我有一个包含对象数组的对象。

obj = {};

obj.arr = new Array();

obj.arr.push({place:"here",name:"stuff"});
obj.arr.push({place:"there",name:"morestuff"});
obj.arr.push({place:"there",name:"morestuff"});

我想知道从数组中删除重复对象的最佳方法是什么。例如,obj.arr将变成。。。

{place:"here",name:"stuff"},
{place:"there",name:"morestuff"}

当前回答

es6魔术在一条线上。。。在那时候可读!

// returns the union of two arrays where duplicate objects with the same 'prop' are removed
const removeDuplicatesWith = (a, b, prop) => {
  a.filter(x => !b.find(y => x[prop] === y[prop]));
};

其他回答

带有Map的一行程序(高性能,不保留顺序)

在数组arr中查找唯一id。

const arrUniq = [...new Map(arr.map(v => [v.id, v])).values()]

如果订单很重要,请检查带过滤器的解决方案:带过滤器的方案


由数组arr中的多个财产(位置和名称)唯一

const arrUniq = [...new Map(arr.map(v => [JSON.stringify([v.place,v.name]), v])).values()]

由数组arr中的所有财产唯一

const arrUniq = [...new Map(arr.map(v => [JSON.stringify(v), v])).values()]

保留数组arr中的第一次出现

const arrUniq = [...new Map(arr.slice().reverse().map(v => [v.id, v])).values()].reverse()

可以将Object.values()与Array.prototype.reduce()结合使用:

const things=新对象();things.thing=新数组();thing.thing.push({place:“here”,name:“stuff”});things.thing.push({place:“there”,name:“morestuff”});things.thing.push({place:“there”,name:“morestuff”});constresult=Object.values(things.thing.reduce((a,c)=>(a[`${c.place}${c.name}`]=c,a),{}));console.log(结果);.作为控制台包装{最大高度:100%!重要;顶部:0;}

ES6一个衬垫在这里

设arr=[{id:1,名称:“sravan ganji”},{id:2,name:“pinky”},{id:4,名称:“mammu”},{id:3,名称:“avy”},{id:3,名称:“rashni”},];console.log(Object.values(arr.reduce((acc,cur)=>Object.assign(acc、{[cur.id]:cur}),{}

您也可以使用地图:

const dedupThings = Array.from(things.thing.reduce((m, t) => m.set(t.place, t), new Map()).values());

完整样本:

const things = new Object();

things.thing = new Array();

things.thing.push({place:"here",name:"stuff"});
things.thing.push({place:"there",name:"morestuff"});
things.thing.push({place:"there",name:"morestuff"});

const dedupThings = Array.from(things.thing.reduce((m, t) => m.set(t.place, t), new Map()).values());

console.log(JSON.stringify(dedupThings, null, 4));

结果:

[
    {
        "place": "here",
        "name": "stuff"
    },
    {
        "place": "there",
        "name": "morestuff"
    }
]

这个呢

function dedupe(arr, compFn){
    let res = [];
    if (!compFn) compFn = (a, b) => { return a === b };
    arr.map(a => {if(!res.find(b => compFn(a, b))) res.push(a)});
    return res;
}