如何获取请求。Django-Rest-Framework序列化器中的用户?

我试过类似的方法，但不管用。

class PostSerializer(serializers.ModelSerializer):

    class Meta:
        model = Post

    def save(self):
        user = self.context['request.user']
        title = self.validated_data['title']
        article = self.validated_data['article']

我需要一种能够访问请求的方法。用户从我的Serializer类。

当前回答

在GET方法中:

添加context={'user':请求。View类中的user}:

class ContentView(generics.ListAPIView):
    def get(self, request, format=None):
        content_list = <Respective-Model>.objects.all()
        serializer = ContentSerializer(content_list, many=True, 
                                       context={'user': request.user})

在Serializer类方法中获取:

class ContentSerializer(serializers.ModelSerializer):
    rate = serializers.SerializerMethodField()

    def get_rate(self, instance):
        user = self.context.get("user") 
        ...  
    ...

POST方法:

遵循其他答案(例如Max的答案)。

2022-04-23 18:52:04

其他回答

你不能直接访问self.context.user。首先，你必须在序列化器中传递上下文。以下步骤如下:

Some where inside your api view: class ApiView(views.APIView): def get(self, request): items = Item.object.all() return Response( ItemSerializer( items, many=True, context=request # <- this line (pass the request as context) ).data ) Then inside your serializer: class ItemSerializer(serializers.ModelSerializer): current_user = serializers.SerializerMethodField('get_user') class Meta: model = Item fields = ( 'id', 'name', 'current_user', ) def get_user(self, obj): request = self.context return request.user # <- here is current your user

2021-03-27 22:53:12

对于那些使用Django ORM并将用户添加为外键的人，他们将需要包括用户的整个对象，而我只能在create方法中做到这一点，并删除必选字段:

class PostSerializer(serializers.ModelSerializer):

def create(self, validated_data):
    
    request = self.context.get("request")
    
    post = Post()
    post.title = validated_data['title']
    post.article = validated_data['article']
    post.user = request.user

    post.save()

    return post

class Meta:
    model = Post
    fields = '__all__'
    extra_kwargs = {'user': {'required': False}}

2020-11-24 17:01:53

DRF SRZ页面

在我的项目中，我的用户字段是只读的，所以我需要得到创建方法中的用户id

class CommentSerializer(serializers.ModelSerializer):
    comment_replis = RecursiveField(many=True, read_only=True)
    user = UserSerializer(read_only=True)

    class Meta:
        model = PostComment
        fields = ('_all_')

    def create(self, validated_data):
 


        post = PostComment.objects.create(**validated_data)   
        print(self._dict_['_kwargs']['data']["user"]) # geting #request.data["user"] #  <- mian code
        post.user=User.objects.get(id=self._dict_['_kwargs']['data']["user"])
        return post

在我的项目中，我尝试了这种方法，并成功了

2022-02-09 19:30:32

如果你正在使用通用视图，并且你想在保存实例时注入当前用户，那么你可以覆盖perform_create或perform_update:

def perform_create(self, serializer):
    serializer.save(user=self.request.user)

User将作为一个属性添加到kwargs中，您可以通过serializer中的validated_data访问它

user = validated_data['user']

2020-11-10 19:04:45