要向所有客户端发送内容,您可以使用:

io.sockets.emit('response', data);

要接收来自客户的信息,您可以使用:

socket.on('cursor', function(data) {
  ...
});

如何将这两者结合起来,以便在服务器上从客户端接收消息时,将该消息发送给除发送消息的用户之外的所有用户?

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

我是否必须通过发送带有消息的client-id,然后在客户端检查来破解它,或者有更简单的方法吗?


当前回答

更新列表以获取进一步的文档。

socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message
socket.on(); //event listener, can be called on client to execute on server
io.sockets.socket(); //for emiting to specific clients
io.sockets.emit(); //send to all connected clients (same as socket.emit)
io.sockets.on() ; //initial connection from a client.

希望这能有所帮助。

其他回答

使用这个编码

io.sockets.on('connection', function (socket) {

    socket.on('mousemove', function (data) {

        socket.broadcast.emit('moving', data);
    });

这个socket.broadcast.emit()将发送函数中的所有内容,除了发送到发送的服务器

广播。Emit将MSG发送到所有其他客户端(发送方除外)

socket.on('cursor', function(data) {
  socket.broadcast.emit('msg', data);
});

来自@LearnRPG的答案,但带有1.0:

 // send to current request socket client
 socket.emit('message', "this is a test");

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); //still works
 //or
 io.emit('message', 'this is a test');

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');

 // sending to all clients in 'game' room(channel), include sender
 // docs says "simply use to or in when broadcasting or emitting"
 io.in('game').emit('message', 'cool game');

 // sending to individual socketid, socketid is like a room
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');

为了回答@Crashalot的评论,socketid来自:

var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })

对于房间中的命名空间,循环房间中的客户端列表(类似于Nav的回答)是我发现的两种可行的方法之一。另一种是使用排除。如

socket.on('message',function(data) {
    io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}

以下是我的列表(1.0版本更新):

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});