我有一个简单的JSON键/值列表，通过POST发送回ASP.NET。例子：
{ "key1": "value1", "key2": "value2"}
我没有试图反序列化为强类型的.NET对象
我只需要一个普通的旧字典（Of String，String），或者一些等价的东西（哈希表，字典（OfString，Object），老式的StringDictionary——见鬼，一个二维字符串数组对我来说很有用。
我可以使用ASP.NET 3.5中可用的任何东西，也可以使用流行的Json.NET（我已经在使用它对客户端进行序列化）。
显然，这两个JSON库都没有这种开箱即用的能力——它们完全专注于通过强契约实现基于反射的反序列化。
有什么想法吗？
限制：
我不想实现我自己的JSON解析器尚无法使用ASP.NET 4.0希望远离旧的、不推荐使用的JSON ASP.NET类
当前回答
对于任何试图将JSON转换为字典只是为了从中检索一些值的人来说
using Newtonsoft.Json.Linq
...
JObject o = JObject.Parse(@"{
'CPU': 'Intel',
'Drives': [
'DVD read/writer',
'500 gigabyte hard drive'
]
}");
string cpu = (string)o["CPU"];
// Intel
string firstDrive = (string)o["Drives"][0];
// DVD read/writer
IList<string> allDrives = o["Drives"].Select(t => (string)t).ToList();
// DVD read/writer
// 500 gigabyte hard drive
其他回答
马克·伦德尔（Mark Rendle）将此作为评论发布，我想将其作为答案发布，因为这是迄今为止唯一一个能够从Google reCaptcha响应中返回成功和错误代码json结果的解决方案。
string jsonReponseString= wClient.DownloadString(requestUrl);
IDictionary<string, object> dict = new JavaScriptSerializer().DeserializeObject(jsonReponseString) as IDictionary<string, object>;
再次感谢，马克！
我也有同样的问题，所以我自己写了这个。此解决方案与其他解决方案不同，因为它可以反序列化到多个级别。
只需将JSON字符串发送到反序列化ToDictionary函数，它将返回非强类型Dictionary＜string，object＞object。
旧代码
private Dictionary<string, object> deserializeToDictionary(string jo)
{
var values = JsonConvert.DeserializeObject<Dictionary<string, object>>(jo);
var values2 = new Dictionary<string, object>();
foreach (KeyValuePair<string, object> d in values)
{
// if (d.Value.GetType().FullName.Contains("Newtonsoft.Json.Linq.JObject"))
if (d.Value is JObject)
{
values2.Add(d.Key, deserializeToDictionary(d.Value.ToString()));
}
else
{
values2.Add(d.Key, d.Value);
}
}
return values2;
}
示例：这将返回FacebookJSON响应的Dictionary<string，object>object。
Test
private void button1_Click(object sender, EventArgs e)
{
string responsestring = "{\"id\":\"721055828\",\"name\":\"Dasun Sameera Weerasinghe\",\"first_name\":\"Dasun\",\"middle_name\":\"Sameera\",\"last_name\":\"Weerasinghe\",\"username\":\"dasun\",\"gender\":\"male\",\"locale\":\"en_US\", hometown: {id: \"108388329191258\", name: \"Moratuwa, Sri Lanka\",}}";
Dictionary<string, object> values = deserializeToDictionary(responsestring);
}
注意：home进一步反序列化为Dictionary＜string，object＞对象
使现代化
如果JSON字符串上没有数组，我的旧答案很有用。如果元素是数组，则这一个将进一步反序列化为List<object>。
只需将JSON字符串发送到反序列化ToDictionaryOrList函数，它将返回非强类型Dictionary＜string，object＞object或List＜object＞。
private static object deserializeToDictionaryOrList(string jo,bool isArray=false)
{
if (!isArray)
{
isArray = jo.Substring(0, 1) == "[";
}
if (!isArray)
{
var values = JsonConvert.DeserializeObject<Dictionary<string, object>>(jo);
var values2 = new Dictionary<string, object>();
foreach (KeyValuePair<string, object> d in values)
{
if (d.Value is JObject)
{
values2.Add(d.Key, deserializeToDictionary(d.Value.ToString()));
}
else if (d.Value is JArray)
{
values2.Add(d.Key, deserializeToDictionary(d.Value.ToString(), true));
}
else
{
values2.Add(d.Key, d.Value);
}
}
return values2;
}else
{
var values = JsonConvert.DeserializeObject<List<object>>(jo);
var values2 = new List<object>();
foreach (var d in values)
{
if (d is JObject)
{
values2.Add(deserializeToDictionary(d.ToString()));
}
else if (d is JArray)
{
values2.Add(deserializeToDictionary(d.ToString(), true));
}
else
{
values2.Add(d);
}
}
return values2;
}
}
对于那些在互联网上搜索并偶然发现这篇文章的人，我写了一篇关于如何使用JavaScriptSerializer类的博客文章。
阅读更多。。。http://procbits.com/2011/04/21/quick-json-serializationdeserialization-in-c/
下面是一个示例：
var json = "{\"id\":\"13\", \"value\": true}";
var jss = new JavaScriptSerializer();
var table = jss.Deserialize<dynamic>(json);
Console.WriteLine(table["id"]);
Console.WriteLine(table["value"]);
我在这里添加了jSnake04和Dasun提交的代码。我添加了从JArray实例创建对象列表的代码。它具有双向递归，但由于它在固定的有限树模型上运行，所以除非数据量很大，否则不会有堆栈溢出的风险。
/// <summary>
/// Deserialize the given JSON string data (<paramref name="data"/>) into a
/// dictionary.
/// </summary>
/// <param name="data">JSON string.</param>
/// <returns>Deserialized dictionary.</returns>
private IDictionary<string, object> DeserializeData(string data)
{
var values = JsonConvert.DeserializeObject<Dictionary<string, object>>(data);
return DeserializeData(values);
}
/// <summary>
/// Deserialize the given JSON object (<paramref name="data"/>) into a dictionary.
/// </summary>
/// <param name="data">JSON object.</param>
/// <returns>Deserialized dictionary.</returns>
private IDictionary<string, object> DeserializeData(JObject data)
{
var dict = data.ToObject<Dictionary<String, Object>>();
return DeserializeData(dict);
}
/// <summary>
/// Deserialize any elements of the given data dictionary (<paramref name="data"/>)
/// that are JSON object or JSON arrays into dictionaries or lists respectively.
/// </summary>
/// <param name="data">Data dictionary.</param>
/// <returns>Deserialized dictionary.</returns>
private IDictionary<string, object> DeserializeData(IDictionary<string, object> data)
{
foreach (var key in data.Keys.ToArray())
{
var value = data[key];
if (value is JObject)
data[key] = DeserializeData(value as JObject);
if (value is JArray)
data[key] = DeserializeData(value as JArray);
}
return data;
}
/// <summary>
/// Deserialize the given JSON array (<paramref name="data"/>) into a list.
/// </summary>
/// <param name="data">Data dictionary.</param>
/// <returns>Deserialized list.</returns>
private IList<Object> DeserializeData(JArray data)
{
var list = data.ToObject<List<Object>>();
for (int i = 0; i < list.Count; i++)
{
var value = list[i];
if (value is JObject)
list[i] = DeserializeData(value as JObject);
if (value is JArray)
list[i] = DeserializeData(value as JArray);
}
return list;
}
游戏开始得有点晚了，但上面的解决方案中没有一个给我指明了一个纯粹而简单的.NET，而不是json.NET解决方案的方向。这就是，最后变得非常简单。下面是一个完整的运行示例，说明如何使用标准.NETJson序列化，该示例在根对象和子对象中都有字典。
关键是这只猫，将设置解析为序列化程序的第二个参数：
DataContractJsonSerializerSettings settings =
new DataContractJsonSerializerSettings();
settings.UseSimpleDictionaryFormat = true;
完整代码如下：
using System;
using System.Collections.Generic;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
namespace Kipon.dk
{
public class JsonTest
{
public const string EXAMPLE = @"{
""id"": ""some id"",
""children"": {
""f1"": {
""name"": ""name 1"",
""subs"": {
""1"": { ""name"": ""first sub"" },
""2"": { ""name"": ""second sub"" }
}
},
""f2"": {
""name"": ""name 2"",
""subs"": {
""37"": { ""name"": ""is 37 in key""}
}
}
}
}
";
[DataContract]
public class Root
{
[DataMember(Name ="id")]
public string Id { get; set; }
[DataMember(Name = "children")]
public Dictionary<string,Child> Children { get; set; }
}
[DataContract]
public class Child
{
[DataMember(Name = "name")]
public string Name { get; set; }
[DataMember(Name = "subs")]
public Dictionary<int, Sub> Subs { get; set; }
}
[DataContract]
public class Sub
{
[DataMember(Name = "name")]
public string Name { get; set; }
}
public static void Test()
{
var array = System.Text.Encoding.UTF8.GetBytes(EXAMPLE);
using (var mem = new System.IO.MemoryStream(array))
{
mem.Seek(0, System.IO.SeekOrigin.Begin);
DataContractJsonSerializerSettings settings =
new DataContractJsonSerializerSettings();
settings.UseSimpleDictionaryFormat = true;
var ser = new DataContractJsonSerializer(typeof(Root), settings);
var data = (Root)ser.ReadObject(mem);
Console.WriteLine(data.Id);
foreach (var childKey in data.Children.Keys)
{
var child = data.Children[childKey];
Console.WriteLine(" Child: " + childKey + " " + child.Name);
foreach (var subKey in child.Subs.Keys)
{
var sub = child.Subs[subKey];
Console.WriteLine(" Sub: " + subKey + " " + sub.Name);
}
}
}
}
}
}
