三个用于访问和操作日期和时间的库，即datetime、arrow和pendulum，都使这些项在命名元组中可用，其元素可以通过名称或索引访问。此外，物品以完全相同的方式访问。(我想如果我更聪明的话，我就不会感到惊讶了。)

>>> YEARS, MONTHS, DAYS, HOURS, MINUTES = range(5)
>>> import datetime
>>> import arrow
>>> import pendulum
>>> [datetime.datetime.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
>>> [arrow.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
>>> [pendulum.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 16]

下面是一行代码，它的最大字符为80。

import time
year, month, day, hour, min = map(int, time.strftime("%Y %m %d %H %M").split())

tzaman的datetime回答要干净得多，但你可以用原始的python time模块来做:

import time
strings = time.strftime("%Y,%m,%d,%H,%M,%S")
t = strings.split(',')
numbers = [ int(x) for x in t ]
print numbers

输出:

[2016, 3, 11, 8, 29, 47]

对于python 3

import datetime
now = datetime.datetime.now()
print(now.year, now.month, now.day, now.hour, now.minute, now.second)

让我们看看如何从当前时间中获取并打印日、月、年:

import datetime

now = datetime.datetime.now()
year = '{:02d}'.format(now.year)
month = '{:02d}'.format(now.month)
day = '{:02d}'.format(now.day)
hour = '{:02d}'.format(now.hour)
minute = '{:02d}'.format(now.minute)
day_month_year = '{}-{}-{}'.format(year, month, day)

print('day_month_year: ' + day_month_year)

结果:

day_month_year: 2019-03-26

datetime模块是你的朋友:

import datetime
now = datetime.datetime.now()
print(now.year, now.month, now.day, now.hour, now.minute, now.second)
# 2015 5 6 8 53 40

您不需要单独的变量，返回的datetime对象上的属性具有您所需要的一切。