我将避免迭代器，因为它们可以在迭代过程中添加/删除对象，也可以为循环使用干净的代码。它将是简单的干净和更少的行。

使用Java 8和Lamda[更新4/2/2019]

import org.json.JSONObject;

public static void printJsonObject(JSONObject jsonObj) {
    jsonObj.keySet().forEach(keyStr ->
    {
        Object keyvalue = jsonObj.get(keyStr);
        System.out.println("key: "+ keyStr + " value: " + keyvalue);

        //for nested objects iteration if required
        //if (keyvalue instanceof JSONObject)
        //    printJsonObject((JSONObject)keyvalue);
    });
}

使用旧方式[更新4/2/2019]

import org.json.JSONObject;

public static void printJsonObject(JSONObject jsonObj) {
    for (String keyStr : jsonObj.keySet()) {
        Object keyvalue = jsonObj.get(keyStr);

        //Print key and value
        System.out.println("key: "+ keyStr + " value: " + keyvalue);

        //for nested objects iteration if required
        //if (keyvalue instanceof JSONObject)
        //    printJsonObject((JSONObject)keyvalue);
    }
}

原来的答案

import org.json.simple.JSONObject;
public static void printJsonObject(JSONObject jsonObj) {
    for (Object key : jsonObj.keySet()) {
        //based on you key types
        String keyStr = (String)key;
        Object keyvalue = jsonObj.get(keyStr);

        //Print key and value
        System.out.println("key: "+ keyStr + " value: " + keyvalue);

        //for nested objects iteration if required
        if (keyvalue instanceof JSONObject)
            printJsonObject((JSONObject)keyvalue);
    }
}

这是该问题的另一种有效解决方案:

public void test (){

    Map<String, String> keyValueStore = new HasMap<>();
    Stack<String> keyPath = new Stack();
    JSONObject json = new JSONObject("thisYourJsonObject");
    keyValueStore = getAllXpathAndValueFromJsonObject(json, keyValueStore, keyPath);
    for(Map.Entry<String, String> map : keyValueStore.entrySet()) {
        System.out.println(map.getKey() + ":" + map.getValue());
    }   
}

public Map<String, String> getAllXpathAndValueFromJsonObject(JSONObject json, Map<String, String> keyValueStore, Stack<String> keyPath) {
    Set<String> jsonKeys = json.keySet();
    for (Object keyO : jsonKeys) {
        String key = (String) keyO;
        keyPath.push(key);
        Object object = json.get(key);

        if (object instanceof JSONObject) {
            getAllXpathAndValueFromJsonObject((JSONObject) object, keyValueStore, keyPath);
        }

        if (object instanceof JSONArray) {
            doJsonArray((JSONArray) object, keyPath, keyValueStore, json, key);
        }

        if (object instanceof String || object instanceof Boolean || object.equals(null)) {
            String keyStr = "";

            for (String keySub : keyPath) {
                keyStr += keySub + ".";
            }

            keyStr = keyStr.substring(0, keyStr.length() - 1);

            keyPath.pop();

            keyValueStore.put(keyStr, json.get(key).toString());
        }
    }

    if (keyPath.size() > 0) {
        keyPath.pop();
    }

    return keyValueStore;
}

public void doJsonArray(JSONArray object, Stack<String> keyPath, Map<String, String> keyValueStore, JSONObject json,
        String key) {
    JSONArray arr = (JSONArray) object;
    for (int i = 0; i < arr.length(); i++) {
        keyPath.push(Integer.toString(i));
        Object obj = arr.get(i);
        if (obj instanceof JSONObject) {
            getAllXpathAndValueFromJsonObject((JSONObject) obj, keyValueStore, keyPath);
        }

        if (obj instanceof JSONArray) {
            doJsonArray((JSONArray) obj, keyPath, keyValueStore, json, key);
        }

        if (obj instanceof String || obj instanceof Boolean || obj.equals(null)) {
            String keyStr = "";

            for (String keySub : keyPath) {
                keyStr += keySub + ".";
            }

            keyStr = keyStr.substring(0, keyStr.length() - 1);

            keyPath.pop();

            keyValueStore.put(keyStr , json.get(key).toString());
        }
    }
    if (keyPath.size() > 0) {
        keyPath.pop();
    }
}

我做了一个小的递归函数，遍历整个json对象并保存键路径及其值。

// My stored keys and values from the json object
HashMap<String,String> myKeyValues = new HashMap<String,String>();

// Used for constructing the path to the key in the json object
Stack<String> key_path = new Stack<String>();

// Recursive function that goes through a json object and stores 
// its key and values in the hashmap 
private void loadJson(JSONObject json){
    Iterator<?> json_keys = json.keys();

    while( json_keys.hasNext() ){
        String json_key = (String)json_keys.next();

        try{
            key_path.push(json_key);
            loadJson(json.getJSONObject(json_key));
       }catch (JSONException e){
           // Build the path to the key
           String key = "";
           for(String sub_key: key_path){
               key += sub_key+".";
           }
           key = key.substring(0,key.length()-1);

           System.out.println(key+": "+json.getString(json_key));
           key_path.pop();
           myKeyValues.put(key, json.getString(json_key));
        }
    }
    if(key_path.size() > 0){
        key_path.pop();
    }
}

使用Java 8和lambda，更清晰:

JSONObject jObject = new JSONObject(contents.trim());

jObject.keys().forEachRemaining(k ->
{

});

https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html#forEachRemaining-java.util.function.Consumer-

对于我的案例，我发现迭代names()效果很好

for(int i = 0; i<jobject.names().length(); i++){
    Log.v(TAG, "key = " + jobject.names().getString(i) + " value = " + jobject.get(jobject.names().getString(i)));
}

首先把这个放在某个地方:

private <T> Iterable<T> iteratorToIterable(final Iterator<T> iterator) {
    return new Iterable<T>() {
        @Override
        public Iterator<T> iterator() {
            return iterator;
        }
    };
}

或者如果你可以访问Java8，就这样:

private <T> Iterable<T> iteratorToIterable(Iterator<T> iterator) {
    return () -> iterator;
}

然后简单地迭代对象的键和值:

for (String key : iteratorToIterable(object.keys())) {
    JSONObject entry = object.getJSONObject(key);
    // ...