我有一个接口在TypeScript。
interface Employee{
id: number;
name: string;
salary: number;
}
我想把工资作为一个可空字段(就像我们可以在c#中做的那样)。这可能在TypeScript中实现吗?
我有一个接口在TypeScript。
interface Employee{
id: number;
name: string;
salary: number;
}
我想把工资作为一个可空字段(就像我们可以在c#中做的那样)。这可能在TypeScript中实现吗?
当前回答
type MyProps = {
workoutType: string | null;
};
其他回答
JavaScript(和TypeScript)中的所有字段的值都可以是null或undefined。
您可以将字段设置为可选的,而不是可空的。
interface Employee1 {
name: string;
salary: number;
}
var a: Employee1 = { name: 'Bob', salary: 40000 }; // OK
var b: Employee1 = { name: 'Bob' }; // Not OK, you must have 'salary'
var c: Employee1 = { name: 'Bob', salary: undefined }; // OK
var d: Employee1 = { name: null, salary: undefined }; // OK
// OK
class SomeEmployeeA implements Employee1 {
public name = 'Bob';
public salary = 40000;
}
// Not OK: Must have 'salary'
class SomeEmployeeB implements Employee1 {
public name: string;
}
比较:
interface Employee2 {
name: string;
salary?: number;
}
var a: Employee2 = { name: 'Bob', salary: 40000 }; // OK
var b: Employee2 = { name: 'Bob' }; // OK
var c: Employee2 = { name: 'Bob', salary: undefined }; // OK
var d: Employee2 = { name: null, salary: 'bob' }; // Not OK, salary must be a number
// OK, but doesn't make too much sense
class SomeEmployeeA implements Employee2 {
public name = 'Bob';
}
在我看来,联合类型在这种情况下是最好的选择:
interface Employee{
id: number;
name: string;
salary: number | null;
}
// Both cases are valid
let employe1: Employee = { id: 1, name: 'John', salary: 100 };
let employe2: Employee = { id: 1, name: 'John', salary: null };
编辑:为了使其按预期工作,您应该在tsconfig中启用strictNullChecks。
type MyProps = {
workoutType: string | null;
};
type Nullable<T> = {
[P in keyof T]: T[P] | null;
};
然后你就可以用它了
Nullable<Employee>
这样,您仍然可以像在其他地方一样使用Employee界面
就加个问号?到可选字段。
interface Employee{
id: number;
name: string;
salary?: number;
}