我试过类似的方法，但不管用。
class PostSerializer(serializers.ModelSerializer):
class Meta:
model = Post
def save(self):
user = self.context['request.user']
title = self.validated_data['title']
article = self.validated_data['article']
我需要一种能够访问请求的方法。用户从我的Serializer类。
当前回答
你不能直接访问self.context.user。首先，你必须在序列化器中传递上下文。以下步骤如下:
Some where inside your api view: class ApiView(views.APIView): def get(self, request): items = Item.object.all() return Response( ItemSerializer( items, many=True, context=request # <- this line (pass the request as context) ).data ) Then inside your serializer: class ItemSerializer(serializers.ModelSerializer): current_user = serializers.SerializerMethodField('get_user') class Meta: model = Item fields = ( 'id', 'name', 'current_user', ) def get_user(self, obj): request = self.context return request.user # <- here is current your user
其他回答
在序列化器中获取当前用户的最好方法是这样的。
AnySerializer(data={
'example_id': id
}, context={'request': request})
这必须在views.py中编写 现在在serializer。py部分
user = serializers.CharField(default=serializers.CurrentUserDefault())
这个“用户”必须是你在模型中的字段，就像任何关系一样，比如外键
在GET方法中:
添加context={'user':请求。View类中的user}:
class ContentView(generics.ListAPIView):
def get(self, request, format=None):
content_list = <Respective-Model>.objects.all()
serializer = ContentSerializer(content_list, many=True,
context={'user': request.user})
在Serializer类方法中获取:
class ContentSerializer(serializers.ModelSerializer):
rate = serializers.SerializerMethodField()
def get_rate(self, instance):
user = self.context.get("user")
...
...
POST方法:
遵循其他答案(例如Max的答案)。
DRF SRZ页面
在我的项目中，我的用户字段是只读的，所以我需要得到 创建方法中的用户id
class CommentSerializer(serializers.ModelSerializer):
comment_replis = RecursiveField(many=True, read_only=True)
user = UserSerializer(read_only=True)
class Meta:
model = PostComment
fields = ('_all_')
def create(self, validated_data):
post = PostComment.objects.create(**validated_data)
print(self._dict_['_kwargs']['data']["user"]) # geting #request.data["user"] # <- mian code
post.user=User.objects.get(id=self._dict_['_kwargs']['data']["user"])
return post
在我的项目中，我尝试了这种方法，并成功了
你不能直接访问self.context.user。首先，你必须在序列化器中传递上下文。以下步骤如下:
Some where inside your api view: class ApiView(views.APIView): def get(self, request): items = Item.object.all() return Response( ItemSerializer( items, many=True, context=request # <- this line (pass the request as context) ).data ) Then inside your serializer: class ItemSerializer(serializers.ModelSerializer): current_user = serializers.SerializerMethodField('get_user') class Meta: model = Item fields = ( 'id', 'name', 'current_user', ) def get_user(self, obj): request = self.context return request.user # <- here is current your user
在视图中使用以下代码:
serializer = UploadFilesSerializer(data=request.data, context={'request': request})
然后在序列化器中使用这个访问它:
user = self.context.get("request").user
