我只是找到了一个优雅的方法:

Convert.ChangeType("2020-12-31", typeof(DateTime));

Convert.ChangeType("2020/12/31", typeof(DateTime));

Convert.ChangeType("2020-01-01 16:00:30", typeof(DateTime));

Convert.ChangeType("2020/12/31 16:00:30", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("en-GB"));

Convert.ChangeType("11/شعبان/1437", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("ar-SA"));

Convert.ChangeType("2020-02-11T16:54:51.466+03:00", typeof(DateTime)); // format: "yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffzzz"

使用DateTime.Parse(字符串):

DateTime dateTime = DateTime.Parse(dateTimeStr);

由于您处理的是基于24小时的时间，并且您使用逗号分隔秒分数，因此我建议您指定一个自定义格式:

DateTime myDate = DateTime.ParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff",
                                       System.Globalization.CultureInfo.InvariantCulture);

String now = DateTime.Now.ToString("YYYY-MM-DD HH:MI:SS");//make it datetime
DateTime.Parse(now);

这个给了你

2019-08-17 11:14:49.000

这招对我很管用:

CultureInfo provider = CultureInfo.InvariantCulture;
DateTime dt = DateTime.ParseExact("2009-05-08 14:40:52,531","yyyy-MM-dd HH:mm:ss,fff", provider);

将此代码放入静态类>公共静态类ClassName{}

public static DateTime ToDateTime(this string datetime, char dateSpliter = '-', char timeSpliter = ':', char millisecondSpliter = ',')
{
   try
   {
      datetime = datetime.Trim();
      datetime = datetime.Replace("  ", " ");
      string[] body = datetime.Split(' ');
      string[] date = body[0].Split(dateSpliter);
      int year = date[0].ToInt();
      int month = date[1].ToInt();
      int day = date[2].ToInt();
      int hour = 0, minute = 0, second = 0, millisecond = 0;
      if (body.Length == 2)
      {
         string[] tpart = body[1].Split(millisecondSpliter);
         string[] time = tpart[0].Split(timeSpliter);
         hour = time[0].ToInt();
         minute = time[1].ToInt();
         if (time.Length == 3) second = time[2].ToInt();
         if (tpart.Length == 2) millisecond = tpart[1].ToInt();
      }
      return new DateTime(year, month, day, hour, minute, second, millisecond);
   }
   catch
   {
      return new DateTime();
   }
}

这样，你就可以使用

string datetime = "2009-05-08 14:40:52,531";
DateTime dt0 = datetime.TToDateTime();

DateTime dt1 = "2009-05-08 14:40:52,531".ToDateTime();
DateTime dt5 = "2009-05-08".ToDateTime();
DateTime dt2 = "2009/05/08 14:40:52".ToDateTime('/');
DateTime dt3 = "2009/05/08 14.40".ToDateTime('/', '.');
DateTime dt4 = "2009-05-08 14:40-531".ToDateTime('-', ':', '-');