我有一个接口在TypeScript。

interface Employee{
    id: number;
    name: string;
    salary: number;
}

我想把工资作为一个可空字段(就像我们可以在c#中做的那样)。这可能在TypeScript中实现吗?


当前回答

type MyProps = {
  workoutType: string | null;
};

其他回答

JavaScript(和TypeScript)中的所有字段的值都可以是null或undefined。

您可以将字段设置为可选的,而不是可空的。

interface Employee1 {
    name: string;
    salary: number;
}

var a: Employee1 = { name: 'Bob', salary: 40000 }; // OK
var b: Employee1 = { name: 'Bob' }; // Not OK, you must have 'salary'
var c: Employee1 = { name: 'Bob', salary: undefined }; // OK
var d: Employee1 = { name: null, salary: undefined }; // OK

// OK
class SomeEmployeeA implements Employee1 {
    public name = 'Bob';
    public salary = 40000;
}

// Not OK: Must have 'salary'
class SomeEmployeeB implements Employee1 {
    public name: string;
}

比较:

interface Employee2 {
    name: string;
    salary?: number;
}

var a: Employee2 = { name: 'Bob', salary: 40000 }; // OK
var b: Employee2 = { name: 'Bob' }; // OK
var c: Employee2 = { name: 'Bob', salary: undefined }; // OK
var d: Employee2 = { name: null, salary: 'bob' }; // Not OK, salary must be a number

// OK, but doesn't make too much sense
class SomeEmployeeA implements Employee2 {
    public name = 'Bob';
}

在我看来,联合类型在这种情况下是最好的选择:

interface Employee{
   id: number;
   name: string;
   salary: number | null;
}

// Both cases are valid
let employe1: Employee = { id: 1, name: 'John', salary: 100 };
let employe2: Employee = { id: 1, name: 'John', salary: null };

编辑:为了使其按预期工作,您应该在tsconfig中启用strictNullChecks。

type MyProps = {
  workoutType: string | null;
};
type Nullable<T> = {
  [P in keyof T]: T[P] | null;
};

然后你就可以用它了

Nullable<Employee>

这样,您仍然可以像在其他地方一样使用Employee界面

就加个问号?到可选字段。

interface Employee{
   id: number;
   name: string;
   salary?: number;
}