这是我的HTML表单:
<form name="myForm" ng-submit="">
<input ng-model='file' type="file"/>
<input type="submit" value='Submit'/>
</form>
我想从本地机器上传一个图像，并想读取上传文件的内容。所有这些我都想用AngularJS来做。
当我试图打印$scope的值时。文件是未定义的。
当前回答
HTML
<html>
<head></head>
<body ng-app = "myApp">
<form ng-controller = "myCtrl">
<input type = "file" file-model="files" multiple/>
<button ng-click = "uploadFile()">upload me</button>
<li ng-repeat="file in files">{{file.name}}</li>
</form>
脚本
<script src =
"http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
<script>
angular.module('myApp', []).directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
element.bind('change', function(){
$parse(attrs.fileModel).assign(scope,element[0].files)
scope.$apply();
});
}
};
}]).controller('myCtrl', ['$scope', '$http', function($scope, $http){
$scope.uploadFile=function(){
var fd=new FormData();
console.log($scope.files);
angular.forEach($scope.files,function(file){
fd.append('file',file);
});
$http.post('http://localhost:1337/mediaobject/upload',fd,
{
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).success(function(d)
{
console.log(d);
})
}
}]);
</script>
其他回答
这是
file.html
<html>
<head>
<script src = "https://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
</head>
<body ng-app = "app">
<div ng-controller = "myCtrl">
<input type = "file" file-model = "myFile"/>
<button ng-click = "uploadFile()">upload me</button>
</div>
</body>
<script src="controller.js"></script>
</html>
controller.js
var app = angular.module('app', []);
app.service('fileUpload', ['$http', function ($http) {
this.uploadFileToUrl = function(file, uploadUrl){
var fd = new FormData();
fd.append('file', file);
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).success(function(res){
console.log(res);
}).error(function(error){
console.log(error);
});
}
}]);
app.controller('fileCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){
$scope.uploadFile = function(){
var file = $scope.myFile;
console.log('file is ' );
console.dir(file);
var uploadUrl = "/fileUpload.php"; // upload url stands for api endpoint to handle upload to directory
fileUpload.uploadFileToUrl(file, uploadUrl);
};
}]);
</script>
fileupload.php
<?php
$ext = pathinfo($_FILES['file']['name'],PATHINFO_EXTENSION);
$image = time().'.'.$ext;
move_uploaded_file($_FILES["file"]["tmp_name"],__DIR__. ' \\'.$image);
?>
简单的指令
Html:
<input type="file" file-upload multiple/>
JS:
app.directive('fileUpload', function () {
return {
scope: true, //create a new scope
link: function (scope, el, attrs) {
el.bind('change', function (event) {
var files = event.target.files;
//iterate files since 'multiple' may be specified on the element
for (var i = 0;i<files.length;i++) {
//emit event upward
scope.$emit("fileSelected", { file: files[i] });
}
});
}
};
在指令中，我们确保创建了一个新的作用域，然后监听对文件输入元素所做的更改。当检测到更改时，以文件对象作为参数向所有祖先作用域(向上)发出事件。
在你的控制器中:
$scope.files = [];
//listen for the file selected event
$scope.$on("fileSelected", function (event, args) {
$scope.$apply(function () {
//add the file object to the scope's files collection
$scope.files.push(args.file);
});
});
然后在ajax调用中:
data: { model: $scope.model, files: $scope.files }
http://shazwazza.com/post/uploading-files-and-json-data-in-the-same-request-with-angular-js/
下面是文件上传的工作示例:
http://jsfiddle.net/vishalvasani/4hqVu/
在这个函数中
setFiles
从视图更新控制器中的文件数组
or
你可以使用AngularJS检查jQuery文件上传
http://blueimp.github.io/jQuery-File-Upload/angularjs.html
该代码将帮助插入文件
<body ng-app = "myApp">
<form ng-controller="insert_Ctrl" method="post" action="" name="myForm" enctype="multipart/form-data" novalidate>
<div>
<p><input type="file" ng-model="myFile" class="form-control" onchange="angular.element(this).scope().uploadedFile(this)">
<span style="color:red" ng-show="(myForm.myFile.$error.required&&myForm.myFile.$touched)">Select Picture</span>
</p>
</div>
<div>
<input type="button" name="submit" ng-click="uploadFile()" class="btn-primary" ng-disabled="myForm.myFile.$invalid" value="insert">
</div>
</form>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>
<script src="insert.js"></script>
</body>
insert.js
var app = angular.module('myApp',[]);
app.service('uploadFile', ['$http','$window', function ($http,$window) {
this.uploadFiletoServer = function(file,uploadUrl){
var fd = new FormData();
fd.append('file', file);
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(data){
alert("insert successfull");
$window.location.href = ' ';//your window location
})
.error(function(){
alert("Error");
});
}
}]);
app.controller('insert_Ctrl', ['$scope', 'uploadFile', function($scope, uploadFile){
$scope.uploadFile = function() {
$scope.myFile = $scope.files[0];
var file = $scope.myFile;
var url = "save_data.php";
uploadFile.uploadFiletoServer(file,url);
};
$scope.uploadedFile = function(element) {
var reader = new FileReader();
reader.onload = function(event) {
$scope.$apply(function($scope) {
$scope.files = element.files;
$scope.src = event.target.result
});
}
reader.readAsDataURL(element.files[0]);
}
}]);
save_data.php
<?php
require "dbconnection.php";
$ext = pathinfo($_FILES['file']['name'],PATHINFO_EXTENSION);
$image = time().'.'.$ext;
move_uploaded_file($_FILES["file"]["tmp_name"],"upload/".$image);
$query="insert into test_table values ('null','$image')";
mysqli_query($con,$query);
?>
<input type=file>元素默认不使用ng-model指令。它需要一个自定义指令:
使用ng-model1的select-ng-files指令的工作演示
angular.module("app",[]); angular.module("app").directive("selectNgFiles", function() { return { require: "ngModel", link: function postLink(scope,elem,attrs,ngModel) { elem.on("change", function(e) { var files = elem[0].files; ngModel.$setViewValue(files); }) } } }); <script src="//unpkg.com/angular/angular.js"></script> <body ng-app="app"> <h1>AngularJS Input `type=file` Demo</h1> <input type="file" select-ng-files ng-model="fileList" multiple> <h2>Files</h2> <div ng-repeat="file in fileList"> {{file.name}} </div> </body>
美元http。从FileList中post
$scope.upload = function(url, fileList) {
var config = { headers: { 'Content-Type': undefined },
transformResponse: angular.identity
};
var promises = fileList.map(function(file) {
return $http.post(url, file, config);
});
return $q.all(promises);
};
当发送带有File对象的POST时，重要的是设置'Content-Type': undefined。然后XHR发送方法将检测File对象并自动设置内容类型。
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