我想在Python中获取当前时间,并将它们分配到年、月、日、小时、分钟等变量中。在Python 2.7中如何做到这一点?


当前回答

tzaman的datetime回答要干净得多,但你可以用原始的python time模块来做:

import time
strings = time.strftime("%Y,%m,%d,%H,%M,%S")
t = strings.split(',')
numbers = [ int(x) for x in t ]
print numbers

输出:

[2016, 3, 11, 8, 29, 47]

其他回答

这是一个老问题,但我想到了一个解决方案,我认为其他人可能会喜欢。

def get_current_datetime_as_dict():
n = datetime.now()
t = n.timetuple()
field_names = ["year",
               "month",
               "day",
               "hour",
               "min",
               "sec",
               "weekday",
               "md",
               "yd"]
return dict(zip(field_names, t))

Timetuple()可以与另一个数组压缩,该数组创建有标签的元组。将其转换为字典,生成的产品可以使用get_current_datetime_as_dict()['year']使用。

这比这里的其他一些解决方案有更多的开销,但我发现能够在代码中为了清晰起见访问命名值是非常好的。

对于python 3

import datetime
now = datetime.datetime.now()
print(now.year, now.month, now.day, now.hour, now.minute, now.second)

让我们看看如何从当前时间中获取并打印日、月、年:

import datetime

now = datetime.datetime.now()
year = '{:02d}'.format(now.year)
month = '{:02d}'.format(now.month)
day = '{:02d}'.format(now.day)
hour = '{:02d}'.format(now.hour)
minute = '{:02d}'.format(now.minute)
day_month_year = '{}-{}-{}'.format(year, month, day)

print('day_month_year: ' + day_month_year)

结果:

day_month_year: 2019-03-26

三个用于访问和操作日期和时间的库,即datetime、arrow和pendulum,都使这些项在命名元组中可用,其元素可以通过名称或索引访问。此外,物品以完全相同的方式访问。(我想如果我更聪明的话,我就不会感到惊讶了。)

>>> YEARS, MONTHS, DAYS, HOURS, MINUTES = range(5)
>>> import datetime
>>> import arrow
>>> import pendulum
>>> [datetime.datetime.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
>>> [arrow.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 15]
>>> [pendulum.now().timetuple()[i] for i in [YEARS, MONTHS, DAYS, HOURS, MINUTES]]
[2017, 6, 16, 19, 16]

您可以使用gmtime

from time import gmtime

detailed_time = gmtime() 
#returns a struct_time object for current time

year = detailed_time.tm_year
month = detailed_time.tm_mon
day = detailed_time.tm_mday
hour = detailed_time.tm_hour
minute = detailed_time.tm_min

注意:时间戳可以传递给gmtime,默认为当前时间 由时间返回()

eg.
gmtime(1521174681)

看到struct_time