我想做的事情似乎很简单,但我在网上找不到任何答案。我有一个对象的NSMutableArray,假设它们是Person对象。我想对NSMutableArray按Person排序。birthDate是一个NSDate。
我认为这与这个方法有关:
NSArray *sortedArray = [drinkDetails sortedArrayUsingSelector:@selector(???)];
在Java中,我将使我的对象实现Comparable,或使用集合。使用内联自定义比较器排序…在Objective-C中怎么做呢?
如果你只是排序一个nsnumber数组,你可以用一个调用来排序它们:
[arrayToSort sortUsingSelector: @selector(compare:)];
这是因为数组中的对象(NSNumber对象)实现了比较方法。你可以为NSString对象做同样的事情,甚至为实现了比较方法的自定义数据对象数组做同样的事情。
下面是一些使用比较器块的示例代码。它对字典数组进行排序,其中每个字典在键“sort_key”中包含一个数字。
#define SORT_KEY @\"sort_key\"
[anArray sortUsingComparator:
^(id obj1, id obj2)
{
NSInteger value1 = [[obj1 objectForKey: SORT_KEY] intValue];
NSInteger value2 = [[obj2 objectForKey: SORT_KEY] intValue];
if (value1 > value2)
{
return (NSComparisonResult)NSOrderedDescending;
}
if (value1 < value2)
{
return (NSComparisonResult)NSOrderedAscending;
}
return (NSComparisonResult)NSOrderedSame;
}];
上面的代码演示了如何为每个排序键获取整数值并对它们进行比较。因为NSNumber对象实现了一个比较方法,它可以重写得更简单:
#define SORT_KEY @\"sort_key\"
[anArray sortUsingComparator:
^(id obj1, id obj2)
{
NSNumber* key1 = [obj1 objectForKey: SORT_KEY];
NSNumber* key2 = [obj2 objectForKey: SORT_KEY];
return [key1 compare: key2];
}];
或者比较器的主体甚至可以被提炼为一行:
return [[obj1 objectForKey: SORT_KEY] compare: [obj2 objectForKey: SORT_KEY]];
我倾向于使用简单的语句和大量的临时变量,因为代码更容易阅读,也更容易调试。编译器无论如何都会优化掉临时变量,因此,全在一行中的版本没有任何优势。
在我的例子中,我使用“sortedArrayUsingComparator”对数组进行排序。请看下面的代码。
contactArray = [[NSArray arrayWithArray:[contactSet allObjects]] sortedArrayUsingComparator:^NSComparisonResult(ContactListData *obj1, ContactListData *obj2) {
NSString *obj1Str = [NSString stringWithFormat:@"%@ %@",obj1.contactName,obj1.contactSurname];
NSString *obj2Str = [NSString stringWithFormat:@"%@ %@",obj2.contactName,obj2.contactSurname];
return [obj1Str compare:obj2Str];
}];
我的目标是,
@interface ContactListData : JsonData
@property(nonatomic,strong) NSString * contactName;
@property(nonatomic,strong) NSString * contactSurname;
@property(nonatomic,strong) NSString * contactPhoneNumber;
@property(nonatomic) BOOL isSelected;
@end
Swift的协议和函数式编程让这变得非常简单,你只需要让你的类符合Comparable协议,实现协议所需的方法,然后使用sorted(by:)高阶函数来创建一个排序的数组,而不需要使用可变数组。
class Person: Comparable {
var birthDate: NSDate?
let name: String
init(name: String) {
self.name = name
}
static func ==(lhs: Person, rhs: Person) -> Bool {
return lhs.birthDate === rhs.birthDate || lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedSame
}
static func <(lhs: Person, rhs: Person) -> Bool {
return lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedAscending
}
static func >(lhs: Person, rhs: Person) -> Bool {
return lhs.birthDate?.compare(rhs.birthDate as! Date) == .orderedDescending
}
}
let p1 = Person(name: "Sasha")
p1.birthDate = NSDate()
let p2 = Person(name: "James")
p2.birthDate = NSDate()//he is older by miliseconds
if p1 == p2 {
print("they are the same") //they are not
}
let persons = [p1, p2]
//sort the array based on who is older
let sortedPersons = persons.sorted(by: {$0 > $1})
//print sasha which is p1
print(persons.first?.name)
//print James which is the "older"
print(sortedPersons.first?.name)
NSMutableArray *stockHoldingCompanies = [NSMutableArray arrayWithObjects:fortune1stock,fortune2stock,fortune3stock,fortune4stock,fortune5stock,fortune6stock , nil];
NSSortDescriptor *sortOrder = [NSSortDescriptor sortDescriptorWithKey:@"companyName" ascending:NO];
[stockHoldingCompanies sortUsingDescriptors:[NSArray arrayWithObject:sortOrder]];
NSEnumerator *enumerator = [stockHoldingCompanies objectEnumerator];
ForeignStockHolding *stockHoldingCompany;
NSLog(@"Fortune 6 companies sorted by Company Name");
while (stockHoldingCompany = [enumerator nextObject]) {
NSLog(@"===============================");
NSLog(@"CompanyName:%@",stockHoldingCompany.companyName);
NSLog(@"Purchase Share Price:%.2f",stockHoldingCompany.purchaseSharePrice);
NSLog(@"Current Share Price: %.2f",stockHoldingCompany.currentSharePrice);
NSLog(@"Number of Shares: %i",stockHoldingCompany.numberOfShares);
NSLog(@"Cost in Dollars: %.2f",[stockHoldingCompany costInDollars]);
NSLog(@"Value in Dollars : %.2f",[stockHoldingCompany valueInDollars]);
}
NSLog(@"===============================");