使用SQL Server，我有…
ID SKU PRODUCT
=======================
1 FOO-23 Orange
2 BAR-23 Orange
3 FOO-24 Apple
4 FOO-25 Orange
我想要的
1 FOO-23 Orange
3 FOO-24 Apple
这个问题并没有让我明白。我如何在一列上选择DISTINCT ?
SELECT
[ID],[SKU],[PRODUCT]
FROM [TestData]
WHERE ([PRODUCT] =
(SELECT DISTINCT [PRODUCT] FROM [TestData] WHERE ([SKU] LIKE 'FOO-%'))
ORDER BY [ID]
当前回答
假设您使用的是SQL Server 2005或更高版本，您可以使用带有ROW_NUMBER()的CTE:
SELECT *
FROM (SELECT ID, SKU, Product,
ROW_NUMBER() OVER (PARTITION BY PRODUCT ORDER BY ID) AS RowNumber
FROM MyTable
WHERE SKU LIKE 'FOO%') AS a
WHERE a.RowNumber = 1
其他回答
试试这个:
SELECT * FROM [TestData] WHERE Id IN(FROM [TestData] GROUP BY Product)
最简单的解决方案是使用子查询来查找与查询匹配的最小ID。在子查询中使用GROUP BY而不是DISTINCT:
SELECT * FROM [TestData] WHERE [ID] IN (
SELECT MIN([ID]) FROM [TestData]
WHERE [SKU] LIKE 'FOO-%'
GROUP BY [PRODUCT]
)
SELECT min (id) AS 'ID', min(sku) AS 'SKU', Product
FROM TestData
WHERE sku LIKE 'FOO%' -- If you want only the sku that matchs with FOO%
GROUP BY product
ORDER BY 'ID'
下面是一个版本，基本上与其他几个答案相同，但是由于一些内联值，您可以将其复制粘贴到SQL server Management Studio中进行测试(并且不会生成任何不需要的表)。
WITH [TestData]([ID],[SKU],[PRODUCT]) AS
(
SELECT *
FROM (
VALUES
(1, 'FOO-23', 'Orange'),
(2, 'BAR-23', 'Orange'),
(3, 'FOO-24', 'Apple'),
(4, 'FOO-25', 'Orange')
)
AS [TestData]([ID],[SKU],[PRODUCT])
)
SELECT * FROM [TestData] WHERE [ID] IN
(
SELECT MIN([ID])
FROM [TestData]
GROUP BY [PRODUCT]
)
结果
ID SKU PRODUCT
1 FOO-23 Orange
3 FOO-24 Apple
我忽略了以下几点…
WHERE ([SKU] LIKE 'FOO-%')
因为这只是作者错误代码的一部分，而不是问题的一部分。这对找这里的人没什么帮助。
假设您使用的是SQL Server 2005或更高版本，您可以使用带有ROW_NUMBER()的CTE:
SELECT *
FROM (SELECT ID, SKU, Product,
ROW_NUMBER() OVER (PARTITION BY PRODUCT ORDER BY ID) AS RowNumber
FROM MyTable
WHERE SKU LIKE 'FOO%') AS a
WHERE a.RowNumber = 1
