcDate.getTime() - tzDate.getTime();
let offset2 = offset1/60000;
let o1 = Math.abs(offset2);
console.log(offset2)
var offsetValue1 =  (offset2 < 0 ? "+" : "-") + ("00" + Math.floor(o1 / 60)).slice(-2) + ("00" + (o1 % 60)).slice(-2);
console.log(offsetValue1)
dt.setTime(dt.getTime() - offset1);

console.log(dt.toISOString());
console.log(dt.toISOString().slice(0,-1)+offsetValue1);