问题

我开始看看Swift编程语言,不知为何我不能正确地从特定的UIStoryboard输入一个UIViewController的初始化。

在Objective-C中,我简单地写:

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"StoryboardName" bundle:nil];
UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"ViewControllerID"];
[self presentViewController:viewController animated:YES completion:nil];

有人能帮助我如何在斯威夫特上实现这一点吗?


当前回答

我创建了一个库,可以用更好的语法更容易地处理这个问题:

https://github.com/Jasperav/Storyboardable

只需改变Storyboard.swift,让ViewControllers符合Storyboardable。

其他回答

// "Main" is name of .storybord file "
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
// "MiniGameView" is the ID given to the ViewController in the interfacebuilder
// MiniGameViewController is the CLASS name of the ViewController.swift file acosiated to the ViewController
var setViewController = mainStoryboard.instantiateViewControllerWithIdentifier("MiniGameView") as MiniGameViewController
var rootViewController = self.window!.rootViewController
rootViewController?.presentViewController(setViewController, animated: false, completion: nil)

当我把它放在AppDelegate时,这工作得很好

这个链接有两个实现:

迅速:

let viewController:UIViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("ViewController") as UIViewController
self.presentViewController(viewController, animated: false, completion: nil)

Objective - C

UIViewController *viewController = [[UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil] instantiateViewControllerWithIdentifier:@"ViewController"];

这个链接有在同一个故事板中初始化视图控制器的代码

/*
 Helper to Switch the View based on StoryBoard
 @param StoryBoard ID  as String
*/
func switchToViewController(identifier: String) {
    let viewController = self.storyboard?.instantiateViewControllerWithIdentifier(identifier) as! UIViewController
    self.navigationController?.setViewControllers([viewController], animated: false)

}

如果你想以模态方式呈现它,你应该有如下所示的东西:

let vc = self.storyboard!.instantiateViewControllerWithIdentifier("YourViewControllerID")
self.showDetailViewController(vc as! YourViewControllerClassName, sender: self)

斯威夫特5

let vc = self.storyboard!.instantiateViewController(withIdentifier: "CVIdentifier")
self.present(vc, animated: true, completion: nil)

我使用这个助手:

struct Storyboard<T: UIViewController> {
    
    static var storyboardName: String {
        return String(describing: T.self)
    }
    
    static var viewController: T {
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        
        guard let vc = storyboard.instantiateViewController(withIdentifier: Self.storyboardName) as? T else {
            fatalError("Could not get controller from Storyboard: \(Self.storyboardName)")
        }
        
        return vc
    }
}

用法(故事板ID必须匹配UIViewController类名)

let myVC = Storyboard.viewController as MyViewController