我有以下html5输入元素:
<input type="number">
为什么这个输入允许在输入字段中输入字符“e”?无法输入其他字母字符(如预期的那样)
使用chrome v. 44.0.2403.107
下面的例子来看看我的意思。
= >“当家”型输入<
当前回答
上述解决方案只适用于普通html。 对于reactJS，我建议你这样做
<input type="number" onKeyDown={(e) =>["e", "E", "+", "-"].includes(e.key) && e.preventDefault()} >
其他回答
因为这正是规范所规定的。数字输入可以接受浮点数，包括负号和e或e字符(其中指数是e或e后面的数字):
A floating-point number consists of the following parts, in exactly the following order: Optionally, the first character may be a "-" character. One or more characters in the range "0—9". Optionally, the following parts, in exactly the following order: a "." character one or more characters in the range "0—9" Optionally, the following parts, in exactly the following order: a "e" character or "E" character optionally, a "-" character or "+" character One or more characters in the range "0—9".
<input type="number" onkeydown="return FilterInput(event)" onpaste="handlePaste(event)" >
function FilterInput(event) {
var keyCode = ('which' in event) ? event.which : event.keyCode;
isNotWanted = (keyCode == 69 || keyCode == 101);
return !isNotWanted;
};
function handlePaste (e) {
var clipboardData, pastedData;
// Get pasted data via clipboard API
clipboardData = e.clipboardData || window.clipboardData;
pastedData = clipboardData.getData('Text').toUpperCase();
if(pastedData.indexOf('E')>-1) {
//alert('found an E');
e.stopPropagation();
e.preventDefault();
}
};
一个简单的解决方案，排除除整数
<输入 类型=“数字” min=“1” 步骤=“1” onkeypress=“return event.keyCode === 8 ||事件.字符代码 >= 48 &&; 事件.字符代码 <= 57“>
此解决方案不防止复制和粘贴(包括字母“e”)。
<input type="number" onkeydown="javascript: return ['Backspace'，'Delete'，'ArrowLeft'，'ArrowRight'].includes(event.code) ?isNaN(Number(event.key)) && event.code!= =‘空间’" / >
我们可以像下面这样简单
<input type="number" onkeydown="javascript:返回事件。keyCode == 69 ?/> . False: true
更新后的答案
我们可以让它更简单，就像@88 MPG建议的那样
<输入类型=“编号”=“回归事件”。键盘代码!
