面试中有一些“很吸引人”的问题，比如为什么你的成绩和别人一样!如果执行下面的代码段。

String s1 = "testString";
String s2 = "testString";
if(s1 == s2) System.out.println("equals!");

如果你想比较字符串，你应该使用equals()。上面的代码将输出等于，因为testString已经被编译器为你进行了存储。您可以自己使用intern方法实习字符串，如前面的答案....所示

通过使用堆对象引用，如果我们想要对应SCP对象引用，我们应该使用intern()方法。

例子:

class InternDemo
{
public static void main(String[] args)
{
String s1=new String("smith");
String s2=s1.intern();
String s3="smith";
System.out.println(s2==s3);//true
}
}

实习生流程图

面试中有一些“很吸引人”的问题，比如为什么你的成绩和别人一样!如果执行下面的代码段。

String s1 = "testString";
String s2 = "testString";
if(s1 == s2) System.out.println("equals!");

如果你想比较字符串，你应该使用equals()。上面的代码将输出等于，因为testString已经被编译器为你进行了存储。您可以自己使用intern方法实习字符串，如前面的答案....所示

字符串实习是编译器的一种优化技术。如果在一个编译单元中有两个相同的字符串字面值，则生成的代码将确保在程序集中为该字面值(双引号括起来的字符)的所有实例只创建一个字符串对象。

我来自c#背景，所以我可以通过给出一个例子来解释:

object obj = "Int32";
string str1 = "Int32";
string str2 = typeof(int).Name;

以下比较的输出:

Console.WriteLine(obj == str1); // true
Console.WriteLine(str1 == str2); // true    
Console.WriteLine(obj == str2); // false !?

注1:对象通过引用进行比较。

注2:typeof (int)。名称由反射方法求值，因此在编译时不会求值。这里这些比较是在编译时进行的。

结果分析: 1) true，因为它们都包含相同的文字，所以生成的代码将只有一个引用“Int32”的对象。见注1。

2) true，因为两个值的内容都是相同的。

3) FALSE，因为str2和obj没有相同的字面值。见注2。

Java interning() method basically makes sure that if String object is present in SCP, If yes then it returns that object and if not then creates that objects in SCP and return its references

for eg: String s1=new String("abc");
        String s2="abc";
        String s3="abc";

s1==s2// false, because 1 object of s1 is stored in heap and other in scp(but this objects doesn't have explicit reference) and s2 in scp
s2==s3// true

now if we do intern on s1
s1=s1.intern() 

//JVM checks if there is any string in the pool with value “abc” is present? Since there is a string object in the pool with value “abc”, its reference is returned.
Notice that we are calling s1 = s1.intern(), so the s1 is now referring to the string pool object having value “abc”.
At this point, all the three string objects are referring to the same object in the string pool. Hence s1==s2 is returning true now.

因为字符串是对象，而且Java中的所有对象总是只存储在堆空间中，所以所有字符串都存储在堆空间中。然而，Java将不使用new关键字创建的字符串保存在堆空间的一个特殊区域中，这个区域称为“字符串池”。Java将使用new关键字创建的字符串保存在常规堆空间中。

The purpose of the string pool is to maintain a set of unique strings. Any time you create a new string without using the new keyword, Java checks whether the same string already exists in the string pool. If it does, Java returns a reference to the same String object and if it does not, Java creates a new String object in the string pool and returns its reference. So, for example, if you use the string "hello" twice in your code as shown below, you will get a reference to the same string. We can actually test this theory out by comparing two different reference variables using the == operator as shown in the following code:

String str1 = "hello";
String str2 = "hello";
System.out.println(str1 == str2); //prints true

String str3 = new String("hello");
String str4 = new String("hello");

System.out.println(str1 == str3); //prints false
System.out.println(str3 == str4); //prints false 

== operator is simply checks whether two references point to the same object or not and returns true if they do. In the above code, str2 gets the reference to the same String object which was created earlier. However, str3 and str4 get references to two entirely different String objects. That is why str1 == str2 returns true but str1 == str3 and str3 == str4 return false . In fact, when you do new String("hello"); two String objects are created instead of just one if this is the first time the string "hello" is used in the anywhere in program - one in the string pool because of the use of a quoted string, and one in the regular heap space because of the use of new keyword.

字符串池是Java通过避免创建包含相同值的多个String对象来节省程序内存的方法。可以使用string的intern方法从字符串池中获取使用new关键字创建的字符串的字符串。它被称为字符串对象的“实习”。例如,

String str1 = "hello";
String str2 = new String("hello");
String str3 = str2.intern(); //get an interned string obj

System.out.println(str1 == str2); //prints false
System.out.println(str1 == str3); //prints true

OCP Java SE 11程序员，Deshmukh