因为这正是规范所规定的。数字输入可以接受浮点数，包括负号和e或e字符(其中指数是e或e后面的数字):

A floating-point number consists of the following parts, in exactly the following order: Optionally, the first character may be a "-" character. One or more characters in the range "0—9". Optionally, the following parts, in exactly the following order: a "." character one or more characters in the range "0—9" Optionally, the following parts, in exactly the following order: a "e" character or "E" character optionally, a "-" character or "+" character One or more characters in the range "0—9".

HTML输入数字类型允许“e/ e”，因为“e”代表指数，这是一个数字符号。

例200000也可以写成2e5。我希望这能帮到你，谢谢你的问题。

角;与IDE keyCode弃用警告

功能上与rinku的答案相同，但有IDE警告预防

numericOnly(event): boolean {
    // noinspection JSDeprecatedSymbols
    const charCode = (event.which) ? event.which : event.key || event.keyCode;  // keyCode is deprecated but needed for some browsers
    return !(charCode === 101 || charCode === 69 || charCode === 45 || charCode === 43);
}

上述解决方案只适用于普通html。 对于reactJS，我建议你这样做

  <input type="number" onKeyDown={(e) =>["e", "E", "+", "-"].includes(e.key) && e.preventDefault()} >

因为这正是规范所规定的。数字输入可以接受浮点数，包括负号和e或e字符(其中指数是e或e后面的数字):

A floating-point number consists of the following parts, in exactly the following order: Optionally, the first character may be a "-" character. One or more characters in the range "0—9". Optionally, the following parts, in exactly the following order: a "." character one or more characters in the range "0—9" Optionally, the following parts, in exactly the following order: a "e" character or "E" character optionally, a "-" character or "+" character One or more characters in the range "0—9".

一个简单的解决方案，排除除整数

<输入 类型=“数字” min=“1” 步骤=“1” onkeypress=“return event.keyCode === 8 ||事件.字符代码 >= 48 &&; 事件.字符代码 <= 57“>

此解决方案不防止复制和粘贴(包括字母“e”)。