我被要求更新一些Excel 2003宏,但是VBA项目有密码保护,而且似乎缺乏文档…没人知道密码。
是否有一种方法可以删除或破解VBA项目的密码?
我被要求更新一些Excel 2003宏,但是VBA项目有密码保护,而且似乎缺乏文档…没人知道密码。
是否有一种方法可以删除或破解VBA项目的密码?
当前回答
Colin Pickard is mostly correct, but don't confuse the "password to open" protection for the entire file with the VBA password protection, which is completely different from the former and is the same for Office 2003 and 2007 (for Office 2007, rename the file to .zip and look for the vbaProject.bin inside the zip). And that technically the correct way to edit the file is to use a OLE compound document viewer like CFX to open up the correct stream. Of course, if you are just replacing bytes, the plain old binary editor may work.
顺便说一句,如果你想知道这些字段的确切格式,他们现在有文档:
http://msdn.microsoft.com/en-us/library/dd926151%28v=office.12%29.aspx
其他回答
如果该文件是一个有效的zip文件(前几个字节是504b——用于.xlsm等格式),那么解压缩该文件并查找子文件xl/vbaProject.bin。这是一个CFB文件,就像.xls文件一样。按照XLS格式的说明(应用于子文件),然后压缩内容。
对于XLS格式,您可以使用本文中的其他一些方法。我个人更喜欢搜索DPB=块并替换文本
CMG="..."
DPB="..."
GC="..."
有空格。这样就避免了CFB容器大小的问题。
您可以尝试这种不需要HEX编辑的直接VBA方法。它将适用于任何文件(*.xls, *.xls, *.xls)。xlsm, *。xlam……)。
测试和工作:
Excel 2007 Excel 2010 Excel 2013 - 32位版本 Excel 2016 - 32位版本
寻找64位版本?请看这个答案
它是如何工作的
我会尽我最大的努力解释它是如何工作的-请原谅我的英语。
The VBE will call a system function to create the password dialog box. If user enters the right password and click OK, this function returns 1. If user enters the wrong password or click Cancel, this function returns 0. After the dialog box is closed, the VBE checks the returned value of the system function if this value is 1, the VBE will "think" that the password is right, hence the locked VBA project will be opened. The code below swaps the memory of the original function used to display the password dialog with a user defined function that will always return 1 when being called.
使用代码
请先备份您的文件!
Open the file(s) that contain your locked VBA Projects Create a new xlsm file and store this code in Module1 code credited to Siwtom (nick name), a Vietnamese developer Option Explicit Private Const PAGE_EXECUTE_READWRITE = &H40 Private Declare Sub MoveMemory Lib "kernel32" Alias "RtlMoveMemory" _ (Destination As Long, Source As Long, ByVal Length As Long) Private Declare Function VirtualProtect Lib "kernel32" (lpAddress As Long, _ ByVal dwSize As Long, ByVal flNewProtect As Long, lpflOldProtect As Long) As Long Private Declare Function GetModuleHandleA Lib "kernel32" (ByVal lpModuleName As String) As Long Private Declare Function GetProcAddress Lib "kernel32" (ByVal hModule As Long, _ ByVal lpProcName As String) As Long Private Declare Function DialogBoxParam Lib "user32" Alias "DialogBoxParamA" (ByVal hInstance As Long, _ ByVal pTemplateName As Long, ByVal hWndParent As Long, _ ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer Dim HookBytes(0 To 5) As Byte Dim OriginBytes(0 To 5) As Byte Dim pFunc As Long Dim Flag As Boolean Private Function GetPtr(ByVal Value As Long) As Long GetPtr = Value End Function Public Sub RecoverBytes() If Flag Then MoveMemory ByVal pFunc, ByVal VarPtr(OriginBytes(0)), 6 End Sub Public Function Hook() As Boolean Dim TmpBytes(0 To 5) As Byte Dim p As Long Dim OriginProtect As Long Hook = False pFunc = GetProcAddress(GetModuleHandleA("user32.dll"), "DialogBoxParamA") If VirtualProtect(ByVal pFunc, 6, PAGE_EXECUTE_READWRITE, OriginProtect) <> 0 Then MoveMemory ByVal VarPtr(TmpBytes(0)), ByVal pFunc, 6 If TmpBytes(0) <> &H68 Then MoveMemory ByVal VarPtr(OriginBytes(0)), ByVal pFunc, 6 p = GetPtr(AddressOf MyDialogBoxParam) HookBytes(0) = &H68 MoveMemory ByVal VarPtr(HookBytes(1)), ByVal VarPtr(p), 4 HookBytes(5) = &HC3 MoveMemory ByVal pFunc, ByVal VarPtr(HookBytes(0)), 6 Flag = True Hook = True End If End If End Function Private Function MyDialogBoxParam(ByVal hInstance As Long, _ ByVal pTemplateName As Long, ByVal hWndParent As Long, _ ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer If pTemplateName = 4070 Then MyDialogBoxParam = 1 Else RecoverBytes MyDialogBoxParam = DialogBoxParam(hInstance, pTemplateName, _ hWndParent, lpDialogFunc, dwInitParam) Hook End If End Function Paste this code under the above code in Module1 and run it Sub unprotected() If Hook Then MsgBox "VBA Project is unprotected!", vbInformation, "*****" End If End Sub Come back to your VBA Projects and enjoy.
删除VBA项目密码的一个简单方法是执行以下操作:
将xlsm文件转换为zip 打开VBAProject.bin文件(我更喜欢使用notepad++ (https://notepad-plus-plus.org/downloads/)) 搜索DPB字段 用DPx替换它 保存文件 将zip文件转换为XLSM 打开excel文件 如果出现消息框,请单击“是” 为VBA项目属性设置新密码 关闭并再次打开该文件 输入新密码取消保护
对于Windows 10机器上的Excel 2016 64位,我使用了十六进制编辑器来更改受保护的xla的密码(尚未对任何其他扩展进行测试)。 提示:在执行此操作之前创建备份。
我采取的步骤:
在十六进制编辑器中打开vba(例如XVI) 搜索这个DPB 将DPB更改为其他内容,如DPX 保存它! 重新打开.xla,将出现一条错误消息,继续。 您现在可以通过打开属性并转到password选项卡来更改.xla的密码。
我希望这对你们中的一些人有所帮助!
Tom -我最初犯了一个学生错误,因为我没有注意字节大小,而是从“CMG”设置复制粘贴到后续条目。这两个文件之间有两种不同的文本大小,但是,正如Stewbob警告的那样,我丢失了VBA项目。
使用HxD,有一个计数器跟踪您选择了多少文件。从CMG开始复制,直到计数器读取8F(十六进制为143),同样地,当粘贴到锁定文件时-我最终在粘贴的末尾使用了两倍的“…”,这看起来有点奇怪,感觉几乎不自然,但它起作用了。
我不知道这是否重要,但在excel中重新打开文件之前,我确保关闭了十六进制编辑器和excel。然后我必须通过菜单打开VB编辑器,进入VBProject属性,并输入'new'密码来解锁代码。
我希望这能有所帮助。