我想从画廊创建一个图片选择器。我使用代码

 intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
 startActivityForResult(intent, TFRequestCodes.GALLERY);

我的问题是在这个活动和视频文件显示。是否有一种方法可以过滤显示的文件,以便在此活动中不显示视频文件?


当前回答

这是一个完整的示例请求权限(如果需要),从图库中选择图像,然后将图像转换为位图或文件

AndroidManifesh.xml

<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>

活动

class MainActivity : AppCompatActivity() {

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)

        button_pick_image.setOnClickListener {
            pickImage()
        }
    }

    private fun pickImage() {
        if (ActivityCompat.checkSelfPermission(this, READ_EXTERNAL_STORAGE) == PackageManager.PERMISSION_GRANTED) {
            val intent = Intent(
                Intent.ACTION_PICK,
                MediaStore.Images.Media.INTERNAL_CONTENT_URI
            )
            intent.type = "image/*"
            intent.putExtra("crop", "true")
            intent.putExtra("scale", true)
            intent.putExtra("aspectX", 16)
            intent.putExtra("aspectY", 9)
            startActivityForResult(intent, PICK_IMAGE_REQUEST_CODE)
        } else {
            ActivityCompat.requestPermissions(
                this,
                arrayOf(Manifest.permission.READ_EXTERNAL_STORAGE),
                READ_EXTERNAL_STORAGE_REQUEST_CODE
            )
        }
    }

    override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
        super.onActivityResult(requestCode, resultCode, data)
        if (requestCode == PICK_IMAGE_REQUEST_CODE) {
            if (resultCode != Activity.RESULT_OK) {
                return
            }
            val uri = data?.data
            if (uri != null) {
                val imageFile = uriToImageFile(uri)
                // todo do something with file
            }
            if (uri != null) {
                val imageBitmap = uriToBitmap(uri)
                // todo do something with bitmap
            }
        }
    }

    override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults)
        when (requestCode) {
            READ_EXTERNAL_STORAGE_REQUEST_CODE -> {
                if (grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    // pick image after request permission success
                    pickImage()
                }
            }
        }
    }

    private fun uriToImageFile(uri: Uri): File? {
        val filePathColumn = arrayOf(MediaStore.Images.Media.DATA)
        val cursor = contentResolver.query(uri, filePathColumn, null, null, null)
        if (cursor != null) {
            if (cursor.moveToFirst()) {
                val columnIndex = cursor.getColumnIndex(filePathColumn[0])
                val filePath = cursor.getString(columnIndex)
                cursor.close()
                return File(filePath)
            }
            cursor.close()
        }
        return null
    }

    private fun uriToBitmap(uri: Uri): Bitmap {
        return MediaStore.Images.Media.getBitmap(this.contentResolver, uri)
    }

    companion object {
        const val PICK_IMAGE_REQUEST_CODE = 1000
        const val READ_EXTERNAL_STORAGE_REQUEST_CODE = 1001
    }
}

演示 https://github.com/PhanVanLinh/AndroidPickImage

其他回答

如果你只是寻找图像和多重选择。

看一次https://stackoverflow.com/a/15029515/1136023

这对将来很有帮助。我个人觉得使用MultipleImagePick很棒。

由于startActivityForResult()已经废弃,我们可以使用ActivityResultLauncher以以下方式从图库中选择图像:

首先,我们需要定义一个ActivityResultLauncher<String[]>并在onCreate()(用于活动)或onViewCreated()(用于片段)中初始化它

        ActivityResultLauncher<String[]> galleryActivityLauncher = registerForActivityResult(new ActivityResultContracts.OpenDocument(), new ActivityResultCallback<Uri>() {
            @Override
            public void onActivityResult(Uri result) {
                if (result != null) {
                    // perform desired operations using the result Uri
                } else {
                    Log.d(TAG, "onActivityResult: the result is null for some reason");
                }
            }
        });

假设我们需要在点击submitButton时打开图库。

在onClickListener中,我们需要调用

galleryActivityLauncher.launch(new String[]{"image/*"});

这里的技巧是launch()的参数。通过在参数数组中添加"image/*",我们指定文件资源管理器只加载图像。

对于只从本地选择添加这个:

        i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)

这个工作得很好:

    val i = Intent(Intent.ACTION_GET_CONTENT,MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
    i.type = "image/*"
    i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)
    startActivityForResult(Intent.createChooser(i,"Select Photo"),pickImageRequestCode)

我也有同样的问题,我用这个密码

addIntent

 Intent intent = new Intent();
        intent.setType("image/*");
        intent.setAction(Intent.ACTION_GET_CONTENT);
        startActivityForResult(Intent.createChooser(intent, "Tack Image"), PICK_PHOTO);

添加onActivityResult

 @Override
  public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO && resultCode == Activity.RESULT_OK) {
      if (data == null) {
      //error
        return;
      }
      try {
        Uri uri = data.getData();
        File file = FileUtil.from(currentActivity, uri);
      } catch (IOException e) {
        e.printStackTrace();
      }
    }
  }

FileUtil类

import android.content.Context;
import android.database.Cursor;
import android.net.Uri;
import android.provider.OpenableColumns;
import android.util.Log;

import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class FileUtil {
  private static final int EOF = -1;
  private static final int DEFAULT_BUFFER_SIZE = 1024 * 4;

  private FileUtil() {

  }

  public static File from(Context context, Uri uri) throws IOException {
    InputStream inputStream = context.getContentResolver().openInputStream(uri);
    String fileName = getFileName(context, uri);
    String[] splitName = splitFileName(fileName);
    File tempFile = File.createTempFile(splitName[0], splitName[1]);
    tempFile = rename(tempFile, fileName);
    tempFile.deleteOnExit();
    FileOutputStream out = null;
    try {
      out = new FileOutputStream(tempFile);
    } catch (FileNotFoundException e) {
      e.printStackTrace();
    }
    if (inputStream != null) {
      copy(inputStream, out);
      inputStream.close();
    }

    if (out != null) {
      out.close();
    }
    return tempFile;
  }

  private static String[] splitFileName(String fileName) {
    String name = fileName;
    String extension = "";
    int i = fileName.lastIndexOf(".");
    if (i != -1) {
      name = fileName.substring(0, i);
      extension = fileName.substring(i);
    }

    return new String[]{name, extension};
  }

  private static String getFileName(Context context, Uri uri) {
    String result = null;
    if (uri.getScheme().equals("content")) {
      Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
      try {
        if (cursor != null && cursor.moveToFirst()) {
          result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
        }
      } catch (Exception e) {
        e.printStackTrace();
      } finally {
        if (cursor != null) {
          cursor.close();
        }
      }
    }
    if (result == null) {
      result = uri.getPath();
      int cut = result.lastIndexOf(File.separator);
      if (cut != -1) {
        result = result.substring(cut + 1);
      }
    }
    return result;
  }

  private static File rename(File file, String newName) {
    File newFile = new File(file.getParent(), newName);
    if (!newFile.equals(file)) {
      if (newFile.exists() && newFile.delete()) {
        Log.d("FileUtil", "Delete old " + newName + " file");
      }
      if (file.renameTo(newFile)) {
        Log.d("FileUtil", "Rename file to " + newName);
      }
    }
    return newFile;
  }

  private static long copy(InputStream input, OutputStream output) throws IOException {
    long count = 0;
    int n;
    byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
    while (EOF != (n = input.read(buffer))) {
      output.write(buffer, 0, n);
      count += n;
    }
    return count;
  }
}

并且必须将provider_paths.xml添加到像image这样的XML文件夹中

provider_paths.xml

<?xml version="1.0" encoding="utf-8"?>
<paths>
    <external-path name="external_files" path="."/>
</paths>

最后在AndroidManifest.xml中添加如下内容

<application
...>

...
      <provider
          android:name="androidx.core.content.FileProvider"
          android:authorities="${applicationId}.provider"
          android:exported="false"
          android:grantUriPermissions="true">
          <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths" />
        </provider>
...
</application>

我希望我能帮上忙

你可以做的比下面的回答更简单:

Uri Selected_Image_Uri = data.getData();
ImageView imageView = (ImageView) findViewById(R.id.loadedimg);
imageView.setImageURI(Selected_Image_Uri);