explode('?', $_SERVER['REQUEST_URI'])[0]

使用PHP Manual - parse_url()来获取您需要的部分。

编辑(例如@Navi Gamage的用法)

你可以这样使用它:

<?php
function reconstruct_url($url){
    $url_parts = parse_url($url);
    $constructed_url = $url_parts['scheme'] . '://' . $url_parts['host'] . $url_parts['path'];

    return $constructed_url;
}

?>

编辑(第二个完整示例):

更新功能，确保方案将附加，没有通知msgs出现:

function reconstruct_url($url){
    $url_parts = parse_url($url);
    $constructed_url = $url_parts['scheme'] . '://' . $url_parts['host'] . (isset($url_parts['path'])?$url_parts['path']:'');

    return $constructed_url;
}

$test = array(
    'http://www.example.com/myurl.html?unwan=abc',
    `http://www.example.com/myurl.html`,
    `http://www.example.com`,
    `https://example.com/myurl.html?unwan=abc&ab=1`
);

foreach($test as $url){
    print_r(parse_url($url));
}

将返回:

Array
(
    [scheme] => http
    [host] => www.example.com
    [path] => /myurl.html
    [query] => unwan=abc
)
Array
(
    [scheme] => http
    [host] => www.example.com
    [path] => /myurl.html
)
Array
(
    [scheme] => http
    [host] => www.example.com
)
Array
(
    [path] => example.com/myurl.html
    [query] => unwan=abc&ab=1
)

这是通过不带第二个参数的parse_url()传递示例url的输出(仅供解释)。

这是使用构造URL后的最终输出:

foreach($test as $url){
    echo reconstruct_url($url) . '<br/>';
}

输出:

http://www.example.com/myurl.html
http://www.example.com/myurl.html
http://www.example.com
https://example.com/myurl.html

你可以使用strtok在第一次出现之前获取字符串?

$url = strtok($_SERVER["REQUEST_URI"], '?');

Strtok()代表了直接提取?在查询字符串中。explosion()不太直接，因为它必须生成一个可能包含两个元素的数组，必须通过该数组访问第一个元素。

其他一些技术可能会在查询字符串丢失或url中其他/非预期的子字符串发生变化时中断——这些技术应该避免。

一个示范:

$urls = [
    'www.example.com/myurl.html?unwantedthngs#hastag',
    'www.example.com/myurl.html'
];

foreach ($urls as $url) {
    var_export(['strtok: ', strtok($url, '?')]);
    echo "\n";
    var_export(['strstr/true: ', strstr($url, '?', true)]); // not reliable
    echo "\n";
    var_export(['explode/2: ', explode('?', $url, 2)[0]]);  // limit allows func to stop searching after first encounter
    echo "\n";
    var_export(['substr/strrpos: ', substr($url, 0, strrpos( $url, "?"))]);  // not reliable; still not with strpos()
    echo "\n---\n";
}

输出:

array (
  0 => 'strtok: ',
  1 => 'www.example.com/myurl.html',
)
array (
  0 => 'strstr/true: ',
  1 => 'www.example.com/myurl.html',
)
array (
  0 => 'explode/2: ',
  1 => 'www.example.com/myurl.html',
)
array (
  0 => 'substr/strrpos: ',
  1 => 'www.example.com/myurl.html',
)
---
array (
  0 => 'strtok: ',
  1 => 'www.example.com/myurl.html',
)
array (
  0 => 'strstr/true: ',
  1 => false,                       // bad news
)
array (
  0 => 'explode/2: ',
  1 => 'www.example.com/myurl.html',
)
array (
  0 => 'substr/strrpos: ',
  1 => '',                          // bad news
)
---

如果你想获取请求路径(更多信息):

echo parse_url($_SERVER["REQUEST_URI"])['path']

如果你想删除查询和(也可能是片段):

function strposa($haystack, $needles=array(), $offset=0) {
        $chr = array();
        foreach($needles as $needle) {
                $res = strpos($haystack, $needle, $offset);
                if ($res !== false) $chr[$needle] = $res;
        }
        if(empty($chr)) return false;
        return min($chr);
}
$i = strposa($_SERVER["REQUEST_URI"], ['#', '?']);
echo strrpos($_SERVER["REQUEST_URI"], 0, $i);

explode('?', $_SERVER['REQUEST_URI'])[0]

假设你仍然想要在没有查询参数的情况下获得URL(如果它们没有设置)，只需使用一个简略的if语句来检查strpos:

$request_uri = strpos( $_SERVER['REQUEST_URI'], '?' ) !== false ? strtok( $_SERVER["REQUEST_URI"], '?' ) : $_SERVER['REQUEST_URI'];