在我的节点应用程序中,我需要删除一个目录,其中有一些文件,但fs。Rmdir只适用于空目录。我该怎么做呢?


当前回答

截至节点v14(2020年10月),fs模块有fs。rm和rs.rmSync支持递归非空目录解链接:

https://nodejs.org/docs/latest-v14.x/api/fs.html#fs_fs_rm_path_options_callback

所以你现在可以这样做:

const fs = require('fs');
fs.rm('/path/to/delete', { recursive: true }, () => console.log('done'));

or:

const fs = require('fs');
fs.rmSync('/path/to/delete', { recursive: true });
console.log('done');

其他回答

2020的答案

如果你想在npm脚本中完成它,如果你使用npx命令,你不需要预先安装任何第三方包

例如,如果你想在运行npm run clean时删除dist和.cache文件夹,那么只需将此命令添加到package.json中

{
  "scripts": {
    "clean": "npx rimraf dist .cache"
  }
}

它适用于任何操作系统

方法删除非空目录

rmdir(path,{recursive:true,force:true}
rm(path,{recursive:true,force:true}

将工作

代码片段:

const fsp = require("fs/promises");

deleteDirRecursively("./b");
removeRecursively("./BCD/b+");

async function deleteDirRecursively(dirPath) {
  try {
    // fsPromises.rmdir() on a file (not a directory) results in the promise being rejected
    // with an ENOENT error on Windows and an ENOTDIR error on POSIX.
    // To get a behavior similar to the rm -rf Unix command,
    // use fsPromises.rm() with options { recursive: true, force: true }.
    //will not thorw error if dir is empty
    //will thow error if dir is not present
    await fsp.rmdir(dirPath, { recursive: true, force: true });
    console.log(dirPath, "deleted successfully");
  } catch (err) {
    console.log(err);
  }

async function removeRecursively(path) {
  try {
    //has ability to remove both file and dir
    //can delete dir recursively and forcefully
    //will delete an empty dir.
    //will remove all the contents of a dir.
    // the only difference between rmdir and rm is that rmdir can only delete dir's
    await fsp.rm(path, { recursive: true, force: true });
    console.log(path, "deleted successfully");
  } catch (err) {
    console.log(err);
  }
}

超速度和防故障

你可以使用lignator包(https://www.npmjs.com/package/lignator),它比任何异步代码(例如rimraf)都快,而且更防故障(特别是在Windows中,文件删除不是瞬时的,文件可能被其他进程锁定)。

4,36 GB的数据,28042个文件,4217个文件夹在Windows上在15秒内删除,而旧硬盘上的rimraf只有60秒。

const lignator = require('lignator');

lignator.remove('./build/');

有一个模块叫做rimraf (https://npmjs.org/package/rimraf)。它提供了与rm -Rf相同的功能

异步用法:

var rimraf = require("rimraf");
rimraf("/some/directory", function () { console.log("done"); });

同步用法:

rimraf.sync("/some/directory");

如果你更喜欢async/await,你可以使用fs/promises API。

const fs = require('fs/promises');

const removeDir = async (dirPath) => {
  await fs.rm(dirPath, {recursive: true});
}

如果您知道文件夹中单个文件的路径,并希望删除包含该文件的文件夹。

const fs = require('fs/promises');
const path = require('path');

const removeDir = async (filePath) => {
  const { dir } = path.parse(filePath);
  await fs.rm(dir, { recursive: true });
}