我有一个包含对象数组的对象。
obj = {};
obj.arr = new Array();
obj.arr.push({place:"here",name:"stuff"});
obj.arr.push({place:"there",name:"morestuff"});
obj.arr.push({place:"there",name:"morestuff"});
我想知道从数组中删除重复对象的最佳方法是什么。例如,obj.arr将变成。。。
{place:"here",name:"stuff"},
{place:"there",name:"morestuff"}
使用ES6“reduce”和“find”数组助手方法的简单解决方案
工作效率高,非常好!
"use strict";
var things = new Object();
things.thing = new Array();
things.thing.push({
place: "here",
name: "stuff"
});
things.thing.push({
place: "there",
name: "morestuff"
});
things.thing.push({
place: "there",
name: "morestuff"
});
// the logic is here
function removeDup(something) {
return something.thing.reduce(function (prev, ele) {
var found = prev.find(function (fele) {
return ele.place === fele.place && ele.name === fele.name;
});
if (!found) {
prev.push(ele);
}
return prev;
}, []);
}
console.log(removeDup(things));
这里是ES6的解决方案,您只想保留最后一项。该解决方案功能强大,符合Airbnb风格。
const things = {
thing: [
{ place: 'here', name: 'stuff' },
{ place: 'there', name: 'morestuff1' },
{ place: 'there', name: 'morestuff2' },
],
};
const removeDuplicates = (array, key) => {
return array.reduce((arr, item) => {
const removed = arr.filter(i => i[key] !== item[key]);
return [...removed, item];
}, []);
};
console.log(removeDuplicates(things.thing, 'place'));
// > [{ place: 'here', name: 'stuff' }, { place: 'there', name: 'morestuff2' }]
const uniqueElements = (arr, fn) => arr.reduce((acc, v) => {
if (!acc.some(x => fn(v, x))) { acc.push(v); }
return acc;
}, []);
const stuff = [
{place:"here",name:"stuff"},
{place:"there",name:"morestuff"},
{place:"there",name:"morestuff"},
];
const unique = uniqueElements(stuff, (a,b) => a.place === b.place && a.name === b.name );
//console.log( unique );
[{
"place": "here",
"name": "stuff"
},
{
"place": "there",
"name": "morestuff"
}]