如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
当前回答
我需要完成同样的任务,并遇到了这个线程。我最终使用数组“join”使用“_”分隔符创建字符串,然后使用正则表达式:-
1. replace "__" or more with just one "_",
2. replace preceding "_" with nothing "" and similarly
3. replace and ending "_" with nothing ""
…然后使用数组“拆分”生成一个已清理的数组:-
var myArr = new Array("","","a","b","","c","","","","","","","","","e","");
var myStr = "";
myStr = myArr.join("_");
myStr = myStr.replace(new RegExp(/__*/g),"_");
myStr = myStr.replace(new RegExp(/^_/i),"");
myStr = myStr.replace(new RegExp(/_$/i),"");
myArr = myStr.split("_");
alert("myArr=" + myArr.join(","));
…或1行代码:-
var myArr = new Array("","","a","b","","c","","","","","","","","","e","");
myArr = myArr.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");
alert("myArr=" + myArr.join(","));
…或,扩展Array对象:-
Array.prototype.clean = function() {
return this.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");
};
var myArr = new Array("","","a","b","","c","","","","","","","","","e","");
alert("myArr=" + myArr.clean().join(","));
其他回答
这是可行的,我在AppJet中测试了它(你可以复制粘贴代码到它的IDE上,然后按“reload”查看它的工作情况,不需要创建帐户)
/* appjet:version 0.1 */
function Joes_remove(someArray) {
var newArray = [];
var element;
for( element in someArray){
if(someArray[element]!=undefined ) {
newArray.push(someArray[element]);
}
}
return newArray;
}
var myArray2 = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
print("Original array:", myArray2);
print("Clenased array:", Joes_remove(myArray2) );
/*
Returns: [1,2,3,3,0,4,4,5,6]
*/
下面是一个使用变量行为和ES2015胖箭头表达式的示例:
Array.prototype.clean = function() {
var args = [].slice.call(arguments);
return this.filter(item => args.indexOf(item) === -1);
};
// Usage
var arr = ["", undefined, 3, "yes", undefined, undefined, ""];
arr.clean(undefined); // ["", 3, "yes", ""];
arr.clean(undefined, ""); // [3, "yes"];
var data = [null, 1,2,3];
var r = data.filter(function(i){ return i != null; })
console.log(r)
[1,2,3]
这只会删除空值,而不是虚假值,我认为这是更可取的。
也可以选择删除空值。
这种方法应该比使用拼接快得多。
function cleanArray(a, removeNull) {
var i, l, temp = [];
l = a.length;
if (removeNull) {
for (i = 0; i < l; i++) {
if (a[i] !== undefined && a[i] !== null) {
temp.push(a[i]);
}
}
} else {
for (i = 0; i < l; i++) {
if (a[i] !== undefined) {
temp.push(a[i]);
}
}
}
a.length = 0;
l = temp.length;
for (i = 0; i < l; i++) {
a[i] = temp[i];
}
temp.length = 0;
return a;
}
var myArray = [1, 2, , 3, , 3, , , 0, , null, false, , NaN, '', 4, , 4, , 5, , 6, , , , ];
cleanArray(myArray);
myArray;
“误用”。。。在(对象成员)循环中。=>循环体中仅显示真实值。
// --- Example ----------
var field = [];
field[0] = 'One';
field[1] = 1;
field[3] = true;
field[5] = 43.68;
field[7] = 'theLastElement';
// --- Example ----------
var originalLength;
// Store the length of the array.
originalLength = field.length;
for (var i in field) {
// Attach the truthy values upon the end of the array.
field.push(field[i]);
}
// Delete the original range within the array so that
// only the new elements are preserved.
field.splice(0, originalLength);