是否有一种方法将所有jar文件包含在类路径的目录中?
我正在尝试java -classpath lib/*.jar:。program,它不能找到在这些罐子里的类文件。我是否需要将每个jar文件分别添加到类路径中?
是否有一种方法将所有jar文件包含在类路径的目录中?
我正在尝试java -classpath lib/*.jar:。program,它不能找到在这些罐子里的类文件。我是否需要将每个jar文件分别添加到类路径中?
当前回答
对我来说,这适用于窗户。
java -cp "/lib/*;" sample
linux
java -cp "/lib/*:" sample
我使用的是Java 6
其他回答
java命令的参数顺序也很重要:
c:\projects\CloudMirror>java Javaside -cp "jna-5.6.0.jar;.\"
Error: Unable to initialize main class Javaside
Caused by: java.lang.NoClassDefFoundError: com/sun/jna/Callback
与
c:\projects\CloudMirror>java -cp "jna-5.6.0.jar;.\" Javaside
Exception in thread "main" java.lang.UnsatisfiedLinkError: Unable
您需要分别添加它们。或者,如果确实需要指定一个目录,可以将所有内容解jar到一个目录中,并将其添加到类路径中。但是,我不推荐这种方法,因为您可能会在类路径版本控制和不可管理性方面出现奇怪的问题。
使用Java 6或更高版本,类路径选项支持通配符。注意事项:
使用直引号(") 使用*,而不是*.jar
窗户
lib/*" my.package.MainClass . java -cp "Test.jar
Unix
java -cp "Test.jar:lib/*" my.package.MainClass .jar:lib/*
这类似于Windows,但使用:而不是;。如果你不能使用通配符,bash允许以下语法(其中lib是包含所有Java存档文件的目录):
Java -cp "$(printf %s: lib/*.jar)"
(注意,使用类路径与-jar选项不兼容。参见:从命令提示符执行带有多个类路径库的jar文件)
理解通配符
从类路径文档中:
Class path entries can contain the basename wildcard character *, which is considered equivalent to specifying a list of all the files in the directory with the extension .jar or .JAR. For example, the class path entry foo/* specifies all JAR files in the directory named foo. A classpath entry consisting simply of * expands to a list of all the jar files in the current directory. A class path entry that contains * will not match class files. To match both classes and JAR files in a single directory foo, use either foo;foo/* or foo/*;foo. The order chosen determines whether the classes and resources in foo are loaded before JAR files in foo, or vice versa. Subdirectories are not searched recursively. For example, foo/* looks for JAR files only in foo, not in foo/bar, foo/baz, etc. The order in which the JAR files in a directory are enumerated in the expanded class path is not specified and may vary from platform to platform and even from moment to moment on the same machine. A well-constructed application should not depend upon any particular order. If a specific order is required then the JAR files can be enumerated explicitly in the class path. Expansion of wildcards is done early, prior to the invocation of a program's main method, rather than late, during the class-loading process itself. Each element of the input class path containing a wildcard is replaced by the (possibly empty) sequence of elements generated by enumerating the JAR files in the named directory. For example, if the directory foo contains a.jar, b.jar, and c.jar, then the class path foo/* is expanded into foo/a.jar;foo/b.jar;foo/c.jar, and that string would be the value of the system property java.class.path. The CLASSPATH environment variable is not treated any differently from the -classpath (or -cp) command-line option. That is, wildcards are honored in all these cases. However, class path wildcards are not honored in the Class-Path jar-manifest header.
注意:由于java 8中的一个已知错误,windows示例必须在条目前使用反斜杠,后面带星号:https://bugs.openjdk.java.net/browse/JDK-8131329
我在一个文件夹里有多个罐子。下面的命令在JDK1.8中对我有用,可以包括文件夹中的所有jar。请注意,如果在类路径中有空格,请在引号中包含
窗户
“C:\My Jars\sdk\lib\*
运行:java -classpath "C:\My Jars\sdk\lib\*; C:\ programs" MyProgram
Linux
编译:javac -classpath "/home/guestuser/My Jars/sdk/lib/*" MyProgram.java
运行:java -classpath "/home/guestuser/My Jars/sdk/lib/*:/home/guestuser/programs" MyProgram
简写形式:如果你的main在一个jar中,你可能需要一个额外的“-jar pathTo/yourJar/YourJarsName.jar”显式声明来让它工作(即使“YourJarsName.jar”在类路径中) (或者,回答5年前提出的原始问题:你不需要显式地重新声明每个jar,但看起来,即使在java6中,你也需要重新声明自己的jar…)
长形式: (我已经明确说明了这一点,我希望即使是java的闯入者也可以使用它)
像这里的许多人一样,我使用eclipse导出JAR:(File-> export ->'可运行的JAR文件')。eclipse (Juno)提供了三个“库处理”选项:
opt1: "Extract required libraries into generated JAR"
opt2: "Package required libraries into generated JAR"
opt3: "Copy required libraries into a sub-folder next to the generated JAR"
通常我会使用opt2 (opt1肯定会破坏),但是我正在使用的一个jar中的本机代码,当您选择该选项时,我发现eclipse利用了方便的“jarinjar”技巧。即使在意识到我需要opt3之后,然后找到这个StackOverflow条目,我仍然花了一些时间来弄清楚如何在eclipse之外启动我的main,所以这里是对我有用的,因为它对其他人很有用……
如果你将罐子命名为fooBarTheJarFile.jar 和所有设置导出到目录:“/theFully/qualifiedPath/toYourChosenDir”。
(意味着“导出目的地”字段将读取:“/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile.jar”)
当你点击finish后,你会发现eclipse将所有的库放在一个名为“fooBarTheJarFile_lib”的文件夹中,就像这样:
/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile.jar
/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/SomeOtherJar01.jar
/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/SomeOtherJar02.jar
/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/SomeOtherJar03.jar
/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/SomeOtherJar04.jar
然后,您可以从系统上的任何地方启动:
java -classpath "/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/*" -jar /theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile.jar package.path_to.the_class_with.your_main.TheClassWithYourMain
(对于Java新手来说:` package.path_to.the_class_with. path `。your_main'是声明的包路径,你可以在' classwithyourmain .java'文件的顶部找到,该文件包含'main(String[] args){…}'你希望在java之外运行)
要注意的陷阱:在你声明的类路径上的jar列表中有'fooBarTheJarFile.jar'是不够的。您需要显式地声明'-jar',并重新声明该jar的位置。
例如:
java -classpath "/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile.jar;/theFully/qualifiedPath/toYourChosenDir/fooBarTheJarFile_lib/*" somepackages.inside.yourJar.leadingToTheMain.TheClassWithYourMain
用相对路径重申:
cd /theFully/qualifiedPath/toYourChosenDir/;
BREAKS: java -cp "fooBarTheJarFile_lib/*" package.path_to.the_class_with.your_main.TheClassWithYourMain
BREAKS: java -cp ".;fooBarTheJarFile_lib/*" package.path_to.the_class_with.your_main.TheClassWithYourMain
BREAKS: java -cp ".;fooBarTheJarFile_lib/*" -jar package.path_to.the_class_with.your_main.TheClassWithYourMain
WORKS: java -cp ".;fooBarTheJarFile_lib/*" -jar fooBarTheJarFile.jar package.path_to.the_class_with.your_main.TheClassWithYourMain
(使用Java版本“1.6.0_27”;通过OpenJDK 64位服务器虚拟机安装在ubuntu 12.04上)